Topic: type-id
Author: parthaspanda22@gmail.com
Date: Wed, 14 Nov 2007 13:03:30 CST Raw View
Although the grammar allows a type to be defined in a type-id,
most C++ compilers reject it. Therefore, the following
doesnt pass:
struct T;
struct T *tptr = new (
struct T {
int i;
}
);
Can anyone to point to the clause the forbids types from being
defined in a type-id?
Sincerely.
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Author: Alberto Ganesh Barbati <AlbertoBarbati@libero.it>
Date: Wed, 14 Nov 2007 18:50:01 CST Raw View
parthaspanda22@gmail.com ha scritto:
> Although the grammar allows a type to be defined in a type-id,
> most C++ compilers reject it. Therefore, the following
> doesnt pass:
>
> struct T;
>
> struct T *tptr = new (
> struct T {
> int i;
> }
> );
>
> Can anyone to point to the clause the forbids types from being
> defined in a type-id?
>
5.2.8/4: "Types shall not be defined in the type-id."
Ganesh
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Author: parthaspanda22@gmail.com
Date: Thu, 15 Nov 2007 08:31:08 CST Raw View
>
> 5.2.8/4: "Types shall not be defined in the type-id."
But thats specific to the type-id used in Type Identification, isnt
it?
Thats why it is worded as "... the type-id".
type-id is also used with the cast operators, sizeof, new,
exception-specification.
In the section related to exception-specification, I find:
"Types shall not be defined in exception-specifications.".
The std is silent on types defined in type-ids.
Sincerely.
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Author: Jerry Coffin <jcoffin@taeus.com>
Date: Sun, 18 Nov 2007 15:39:42 CST Raw View
In article <1195052800.425781.136540@i38g2000prf.googlegroups.com>,
parthaspanda22@gmail.com says...
> Although the grammar allows a type to be defined in a type-id,
> most C++ compilers reject it. Therefore, the following
> doesnt pass:
>
> struct T;
>
> struct T *tptr = new (
> struct T {
> int i;
> }
> );
>
> Can anyone to point to the clause the forbids types from being
> defined in a type-id?
5.3.4/4: "The type-specifier-seq shall not contain class declarations,
or enumeration declarations."
--
Later,
Jerry.
The universe is a figment of its own imagination.
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