C++ standard says (12.1.3):

A typedef-name that names a class is a class-name; however, a typedef-
name that names a class shall not be used as the identifier in the
declarator for a constructor declaration.

Does anyone know a rationale for that?
I really would like a typedef of a class name the same way I can use
"inherited" as a typedef of the base class:

class LongNameOfDerivedClass : public LongNameOfBaseClass
{
    typedef LongNameOfBaseClass inherited;
    typedef LongNameOfDerivedClass self;

public:
    self() : inherited() { /*...*/ }
    self( self const& copy ) : inherited(copy) { /*...*/ }
    self & operator=( self const& copy ) { /*...*/ }
    ~self(){/*...*/}
};

---
[ comp.std.c++ is moderated.  To submit articles, try just posting with ]
[ your news-reader.  If that fails, use mailto:std-c++@ncar.ucar.edu    ]
[              --- Please see the FAQ before posting. ---               ]
[ FAQ: http://www.comeaucomputing.com/csc/faq.html                      ]