Topic: Const and array argument for a template
Author: joe_hesse@actcx.com ("Joseph Hesse")
Date: Tue, 17 Sep 2002 23:09:11 +0000 (UTC) Raw View
Hi,
Is there some simple explanation for the fact that
int a[2] = {1, 2};
const int (&b)[2] = a;
works just fine and that
template <typename T, int s>
void f(const T (&array)[size]) {}
will not work for
void foo()
{
int a[2] = {1, 2};
f(a); // no matching template function
}
except for the fact that the standard does not allow it?
Thank you,
Joe Hesse
---
[ comp.std.c++ is moderated. To submit articles, try just posting with ]
[ your news-reader. If that fails, use mailto:std-c++@ncar.ucar.edu ]
[ --- Please see the FAQ before posting. --- ]
[ FAQ: http://www.jamesd.demon.co.uk/csc/faq.html ]