Hi all,

I stumbled upon a problem when using a non-templated nested class within a
templated class.
The GCC compiler reports an error (see code and diagnostics below), but I
don't see what wrong with this code.
It seems as if the compiler doesn't consider the operator() method to be a
member function.
Is this a compiler problem, or is this code wrong?

Marcel.

----------------------------------------------------

#include <vector>

template <class T>
class Templated
{
private:
  typedef std::vector<T> buf_t;
  class NonTemplated
  {
  public:
    operator typename buf_t::size_type() const;
  private:
    typename buf_t::size_type myIndex;
  };
};

template <class T>
Templated<T>::NonTemplated::operator typename
Templated<T>::buf_t::size_type() const
{
  return myIndex;
}


int main()
{
  Templated<int> tmpl;
  return 0;
}


tTemplate.cc:19: no `Templated<T>::NonTemplated::operator std::vector<T,
   std::allocator<_CharT> >::size_type() const' member function declared in
   class `Templated<T>::NonTemplated'
tTemplate.cc:19: template definition of non-template `
   Templated<T>::NonTemplated::operator std::vector<T,
std::allocator<_CharT>
   >::size_type() const'




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""Marcel Loose"" <loose@astron.nl> wrote in message
news:alpmlt$1sf6tt$1@ID-64911.news.dfncis.de...
> Hi all,
>
> I stumbled upon a problem when using a non-templated nested class within a
> templated class.
[snip]
> Is this a compiler problem, or is this code wrong?

I believe this code is correct, and you've got a compiler bug.
However this problem can be worked around by making the operator
inline -which also works around
a similar restriction in Microsoft VC6 and VC7.

Roger Orr
--
MVP in C++ at www.brainbench.com


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