Albrecht Fritzsche <albrecht.fritzsche@alfabet.de> wrote in message news:<3C4FEFD6.4050507@alfabet.de>...
> Ok, now I think that I've understood the wordings incorrectly.
>
>     template<class S, class T> mem_fun_t<S, T>
>      mem_fun(S (T::*f)());
>
>     template<class S, class T> const_mem_fun_t<S, T>
>      mem_fun(S (T::*f)() const);
>
> are the two signatures, the identical wording confused me some-
> how. But another question remains - if there are
>
>     mem_fun_t/const_mem_fun_t
>     mem_fun1_t/const_mem_fun1_t
>
> "pairs", why not a
>
>     mem_fun/const_mem_fun
>
> ? Doesn't that seem to contradict some symmetry somehow?
>
> Ali

Yes; there is less symmetry than perhaps possible. Overloading
allows two functions to exist with the same name, while types
require unique names. This fundamental asymmetry causes the
effect you observed. Generic programming almost requires
the overloading, so it's a tradeof between lots of
functionality and a little bit of symmetry.

Regards,
--
Michiel Salters

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Ok, now I think that I've understood the wordings incorrectly.

    template<class S, class T> mem_fun_t<S, T>
     mem_fun(S (T::*f)());

    template<class S, class T> const_mem_fun_t<S, T>
     mem_fun(S (T::*f)() const);

are the two signatures, the identical wording confused me some-
how. But another question remains - if there are

    mem_fun_t/const_mem_fun_t
    mem_fun1_t/const_mem_fun1_t

"pairs", why not a

    mem_fun/const_mem_fun

? Doesn't that seem to contradict some symmetry somehow?

Ali
--
Albrecht Fritzsche, Software Developer
alfabet meta-modeling AG,
leibnizstr. 53, 10629 berlin, germany
http://www.alfabet.de

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