Hi,

In Borland C++ help I have read this:

<quote>
template <class T> void func(const T)

{
   .
   .
   .
};
func(0);  // This is illegal under ANSI C++: unresolved func(int).

// However, Borland C++  allows func(const int) to be called.

</quote>

Objects created from literals are rvalues and rvalues of built-in types are
never cv-qualified (I've read this here or on c.l.c++.m). That's why
compiler can't find any good version of 'func' function. Am I right ? If so
then should rvalues of built-in types be sometimes (always ?) cv-qualified
making this example legal ? What about user types ?

Piotr Dobrogost


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