"Martin Aupperle" <MikeAlpha@NoSpam_csi.com> wrote in message
news:3b02a2fa.76957619@news.nikoma.de...
> Hello,
>
> we recently came across the question whether f is inline or not, given
> the following construct;
>
> class X
> {
>   friend void f() { cout << "in f"; }
> };
>
> I know that this would be the case if f were a member function. But it
> is a global function.
>
> Martin

If the definition is allowed "within" the class declaration, the function is
inline, as stated in    11.4, bullet 5 of the standard:

"A function can be defined in a friend declaration of a class if and only if
the class is a non-local class (9.8), the function name is unqualified, and
the function has namespace scope. [snip...] Such a function is implicitly
inline."



Gennaro.


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Hello,

we recently came across the question whether f is inline or not, given
the following construct;

class X
{
  friend void f() { cout << "in f"; }
};

I know that this would be the case if f were a member function. But it
is a global function.

Martin

------------------------------------------------
Martin Aupperle
MikeAlpha@NoSpam_csi.com
(remove NoSpam_)
------------------------------------------------

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