Siemel Naran wrote:

> Fine.  Now please explain to me why the rules for builtin types are
> different from the rules for user types.  After, I like to think
> that there exist classes like this
>    class int { ... };
>    class double { ... };

But there are no such classes. Otherwise, expressions such as
int() + double() would be ambiguous, because we have as
candidates:
- operator+ (int, int)
- operator+ (double, double)
- ...
and as conversion sequences:
- int -> double
- double -> int
- ...
and why on earth should class double be prefered over class int ?

--

Valentin Bonnard


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