sanjayp@ddi.com wrote:
> Hi, Consider this:
>
> class A  {
>     static void* foo;
> public:
 class B; // <<< add fwd-decl class A::B
>     friend class B;
>     class B {
>     public:
>         void foobar() {
>      foo;
     A::foo; // <<< instead
>         }
>     };
> };

void * A::foo ; // storage <<< = NULL;

 --ALfred


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Hi,

Consider this:

class A  {
private:
    static void* foo;
public:
    friend class B;
    class B {
    public:
        void foobar() {
     foo;
        }
    };
};

Can someone tell me if A::B is a friend of A in the above case? I looked up
the standard but somehow it wasn't clear to me. As far as I understand the
friend declaration introduces class B in A's enclosing scope (non-class). So
A::B is not a friend of A? But gcc seems to accept the above code. Pls send
me a reply if you can.

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