(I posted this several weeks ago in comp.lang.c++.moderated, but got 0 replies.
)

Hello,

I understand this is a quote from the new standard draft,

[Example:
  template<class T> class task;
  template<class T> task<T>* preempt(task<T>*);
  template<class T> class task {
          // ...
          friend void next_time();
          friend void process(task<T>*);
          friend task<T>* preempt<T>(task<T>*);
          template<class C> friend int func(C);

          friend class task<int>;
          template<class P> friend class frd;
          // ...
  };

It seems to me that in 'friend void process(task<T>*);' a `<>' is missing,
and it should be 'friend void process<>(task<T>*);'.

Is that really the case, or the declaration above legal?

-pepe
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Joseph Heled <pepe@iconz.co.nz> writes:

> I understand this is a quote from the new standard draft,

>   template<class T> class task {
[snip]
>           friend void process(task<T>*);

> It seems to me that in 'friend void process(task<T>*);' a `<>' is missing,
> and it should be 'friend void process<>(task<T>*);'.

This would be the case if process were a template function, but it is
not.  It is just an overloaded non-template function, that must be
defined separately for each single type, i.e.:

void process(task<int>*) { /* ... */ }
void process(task<void>*) { /* ... */ }
// etc

--
Alexandre Oliva
mailto:oliva@dcc.unicamp.br mailto:aoliva@acm.org
http://www.dcc.unicamp.br/~oliva
Universidade Estadual de Campinas, SP, Brasil


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