Is p->B::m() legal in the following ?

        class B {
          public:
                static void m();
        };

        class D : private B { };

 D*p;

        void h()
        {
                // B::m();      // m is accessible
                // p->m();      // m is not accessible

                p->B::m();      // is it accessible ?
        }

According to CD2 11.2 "Accessibility of base classes and base class members"
paragraph 4, it seem to me that p->B::m() is legal,
even though p->m() is not legal:

 1. "naming class" is B
 2. m as a member of B is public
 3. as a result, m is accessible

g++-2.8.2 says:

 fields of `B' are inaccessible in `D' due to private inheritance

This message looks reasonable,
but I could not find why p->B::m() is not legal in CD2.
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