Given the following declaration:

    struct functor {
        template<typename T> T operator() () const;
    };

What is the correct syntax for calling functor::operator() ?
As I understand it, one way would be, e.g.,

    int i;
    functor f;

    i = f.template operator()<int>();

but that is so ugly that it would be better to live without an operator()
at all.

    Regards,
        Brane

--
Branko Cibej   <branko.cibej@hermes.si>
HERMES SoftLab, Litijska 51, 1000 Ljubljana, Slovenia
phone: (++386 61) 186 53 49  fax: (++386 61) 186 52 70
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