Anand J. Bhalerao <anand@abnar-telsoft.com> wrote:
>
> 2> Pointer arithmetics on references don't work ;
> char  c[10] ;
> char &p = c[0] ;
> p++ ; // illegal

Not illegal, surely.  p++ in this context evaluates to the current value of
c[0], and also has a side effect of incrementing c[0].

Of course this is not pointer arithmetic.  If p were a pointer, the line
would also be legal, but would do something entirely different.


--
Ian Griffiths
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Ian Griffiths wrote in article <01bcb3df$a4d9d730$40c310ac@dmv-03477>...

>Anand J. Bhalerao <anand@abnar-telsoft.com> wrote:
>>
>> 2> Pointer arithmetics on references don't work ;
>> char  c[10] ;
>> char &p = c[0] ;
>> p++ ; // illegal
>
>Not illegal, surely.  p++ in this context evaluates to the current value of
>c[0], and also has a side effect of incrementing c[0].
>
>Of course this is not pointer arithmetic.  If p were a pointer, the line
>would also be legal, but would do something entirely different.
>

thanx for pointing out the wrong example. The expected result of the
operation should be included in the above statements.

BR, anand
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