Marcelo Cantos <marcelo@janus.mds.rmit.edu.au> writes:

|>  The standard gives no indication as to order of evaluation of
|>  arguments with respect to the object (or I haven't looked hard enough!
|>  ;-).  For instance:
|>
|>    #include <iostream.h>
|>
|>    class Foo {
|>    public:
|>        void f(int) { }
|>    };
|>
|>    Foo g() { cout << "g() "; return Foo(); }
|>    int h() { cout << "h() "; return 0; }
|>
|>    main() { g().f(h()); cout << endl; }
|>
|>  Should the above code produce:
|>
|>    g() h()
|>
|>  or
|>
|>    h() g()
|>
|>  or is it implementation defined?

Not even implementation defined: unspecified.  Either order is
permitted, the implementation doesn't have to tell you which one it
uses, or even be consistent in its use.

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The standard gives no indication as to order of evaluation of
arguments with respect to the object (or I haven't looked hard enough!
;-).  For instance:

  #include <iostream.h>

  class Foo {
  public:
      void f(int) { }
  };

  Foo g() { cout << "g() "; return Foo(); }
  int h() { cout << "h() "; return 0; }

  main() { g().f(h()); cout << endl; }

Should the above code produce:

  g() h()

or

  h() g()

or is it implementation defined?  My guess is that the object is just
treated as another parameter (albeit hidden) from the perspective of
argument evaluation order, and hence its evaluation order is
implementation defined.

I would like to be more certain, however.

--
______________________________________________________________________
Marcelo Cantos, Research Assistant       __/_  marcelo@mds.rmit.edu.au
Multimedia Database Systems Group, RMIT   /       _ Tel 61-3-9282-2497
L2/723 Swanston St, Carlton VIC 3053, Aus/ralia ><_>Fax 61-3-9282-2490
Acknowledgements: errors - me; wisdom - God; sponsorship - RMIT
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