Has anyone had any problems throwing enumerated types?

I am using an enumerated type to determine different errors,
but execution continues after a throw statement containing
one.  And I know that execution is reaching the throw statement.

I have no idea what is going on.  I am adhering to the syntax
described in the C++ Standard Working Paper (available @
http://www.cygnus.com/misc/wp/draft).

Is it possible that enumerated types cannot be thrown?
Has anyone got any ideas?  I'm sure out.

Thank you in advance.


*
* Chris George
* St. John's, Newfoundland
* cgeorge@cs.mun.ca
* cgeorge@athena.nwafc.nf.ca
*
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cgeorge@hobbes.nwafc.nf.ca (Chris George) writes:

> Has anyone had any problems throwing enumerated types?

> Is it possible that enumerated types cannot be thrown?
> Has anyone got any ideas?  I'm sure out.

It is probably a  compiler bug.  Some  compilers, such as the  current
release of g++, do not support exception handling in all platforms.

--
Alexandre Oliva
oliva@dcc.unicamp.br
Universidade Estadual de Campinas, S=E3o Paulo, Brasil
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Well, I have found the problem.  G++'s optimization flag (-O)
somehow disables exception handling.

Also, the code from my last posting generates an Abort(core dump)
because of the string constant.  The code is similiar to an example
in the C++ Standard Working Paper.  Maybe g++ is not fully compliant
to that document.

Chris
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cgeorge@hobbes.nwafc.nf.ca (Chris George) writes:

> Well, I have found the problem.  G++'s optimization flag (-O)
> somehow disables exception handling.
>
> Also, the code from my last posting generates an Abort(core dump)
> because of the string constant.  The code is similiar to an example
> in the C++ Standard Working Paper.  Maybe g++ is not fully compliant
> to that document.

Exception handling in g++ 2.7.2 is still alpha  in most platforms, and
it does not work with optimization, as noted in the documentation.

--
Alexandre Oliva
oliva@dcc.unicamp.br
Universidade Estadual de Campinas, S=E3o Paulo, Brasil
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