To my knowledge, if I have

  template< class T> void f( T, T );

not even the slightest conversions are allowed when instantiating f.
It is an error to say

  int i=0;
  const int j=1;

  f( i, j );

Now, I heard that something has been changed in this area. Is the rule
still so strict? Or are "trivial conversions" (e.g. doing away the
cv-qualifiers) now allowed?

Thank you - Martin
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>>>>> Martin Aupperle <100754.2730@compuserve.com> writes:

> To my knowledge, if I have
>   template< class T> void f( T, T );

> not even the slightest conversions are allowed when instantiating f.
> It is an error to say

>   int i=0;
>   const int j=1;

>   f( i, j );

> Now, I heard that something has been changed in this area. Is the rule
> still so strict? Or are "trivial conversions" (e.g. doing away the
> cv-qualifiers) now allowed?

The notion of 'trivial conversions' is no longer part of the standard, but
yes, this example is now allowed.

5 A  template  type  argument T or a template non-type argument i can be
  deduced if P and A have one of the following forms:
          T
          cv-list T
          T*
          T&
          T[integer-constant]
          class-template-name<T>
          type(*)(T)
          T(*)()
          T(*)(T)
          type T::*
          T type::*
          T (type::*)()
          type (T::*)()
          type (type::*)(T)
          type[i]
          class-template-name<i>

Jason
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