In a recent thread in c.l.c++, James Kanze and Fabrice Clerc just
pointed out to me section 14.8.4 of the DWP which says the following:

=====

  14.8  Template arguments                                    [temp.arg]

4 Nor is a local type or a type with no linkage name an acceptable  tem-
  plate-argument.  [Example:
          void f()
          {
              struct S { /* ... */ };
              X<S,p> x3; // error: local type used as template-argument
          }
   --end example]

=====

Why is this necessary? Why isn't the template argument S in X<S,p>
simply treated as X<f()::S, p> (or something along these lines)?

regards,
mumit -- khan@xraylith.wisc.edu
http://www.xraylith.wisc.edu/~khan/
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>>>>> "MK" == Mumit Khan <khan@xraylith.wisc.edu> writes:
MK> In a recent thread in c.l.c++, James Kanze and Fabrice Clerc just
MK> pointed out to me section 14.8.4 of the DWP which says the following:
MK> =====
MK>   14.8  Template arguments                                    [temp.arg]

MK> 4 Nor is a local type or a type with no linkage name an acceptable  tem-
MK>   plate-argument.  [Example:
MK>           void f()
MK>           {
MK>               struct S { /* ... */ };
MK>               X<S,p> x3; // error: local type used as template-argument
MK>           }
MK>    --end example]
MK> =====
MK> Why is this necessary? Why isn't the template argument S in X<S,p>
MK> simply treated as X<f()::S, p> (or something along these lines)?

I think this is because the point of instantiation is immediately
_before_ the ``enclosing scope for the point of first use'' (see
[temp.point] 14.3.2/1 for exact wording; also /6 and the rest of
that section).

 Daveed
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