mykland@samson.tmlh.no (Bjorn Tore Mykland ) writes:

>Could someone help me??
>I want to convert a number (int), so that I can  use it in a
>StringArray.

>ex:

> int Number = 12;
> char CharText[LineLength];
> CharText = "this is a test ";

>   char NumText= <number to NumText>;    ???
>   strcat(CharText, numtext);
>   cout << CharText << endl;


>Should give -- >   this is a test 12        (as text)

>I know that i can use 'int' directly into 'cout',  but the point is that I
>must use it to generate a filenames like:   filename1, filename2,
>filename3.......

Open a stream to your character array (CharText).  Then just ``print''
the text and the number to the string as you would with any other
stream:

  #include <strstream.h>

  ostrstream oCharText(CharText, LineLength);

  oCharText << "test is a test " << Number;
  oCharText.close(); // Not needed, but a Good Idea(tm)

  cout << CharText << endl;

Dave ``Do it with streams'' Kilzer
--
David D. Kilzer              \        Emergency Holographic Doctor:
ddkilzer@iastate.edu         /   ``Don't worry, I'm not going to kiss you.
Computer Engineer 4          \      I'm only adjusting the restraint.''
Iowa State University, Ames  /         _Star_Trek_Voyager:__Phage_

In article <3qfb65$ft6@natasha.rmii.com> mike@if.com (MIke Homyack -
System Owner) writes:

|> On Mon, 29 May 1995 23:12:17, Bjorn Tore Mykland (mykland@samson.tmlh.no) wrote:
|>  [snip]
|>  - ex:

|>  -  int Number = 12;
|>  -  char CharText[LineLength];
|>  -  CharText = "this is a test ";

|>  -    char NumText= <number to NumText>;    ???
|>  -    strcat(CharText, numtext);
|>  -    cout << CharText << endl;


|>  - Should give -- >   this is a test 12        (as text)

|>  - I know that i can use 'int' directly into 'cout',  but the point is that I
|>  - must use it to generate a filenames like:   filename1, filename2,
|>  - filename3.......

|>  - Mykland  :)

|> Presuming NumText is a char array big enough to hold the converted number,
|> why not simply use sprintf?
|> ie.
|>  sprintf(NumText, "%d", Number);

|> This may not be the coolest, OOP way of doing this, but it works for me.  I
|> suppose that you could obfuscate things by wrapping the sprintf in another
|> function or even create a method for a numeric class that returns that number
|> as a string... but it's probably overkill in this case.

A better solution might be to simply use ostrstream.  If performance
is not a particular problem, you can even leave the entire memory
management to ostrstream, with the result that you don't have to know
how big the destination string should be:

 ostrstream numText ;
 numText << "filename" << number << ends ;
 char const* p = numText->str() ;

At this point, *you* own the buffer, and are responsible for either
freeing it (delete [] p) or returning ownership to ostrstream
(numText.rdbuf()->freeze( 0 )).  I generally prefer the latter, but it
*does* invalidate your pointer.
--
James Kanze         Tel.: (+33) 88 14 49 00        email: kanze@gabi-soft.fr
GABI Software, Sarl., 8 rue des Francs-Bourgeois, F-67000 Strasbourg, France
Conseils en informatique industrielle --
                              -- Beratung in industrieller Datenverarbeitung

In article <ddkilzer.801861797@tbp.eng.iastate.edu>
ddkilzer@iastate.edu (David D Kilzer) writes:

|>   ostrstream oCharText(CharText, LineLength);

|>   oCharText << "test is a test " << Number;
|>   oCharText.close(); // Not needed, but a Good Idea(tm)

Does your ostrstream even have a `close' function?  Mine doesn't (and
ostringstream in the draft standard doesn't either).  On the other
hand, if you do want to get at a C-like string, you should generally
output an `ends' somewhere.

|>   cout << CharText << endl;

I think this should be:

 cout << oCharText.rdbuf() << endl ;

But as the original poster said that he also wanted to use the string
in other contexts (as a filename, etc.), ostrstream.str() might of
interest.  (Outputting the buffer, as above, does not require the
`ends', but accessing the stream as a string with `ostrstream.str()'
does.)
--
James Kanze         Tel.: (+33) 88 14 49 00        email: kanze@gabi-soft.fr
GABI Software, Sarl., 8 rue des Francs-Bourgeois, F-67000 Strasbourg, France
Conseils en informatique industrielle --
                              -- Beratung in industrieller Datenverarbeitung

Hello!


Could someone help me??


I want to convert a number (int), so that I can  use it in a
StringArray.

ex:

 int Number = 12;
 char CharText[LineLength];
 CharText = "this is a test";

   char NumText= <number to NumText>;    ???
   strcat(CharText, numtext);
   cout << CharText << endl;

Mykland

Hello!

Could someone help me??
I want to convert a number (int), so that I can  use it in a
StringArray.

ex:

 int Number = 12;
 char CharText[LineLength];
 CharText = "this is a test ";

   char NumText= <number to NumText>;    ???
   strcat(CharText, numtext);
   cout << CharText << endl;


Should give -- >   this is a test 12        (as text)

I know that i can use 'int' directly into 'cout',  but the point is that I
must use it to generate a filenames like:   filename1, filename2,
filename3.......

Mykland  :)

Followup-To: comp.lang.c++

In article <mykland.173.00173514@samson.tmlh.no>,
   mykland@samson.tmlh.no (Bjorn Tore Mykland ) wrote:
:Hello!
:
:Could someone help me??
:I want to convert a number (int), so that I can  use it in a
:StringArray.
:
:ex:
:
: int Number = 12;
: char CharText[LineLength];
: CharText = "this is a test ";
:
:   char NumText= <number to NumText>;    ???
:   strcat(CharText, numtext);
:   cout << CharText << endl;
:
:
:Should give -- >   this is a test 12        (as text)
:
:I know that i can use 'int' directly into 'cout',  but the point
is that I
:must use it to generate a filenames like:   filename1, filename2,
:filename3.......

(Wrong newsgroup, followups redirected)

Use an ostrstream, ala:

#include <strstream.h>

 ...

    for (int n = 1; n <= 3; ++n)  {
 ostrstream filename;
 filename << "filename" << n << ends;
 // use filename.str() as required-it's a char*
 delete[] filename.str();
 }

    filename << "file

 --Paul J. Ste. Marie, pstemari@well.sf.ca.us, pstemari@erinet.com

The Financial Crimes Enforcement Network claims that they capture every
public posting that has their name ("FinCEN") in it.  I wish them good hunting.

On Mon, 29 May 1995 23:12:17, Bjorn Tore Mykland (mykland@samson.tmlh.no) wrote:
 [snip]
 - ex:

 -  int Number = 12;
 -  char CharText[LineLength];
 -  CharText = "this is a test ";

 -    char NumText= <number to NumText>;    ???
 -    strcat(CharText, numtext);
 -    cout << CharText << endl;


 - Should give -- >   this is a test 12        (as text)

 - I know that i can use 'int' directly into 'cout',  but the point is that I
 - must use it to generate a filenames like:   filename1, filename2,
 - filename3.......

 - Mykland  :)

Presuming NumText is a char array big enough to hold the converted number,
why not simply use sprintf?
ie.
 sprintf(NumText, "%d", Number);

This may not be the coolest, OOP way of doing this, but it works for me.  I
suppose that you could obfuscate things by wrapping the sprintf in another
function or even create a method for a numeric class that returns that number
as a string... but it's probably overkill in this case.

--
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== === = === = === =============================================================
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