Josh Fallon (FallonJB95%cs29@cadetmail.usafa.af.mil) wrote:

: Hi,
:  I am relativly new to C++ and am having a small problem.  I want to
: create a pointer to a multidimensional array, but the compiler says that it
: can't convert one type to another.  Here is the troublesome line

: Unsigned Int* MyName = New Char[8000][3] ;

: If I make it one dimensional, it works fine, but otherwise I get the "Can't
: convert Char[3] to Unsigned Int*.  I realize I am probably violating some
: basic rule, so if anyone can help me out, I'd appreciate it.  Thanks.
: E-mail or posting is fine.

See the FAQ for comp.lang.c. In the mean time, try this:

 char (*MyName)[3] = new char[8000][3];

Remember that C and C++ don't really have 2-D arrays; they only have 1-D
arrays, but an array can have items that are themselves arrays. So...

 char table[10][80];

defines an array of 10 items; each item is an array of 80 char. To assign
table's address to a pointer, that pointer has to point to "an array of 80
char", and because of C++ precendence rules, you need the parens in the
pointer definition:

 char (*tp)[80] = table;

BTW: howcome the base type for your pointer was "unsigned int", but
you used "new char..."?

Hope this helps,

--
Mike Woinoski

Hi,
 I am relativly new to C++ and am having a small problem.  I want to
create a pointer to a multidimensional array, but the compiler says that it
can't convert one type to another.  Here is the troublesome line

Unsigned Int* MyName = New Char[8000][3] ;

If I make it one dimensional, it works fine, but otherwise I get the "Can't
convert Char[3] to Unsigned Int*.  I realize I am probably violating some
basic rule, so if anyone can help me out, I'd appreciate it.  Thanks.
E-mail or posting is fine.

--Josh
 Fallonjb95%cs29@cadetmail.usafa.af.mil