jason@cygnus.com (Jason Merrill) writes:

>Would someone please explain to me again why this conversion is unsafe?
>I've seen the rationale a couple of times now, but I keep forgetting.  I
>swear I'll save it this time...:)

I could have sworn I saved it last time, but I can't find it.
Oh well, the wetware backup seems to have worked, albeit with a rather
long access time ;-)

 char *p, **pp;
        const char *pc, **ppc;

 pc = "foo";  // fine
 pp = &p;  // ok, `char **' on both sides
 ppc = pp;  // doubtful: `char **' -> `const char **'
 *ppc = pc;  // ok, `const char *' on both sides
 *p = 'x';  // oops, `p' points to "foo" -
    // we've attempted to modify a string literal!

--
Fergus Henderson - fjh@munta.cs.mu.oz.au

In article <JASON.94Sep21143003@deneb.cygnus.com> jason@cygnus.com (Jason Merrill) writes:

> Would someone please explain to me again why this conversion is unsafe?

   char const *str = "foo";
   char *x[1];
   char const **y = (char const**)x;
   *y = str;
   **x = 'x';   // Modify *str

> Where's a FAQ list when you need one?

Still at rtfm.mit.edu, I suppose:-)

--
Regards,

Hallvard

>>>>> Hallvard B Furuseth <h.b.furuseth@usit.uio.no> writes:

>> Where's a FAQ list when you need one?

> Still at rtfm.mit.edu, I suppose:-)

Not for this group.

Jason