I'm currently working on a C++ Parser with the
Roskind grammar. I recently ran into a syntax error.
Here it is :

  int a;
  int &b = a;

  void main()
  {
    (int &)b = a;
  }

Typically, a type cast can't be an lvalue but in the
case of a cast to a reference it can. The grammar doesn't
support it. Does anyone know what to do with this?

--
Philippe Mathieu (mathieu@info.polymtl.ca)

   " This is a test..." , Ministry