C and C++ do not contain array denotations, nor a rowing coercion. What you
want is Algol 68 - of blessed memory.

--------------
Raphael Mankin   Nil taurus excretum

Here's the deal. The other day I was writing a string cat function
to put a character onto the end of a string. I tried something like
this...

void strCat(char *fred, char bob)
{
/* ... */
 strcat(fred, (char*){bob, 0});
/* ... */
}


and borland c++ 3.1 spat. I can't recall the actual error, but someone
may know exactly why this wasn't allowed. Help?

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s913606@yallara.cs.rmit.OZ.AU (Mab) writes:

>Here's the deal. The other day I was writing a string cat function
>to put a character onto the end of a string. I tried something like
>this...

>void strCat(char *fred, char bob)
>{
>/* ... */
> strcat(fred, (char*){bob, 0});
>/* ... */
>}


>and borland c++ 3.1 spat. I can't recall the actual error, but someone
>may know exactly why this wasn't allowed. Help?
Why should it be allowed? It is not near anything being legitimate code.
What are those curly braces supposed to mean? A struct? An array?
If it is supposed to be the latter, you have to use char[] as your type.
But you cannot mix in some mightbe initialization into a function call.

Use a named array, such as char tmp[2] = {bob,0};
then use that as your second argument. However, I do not remember right
now whether C++ allows automatic array initializations. Might be, but
plain C does not. If C++ echoes this, you will have to use explicit
tmp[0] = bob, tmp[1] = '\0';


--
 David Kastrup        dak@messua.informatik.rwth-aachen.de
 Tel: +49-241-72419 Fax: +49-241-79502
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