Hello everyone,

I've got a question for all of you regarding the scope of friend functions.
ARM says on page 187 (last paragraph) that "Like a member function, a
friend function defined within a class is in teh lexical scope of that
class;".
   I believe this rule is incomplete. It only pertains to friend functions
that are not member functions of another class.
   Consider the case in the following source segment:


extern "C" int printf( const char * ...);

int ::i = 5 ;

class OUT1{
public:
 static i;
 void f();
};

class OUT2{
public:
 static i;
 friend void OUT1::f() {
  printf("i = %d\n", i);  // <-- Which i should be printed ?
 }
};

// Definition of Static members
int OUT1::i = 10;
int OUT2::i = 20;

void main() {
 OUT1 obj;
 obj.f();
}

  Class OUT2 defines the member function OUT1::f() in a friend function
declaration. What would be the order that a compiler will do a look-up
for the name i ? Would that be :
     void OUT1::f()  (scope of member function)
     class  OUT1     (scope of class OUT2 )
     global scope

   Would the scope of class OUT2 ever be considered. In other words if
none of ::i, OUT1::i is defined, would the compiler ever resolve i to
OUT2::i ?

   By the way CFRONT gives a link error in this case (unresolved OUT1::f)!!!!

   Thanks a lot in advance.
   Speros Armyros