Topic: Why lambda's operator() is not constexpr?


Author: Zhihao Yuan <lichray@gmail.com>
Date: Sun, 23 Jun 2013 17:47:31 -0400
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I just want to call a lambda within a constexpr function...
And I have to write a functor by hand...

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Zhihao Yuan, ID lichray
The best way to predict the future is to invent it.
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4BSD -- http://4bsd.biz/

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