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Now that in C++, auto constructor is calling constructors by type deduction
of constructor arguments.
But I want to call constructors by type deduction of variable when auto
constructor to variable that has been declared type.
Where you can not use auto variable, for example the type of the
initialization of the member variable will be able to be abbreviated.

#include <vector>
#include <type_traits>

struct foo
{
    std::vector<int> a;
    std::vector<int> *b;
    foo()
    {
        //This is the same as "a =
std::remove_pointer<decltype(a)>::type();" or "a = decltype(a)();"
        a = auto();

        //This is the same as "b = new
std::remove_pointer<decltype(b)>::type();"
        b = new auto();
    }
};

Thank you

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<div dir=3D"ltr">Now that in C++, auto constructor is calling constructors =
by type deduction of constructor arguments.<br>But I want to call construct=
ors by type deduction of variable when auto constructor to variable that ha=
s been declared type.<br>Where you can not use auto variable, for example t=
he type of the initialization of the member variable will be able to be abb=
reviated.<br><br>#include &lt;vector&gt;<br>#include &lt;type_traits&gt;<br=
><br>struct foo<br>{<br>&nbsp;&nbsp;&nbsp; std::vector&lt;int&gt; a;<br>&nb=
sp;&nbsp;&nbsp; std::vector&lt;int&gt; *b;<br>&nbsp;&nbsp;&nbsp; foo()<br>&=
nbsp;&nbsp;&nbsp; {<br>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; //This is=
 the same as "a =3D std::remove_pointer&lt;decltype(a)&gt;::type();" or "a =
=3D decltype(a)();"<br>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; a =3D aut=
o();<br><br>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; //This is the same a=
s "b =3D new std::remove_pointer&lt;decltype(b)&gt;::type();"<br>&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; b =3D new auto();<br>&nbsp;&nbsp;&nbsp; }<=
br>};<br><br>Thank you<br></div>

<p></p>

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/a>.<br />

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