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Is there an existing proposal for, or perhaps an existing language feature,
that can be used like boost::size() on basic arrays (not std::arrays) to
obtain its size in elements? The idiom sizeof (arr) / sizeof (arr[0]) is
well-known and, without constexpr, there was no full equivalent of it.

Note my question is about something as simple as std::size(x); I know I can
build one from other things like as std::begin() and std::end(), but then I
would need to wrap that into some compact function; having to write these
wrappers (or macros earlier) is precisely what I find desirable to avoid.

Cheers,
V.

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<div dir=3D"ltr">Is there an existing proposal for, or perhaps an existing =
language feature, that can be used like boost::size() on basic arrays (not =
std::arrays) to obtain its size in elements? The idiom sizeof (arr) / sizeo=
f (arr[0]) is well-known and, without constexpr, there was no full equivale=
nt of it.<div><br></div><div>Note my question is about something as simple =
as std::size(x); I know I can build one from other things like as std::begi=
n() and std::end(), but then I would need to wrap that into some compact fu=
nction; having to write these wrappers (or macros earlier) is precisely wha=
t I find desirable to avoid.</div><div><br></div><div>Cheers,<br></div><div=
>V.</div></div>

<p></p>

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2015-12-15 15:50 GMT+01:00 Viacheslav Usov <via.usov@gmail.com>:
> Is there an existing proposal for, or perhaps an existing language feature,
> that can be used like boost::size() on basic arrays (not std::arrays) to
> obtain its size in elements? The idiom sizeof (arr) / sizeof (arr[0]) is
> well-known and, without constexpr, there was no full equivalent of it.

It's already part of the current working draft, see header <iterator>,
which provides free, constexpr function templates, supporting both
built-in arrays and types that have a size() member function.

> Note my question is about something as simple as std::size(x); I know I can
> build one from other things like as std::begin() and std::end(), but then I
> would need to wrap that into some compact function; having to write these
> wrappers (or macros earlier) is precisely what I find desirable to avoid.

Exactly this std::size function does already exist.

- Daniel

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Thanks. So now I just need to figure out what compilers already support
that.

Cheers,
V.

On Tue, Dec 15, 2015 at 4:15 PM, Daniel Kr=C3=BCgler <daniel.kruegler@gmail=
..com>
wrote:

> 2015-12-15 15:50 GMT+01:00 Viacheslav Usov <via.usov@gmail.com>:
> > Is there an existing proposal for, or perhaps an existing language
> feature,
> > that can be used like boost::size() on basic arrays (not std::arrays) t=
o
> > obtain its size in elements? The idiom sizeof (arr) / sizeof (arr[0]) i=
s
> > well-known and, without constexpr, there was no full equivalent of it.
>
> It's already part of the current working draft, see header <iterator>,
> which provides free, constexpr function templates, supporting both
> built-in arrays and types that have a size() member function.
>
> > Note my question is about something as simple as std::size(x); I know I
> can
> > build one from other things like as std::begin() and std::end(), but
> then I
> > would need to wrap that into some compact function; having to write the=
se
> > wrappers (or macros earlier) is precisely what I find desirable to avoi=
d.
>
> Exactly this std::size function does already exist.
>
> - Daniel
>
> --
>
> ---
> You received this message because you are subscribed to the Google Groups
> "ISO C++ Standard - Future Proposals" group.
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> https://groups.google.com/a/isocpp.org/group/std-proposals/.
>

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<div dir=3D"ltr">Thanks. So now I just need to figure out what compilers al=
ready support that.<div><br></div><div>Cheers,</div><div>V.</div></div><div=
 class=3D"gmail_extra"><br><div class=3D"gmail_quote">On Tue, Dec 15, 2015 =
at 4:15 PM, Daniel Kr=C3=BCgler <span dir=3D"ltr">&lt;<a href=3D"mailto:dan=
iel.kruegler@gmail.com" target=3D"_blank">daniel.kruegler@gmail.com</a>&gt;=
</span> wrote:<br><blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .=
8ex;border-left:1px #ccc solid;padding-left:1ex">2015-12-15 15:50 GMT+01:00=
 Viacheslav Usov &lt;<a href=3D"mailto:via.usov@gmail.com">via.usov@gmail.c=
om</a>&gt;:<br>
&gt; Is there an existing proposal for, or perhaps an existing language fea=
ture,<br>
&gt; that can be used like boost::size() on basic arrays (not std::arrays) =
to<br>
&gt; obtain its size in elements? The idiom sizeof (arr) / sizeof (arr[0]) =
is<br>
&gt; well-known and, without constexpr, there was no full equivalent of it.=
<br>
<br>
It&#39;s already part of the current working draft, see header &lt;iterator=
&gt;,<br>
which provides free, constexpr function templates, supporting both<br>
built-in arrays and types that have a size() member function.<br>
<br>
&gt; Note my question is about something as simple as std::size(x); I know =
I can<br>
&gt; build one from other things like as std::begin() and std::end(), but t=
hen I<br>
&gt; would need to wrap that into some compact function; having to write th=
ese<br>
&gt; wrappers (or macros earlier) is precisely what I find desirable to avo=
id.<br>
<br>
Exactly this std::size function does already exist.<br>
<span class=3D"HOEnZb"><font color=3D"#888888"><br>
- Daniel<br>
<br>
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..com/a/isocpp.org/group/std-proposals/</a>.<br>
</font></span></blockquote></div><br></div>

<p></p>

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