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Hi,

Would anyone be interested in adding std::shift to <algorithm>?

It would be similar to both:
- std::rotate, but without moving the head elements back to the tail. This
would allow a more efficient implementation and clearer semantics in case
rotation is not needed as well as correctness in case rotation is undesired.
- <algorithm>'s std::move/std::move_backward (depending on the shift
direction).

std::shift should probably accommodate both left and right shifts by one of:
- giving it either begin() and end(), or rbegin() and rend(), similar to
how std::rotate works for both left and right rotations. The advantage is
compactness of the implementation.
- allowing the shift count parameter to be either positive or negative. The
advantage is compactness, though it might not be clear which direction is
which - to be consistent with rotate, positive integers should shift to the
left.
- having std::shift_right and std::shift_left functions. The advantage is
clarity when calling the methods, although the same argument could be made
for having separate std::rotate_left and std::rotate_right instead of
std::rotate, which we don't have.

Here's a sample implementation of a shift to the right direction:

template<class BidirIt>
void shift_right(BidirIt first, BidirIt last, unsigned int n = 1)
{
    std::move_backward(first, last - n, last);
}

This demonstrates that while std::shift is implementable with
std::move/std::move_backward,
1) It isn't immediately clear from the code (at least to my eyes) that this
is a shift right, unless you are intimately familiar with
std::move_backward.
2) Different calls, either to std::move or to std::move_backward, are
required, depending on the shift direction.

So, implementing std::shift would allow writing more readable code.

Thanks,
Dan

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<div dir=3D"ltr">Hi,<div><br></div><div>Would anyone be interested in addin=
g std::shift to &lt;algorithm&gt;?=C2=A0</div><div><br></div><div>It would =
be similar to both:</div><div>- std::rotate, but without moving the head el=
ements back to the tail. This would allow a more efficient implementation a=
nd clearer semantics in case rotation is not needed as well as correctness =
in case rotation is undesired.</div><div>- &lt;algorithm&gt;&#39;s std::mov=
e/std::move_backward (depending on the shift direction).</div><div><br></di=
v><div>std::shift should probably accommodate both left and right shifts by=
 one of:</div><div>- giving it either begin() and end(), or rbegin() and re=
nd(), similar to how std::rotate works for both left and right rotations. T=
he advantage is compactness of the implementation.</div><div>- allowing the=
 shift count parameter to be either positive or negative. The advantage is =
compactness, though it might not be clear which direction is which - to be =
consistent with rotate, positive integers should shift to the left.<br></di=
v><div><div>- having std::shift_right and std::shift_left functions. The ad=
vantage is clarity when calling the methods, although the same argument cou=
ld be made for having separate std::rotate_left and std::rotate_right inste=
ad of std::rotate, which we don&#39;t have.</div></div><div><br></div><div>=
Here&#39;s a sample implementation of a shift to the right direction:</div>=
<br><div class=3D"prettyprint" style=3D"background-color: rgb(250, 250, 250=
); border: 1px solid rgb(187, 187, 187); word-wrap: break-word;"><code clas=
s=3D"prettyprint"><div class=3D"subprettyprint"><span style=3D"color: #008;=
" class=3D"styled-by-prettify">template</span><span style=3D"color: #660;" =
class=3D"styled-by-prettify">&lt;</span><span style=3D"color: #008;" class=
=3D"styled-by-prettify">class</span><span style=3D"color: #000;" class=3D"s=
tyled-by-prettify"> </span><span style=3D"color: #606;" class=3D"styled-by-=
prettify">BidirIt</span><span style=3D"color: #660;" class=3D"styled-by-pre=
ttify">&gt;</span><span style=3D"color: #000;" class=3D"styled-by-prettify"=
> <br></span><span style=3D"color: #008;" class=3D"styled-by-prettify">void=
</span><span style=3D"color: #000;" class=3D"styled-by-prettify"> shift_rig=
ht</span><span style=3D"color: #660;" class=3D"styled-by-prettify">(</span>=
<span style=3D"color: #606;" class=3D"styled-by-prettify">BidirIt</span><sp=
an style=3D"color: #000;" class=3D"styled-by-prettify"> first</span><span s=
tyle=3D"color: #660;" class=3D"styled-by-prettify">,</span><span style=3D"c=
olor: #000;" class=3D"styled-by-prettify"> </span><span style=3D"color: #60=
6;" class=3D"styled-by-prettify">BidirIt</span><span style=3D"color: #000;"=
 class=3D"styled-by-prettify"> </span><span style=3D"color: #008;" class=3D=
"styled-by-prettify">last</span><span style=3D"color: #660;" class=3D"style=
d-by-prettify">,</span><span style=3D"color: #000;" class=3D"styled-by-pret=
tify"> </span><span style=3D"color: #008;" class=3D"styled-by-prettify">uns=
igned</span><span style=3D"color: #000;" class=3D"styled-by-prettify"> </sp=
an><span style=3D"color: #008;" class=3D"styled-by-prettify">int</span><spa=
n style=3D"color: #000;" class=3D"styled-by-prettify"> n </span><span style=
=3D"color: #660;" class=3D"styled-by-prettify">=3D</span><span style=3D"col=
or: #000;" class=3D"styled-by-prettify"> </span><span style=3D"color: #066;=
" class=3D"styled-by-prettify">1</span><span style=3D"color: #660;" class=
=3D"styled-by-prettify">)</span><span style=3D"color: #000;" class=3D"style=
d-by-prettify"> <br></span><span style=3D"color: #660;" class=3D"styled-by-=
prettify">{</span><span style=3D"color: #000;" class=3D"styled-by-prettify"=
> <br>=C2=A0 =C2=A0 std</span><span style=3D"color: #660;" class=3D"styled-=
by-prettify">::</span><span style=3D"color: #000;" class=3D"styled-by-prett=
ify">move_backward</span><span style=3D"color: #660;" class=3D"styled-by-pr=
ettify">(</span><span style=3D"color: #000;" class=3D"styled-by-prettify">f=
irst</span><span style=3D"color: #660;" class=3D"styled-by-prettify">,</spa=
n><span style=3D"color: #000;" class=3D"styled-by-prettify"> </span><span s=
tyle=3D"color: #008;" class=3D"styled-by-prettify">last</span><span style=
=3D"color: #000;" class=3D"styled-by-prettify"> </span><span style=3D"color=
: #660;" class=3D"styled-by-prettify">-</span><span style=3D"color: #000;" =
class=3D"styled-by-prettify"> n</span><span style=3D"color: #660;" class=3D=
"styled-by-prettify">,</span><span style=3D"color: #000;" class=3D"styled-b=
y-prettify"> </span><span style=3D"color: #008;" class=3D"styled-by-prettif=
y">last</span><span style=3D"color: #660;" class=3D"styled-by-prettify">);<=
/span><span style=3D"color: #000;" class=3D"styled-by-prettify"> <br></span=
><span style=3D"color: #660;" class=3D"styled-by-prettify">}</span><span st=
yle=3D"color: #000;" class=3D"styled-by-prettify"><br></span></div></code><=
/div><div><br></div><div>This demonstrates that while std::shift is impleme=
ntable with std::move/std::move_backward,</div><div>1) It isn&#39;t immedia=
tely clear from the code (at least to my eyes) that this is a shift right, =
unless you are intimately familiar with std::move_backward.</div><div>2) Di=
fferent calls, either to std::move or to std::move_backward, are required, =
depending on the shift direction.</div><div><br></div><div>So, implementing=
 std::shift would allow writing more readable code.</div><div><br></div><di=
v>Thanks,</div><div>Dan</div></div>

<p></p>

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Hello.

Really nice idea! But i have some suggestions:
* shift should return iterator (or two)
* it should be constexpr

Also i suggest you create PR to Boost.Algorithm (or we can work together -=
=20
i will help you as mush as possible). And after including into=20
Bost.Algorithm we can write proposal to C++ Standard.

=D1=81=D1=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=D1=8E=D0=BB=D1=8F 2017 =D0=B3., 1=
2:53:19 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=B5=
=D0=BB=D1=8C d...@soundradix.com=20
=D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=BB:
>
> Hi,
>
> Would anyone be interested in adding std::shift to <algorithm>?=20
>
> It would be similar to both:
> - std::rotate, but without moving the head elements back to the tail. Thi=
s=20
> would allow a more efficient implementation and clearer semantics in case=
=20
> rotation is not needed as well as correctness in case rotation is undesir=
ed.
> - <algorithm>'s std::move/std::move_backward (depending on the shift=20
> direction).
>
> std::shift should probably accommodate both left and right shifts by one=
=20
> of:
> - giving it either begin() and end(), or rbegin() and rend(), similar to=
=20
> how std::rotate works for both left and right rotations. The advantage is=
=20
> compactness of the implementation.
> - allowing the shift count parameter to be either positive or negative.=
=20
> The advantage is compactness, though it might not be clear which directio=
n=20
> is which - to be consistent with rotate, positive integers should shift t=
o=20
> the left.
> - having std::shift_right and std::shift_left functions. The advantage is=
=20
> clarity when calling the methods, although the same argument could be mad=
e=20
> for having separate std::rotate_left and std::rotate_right instead of=20
> std::rotate, which we don't have.
>
> Here's a sample implementation of a shift to the right direction:
>
> template<class BidirIt>=20
> void shift_right(BidirIt first, BidirIt last, unsigned int n =3D 1)=20
> {=20
>     std::move_backward(first, last - n, last);=20
> }
>
> This demonstrates that while std::shift is implementable with=20
> std::move/std::move_backward,
> 1) It isn't immediately clear from the code (at least to my eyes) that=20
> this is a shift right, unless you are intimately familiar with=20
> std::move_backward.
> 2) Different calls, either to std::move or to std::move_backward, are=20
> required, depending on the shift direction.
>
> So, implementing std::shift would allow writing more readable code.
>
> Thanks,
> Dan
>

--=20
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ISO C++ Standard - Future Proposals" group.
To unsubscribe from this group and stop receiving emails from it, send an e=
mail to std-proposals+unsubscribe@isocpp.org.
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g.

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<div dir=3D"ltr">Hello.<div><br></div><div>Really nice idea! But i have som=
e suggestions:</div><div>* shift should return iterator (or two)</div><div>=
* it should be constexpr</div><div><br></div><div>Also i suggest you create=
 PR to Boost.Algorithm (or we can work together - i will help you as mush a=
s possible). And after including into Bost.Algorithm we can write proposal =
to C++ Standard.<br><br>=D1=81=D1=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=D1=8E=D0=
=BB=D1=8F 2017 =D0=B3., 12:53:19 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=
=D0=B2=D0=B0=D1=82=D0=B5=D0=BB=D1=8C d...@soundradix.com =D0=BD=D0=B0=D0=BF=
=D0=B8=D1=81=D0=B0=D0=BB:<blockquote class=3D"gmail_quote" style=3D"margin:=
 0;margin-left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div =
dir=3D"ltr">Hi,<div><br></div><div>Would anyone be interested in adding std=
::shift to &lt;algorithm&gt;?=C2=A0</div><div><br></div><div>It would be si=
milar to both:</div><div>- std::rotate, but without moving the head element=
s back to the tail. This would allow a more efficient implementation and cl=
earer semantics in case rotation is not needed as well as correctness in ca=
se rotation is undesired.</div><div>- &lt;algorithm&gt;&#39;s std::move/std=
::move_backward (depending on the shift direction).</div><div><br></div><di=
v>std::shift should probably accommodate both left and right shifts by one =
of:</div><div>- giving it either begin() and end(), or rbegin() and rend(),=
 similar to how std::rotate works for both left and right rotations. The ad=
vantage is compactness of the implementation.</div><div>- allowing the shif=
t count parameter to be either positive or negative. The advantage is compa=
ctness, though it might not be clear which direction is which - to be consi=
stent with rotate, positive integers should shift to the left.<br></div><di=
v><div>- having std::shift_right and std::shift_left functions. The advanta=
ge is clarity when calling the methods, although the same argument could be=
 made for having separate std::rotate_left and std::rotate_right instead of=
 std::rotate, which we don&#39;t have.</div></div><div><br></div><div>Here&=
#39;s a sample implementation of a shift to the right direction:</div><br><=
div style=3D"background-color:rgb(250,250,250);border:1px solid rgb(187,187=
,187);word-wrap:break-word"><code><div><span style=3D"color:#008">template<=
/span><span style=3D"color:#660">&lt;</span><span style=3D"color:#008">clas=
s</span><span style=3D"color:#000"> </span><span style=3D"color:#606">Bidir=
It</span><span style=3D"color:#660">&gt;</span><span style=3D"color:#000"> =
<br></span><span style=3D"color:#008">void</span><span style=3D"color:#000"=
> shift_right</span><span style=3D"color:#660">(</span><span style=3D"color=
:#606">BidirIt</span><span style=3D"color:#000"> first</span><span style=3D=
"color:#660">,</span><span style=3D"color:#000"> </span><span style=3D"colo=
r:#606">BidirIt</span><span style=3D"color:#000"> </span><span style=3D"col=
or:#008">last</span><span style=3D"color:#660">,</span><span style=3D"color=
:#000"> </span><span style=3D"color:#008">unsigned</span><span style=3D"col=
or:#000"> </span><span style=3D"color:#008">int</span><span style=3D"color:=
#000"> n </span><span style=3D"color:#660">=3D</span><span style=3D"color:#=
000"> </span><span style=3D"color:#066">1</span><span style=3D"color:#660">=
)</span><span style=3D"color:#000"> <br></span><span style=3D"color:#660">{=
</span><span style=3D"color:#000"> <br>=C2=A0 =C2=A0 std</span><span style=
=3D"color:#660">::</span><span style=3D"color:#000">move_backward</span><sp=
an style=3D"color:#660">(</span><span style=3D"color:#000">first</span><spa=
n style=3D"color:#660">,</span><span style=3D"color:#000"> </span><span sty=
le=3D"color:#008">last</span><span style=3D"color:#000"> </span><span style=
=3D"color:#660">-</span><span style=3D"color:#000"> n</span><span style=3D"=
color:#660">,</span><span style=3D"color:#000"> </span><span style=3D"color=
:#008">last</span><span style=3D"color:#660">);</span><span style=3D"color:=
#000"> <br></span><span style=3D"color:#660">}</span><span style=3D"color:#=
000"><br></span></div></code></div><div><br></div><div>This demonstrates th=
at while std::shift is implementable with std::move/std::move_backward,</di=
v><div>1) It isn&#39;t immediately clear from the code (at least to my eyes=
) that this is a shift right, unless you are intimately familiar with std::=
move_backward.</div><div>2) Different calls, either to std::move or to std:=
:move_backward, are required, depending on the shift direction.</div><div><=
br></div><div>So, implementing std::shift would allow writing more readable=
 code.</div><div><br></div><div>Thanks,</div><div>Dan</div></div></blockquo=
te></div></div>

<p></p>

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Sure, it can return an iterator (or at least have an overload which does)
similar to std::rotate / std::move.
I agree about constexpr, but I guess that would come with the rest of the
<algorithm> algorithms become constexpr.

Since it's such a simple algorithm, with the main benefit of adding it to
the STL being adding readability/efficiency/concise, I'm not whether
submitting it to boost.algorithm first would be a more effective way to go
than just making a proposal. What do you think?

Thanks,
Dan

On Wed, Jul 12, 2017 at 2:18 PM, Alexander Zaitsev <zamazan4ik@gmail.com>
wrote:

> Hello.
>
> Really nice idea! But i have some suggestions:
> * shift should return iterator (or two)
> * it should be constexpr
>
> Also i suggest you create PR to Boost.Algorithm (or we can work together =
-
> i will help you as mush as possible). And after including into
> Bost.Algorithm we can write proposal to C++ Standard.
>
> =D1=81=D1=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=D1=8E=D0=BB=D1=8F 2017 =D0=B3.,=
 12:53:19 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=
=B5=D0=BB=D1=8C d...@soundradix.com
> =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=BB:
>>
>> Hi,
>>
>> Would anyone be interested in adding std::shift to <algorithm>?
>>
>> It would be similar to both:
>> - std::rotate, but without moving the head elements back to the tail.
>> This would allow a more efficient implementation and clearer semantics i=
n
>> case rotation is not needed as well as correctness in case rotation is
>> undesired.
>> - <algorithm>'s std::move/std::move_backward (depending on the shift
>> direction).
>>
>> std::shift should probably accommodate both left and right shifts by one
>> of:
>> - giving it either begin() and end(), or rbegin() and rend(), similar to
>> how std::rotate works for both left and right rotations. The advantage i=
s
>> compactness of the implementation.
>> - allowing the shift count parameter to be either positive or negative.
>> The advantage is compactness, though it might not be clear which directi=
on
>> is which - to be consistent with rotate, positive integers should shift =
to
>> the left.
>> - having std::shift_right and std::shift_left functions. The advantage i=
s
>> clarity when calling the methods, although the same argument could be ma=
de
>> for having separate std::rotate_left and std::rotate_right instead of
>> std::rotate, which we don't have.
>>
>> Here's a sample implementation of a shift to the right direction:
>>
>> template<class BidirIt>
>> void shift_right(BidirIt first, BidirIt last, unsigned int n =3D 1)
>> {
>>     std::move_backward(first, last - n, last);
>> }
>>
>> This demonstrates that while std::shift is implementable with
>> std::move/std::move_backward,
>> 1) It isn't immediately clear from the code (at least to my eyes) that
>> this is a shift right, unless you are intimately familiar with
>> std::move_backward.
>> 2) Different calls, either to std::move or to std::move_backward, are
>> required, depending on the shift direction.
>>
>> So, implementing std::shift would allow writing more readable code.
>>
>> Thanks,
>> Dan
>>
> --
> You received this message because you are subscribed to the Google Groups
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> isocpp.org/d/msgid/std-proposals/55df161b-f0c5-4d81-
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> <https://groups.google.com/a/isocpp.org/d/msgid/std-proposals/55df161b-f0=
c5-4d81-ad1d-882425e7bf8a%40isocpp.org?utm_medium=3Demail&utm_source=3Dfoot=
er>
> .
>

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<div dir=3D"ltr">Sure, it can return an iterator (or at least have an overl=
oad which does) similar to std::rotate / std::move.<div>I agree about const=
expr, but I guess that would come with the rest of the &lt;algorithm&gt; al=
gorithms become constexpr.</div><div><br></div><div>Since it&#39;s such a s=
imple algorithm, with the main benefit of adding it to the STL being adding=
 readability/efficiency/<wbr>concise, I&#39;m not whether submitting it to =
boost.algorithm first would be a more effective way to go than just making =
a proposal. What do you think?</div><div><br></div><div>Thanks,</div><div>D=
an</div></div><div class=3D"gmail_extra"><br><div class=3D"gmail_quote">On =
Wed, Jul 12, 2017 at 2:18 PM, Alexander Zaitsev <span dir=3D"ltr">&lt;<a hr=
ef=3D"mailto:zamazan4ik@gmail.com" target=3D"_blank">zamazan4ik@gmail.com</=
a>&gt;</span> wrote:<br><blockquote class=3D"gmail_quote" style=3D"margin:0=
 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">Hel=
lo.<div><br></div><div>Really nice idea! But i have some suggestions:</div>=
<div>* shift should return iterator (or two)</div><div>* it should be const=
expr</div><div><br></div><div>Also i suggest you create PR to Boost.Algorit=
hm (or we can work together - i will help you as mush as possible). And aft=
er including into Bost.Algorithm we can write proposal to C++ Standard.<br>=
<br>=D1=81=D1=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=D1=8E=D0=BB=D1=8F 2017 =D0=B3=
.., 12:53:19 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=
=B5=D0=BB=D1=8C <a href=3D"mailto:d...@soundradix.com" target=3D"_blank">d.=
...@soundradix.com</a> =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=BB:<span clas=
s=3D""><blockquote class=3D"gmail_quote" style=3D"margin:0;margin-left:0.8e=
x;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">Hi,<div><br=
></div><div>Would anyone be interested in adding std::shift to &lt;algorith=
m&gt;?=C2=A0</div><div><br></div><div>It would be similar to both:</div><di=
v>- std::rotate, but without moving the head elements back to the tail. Thi=
s would allow a more efficient implementation and clearer semantics in case=
 rotation is not needed as well as correctness in case rotation is undesire=
d.</div><div>- &lt;algorithm&gt;&#39;s std::move/std::move_backward (depend=
ing on the shift direction).</div><div><br></div><div>std::shift should pro=
bably accommodate both left and right shifts by one of:</div><div>- giving =
it either begin() and end(), or rbegin() and rend(), similar to how std::ro=
tate works for both left and right rotations. The advantage is compactness =
of the implementation.</div><div>- allowing the shift count parameter to be=
 either positive or negative. The advantage is compactness, though it might=
 not be clear which direction is which - to be consistent with rotate, posi=
tive integers should shift to the left.<br></div><div><div>- having std::sh=
ift_right and std::shift_left functions. The advantage is clarity when call=
ing the methods, although the same argument could be made for having separa=
te std::rotate_left and std::rotate_right instead of std::rotate, which we =
don&#39;t have.</div></div><div><br></div><div>Here&#39;s a sample implemen=
tation of a shift to the right direction:</div><br><div style=3D"background=
-color:rgb(250,250,250);border:1px solid rgb(187,187,187);word-wrap:break-w=
ord"><code><div><span style=3D"color:#008">template</span><span style=3D"co=
lor:#660">&lt;</span><span style=3D"color:#008">class</span><span style=3D"=
color:#000"> </span><span style=3D"color:#606">BidirIt</span><span style=3D=
"color:#660">&gt;</span><span style=3D"color:#000"> <br></span><span style=
=3D"color:#008">void</span><span style=3D"color:#000"> shift_right</span><s=
pan style=3D"color:#660">(</span><span style=3D"color:#606">BidirIt</span><=
span style=3D"color:#000"> first</span><span style=3D"color:#660">,</span><=
span style=3D"color:#000"> </span><span style=3D"color:#606">BidirIt</span>=
<span style=3D"color:#000"> </span><span style=3D"color:#008">last</span><s=
pan style=3D"color:#660">,</span><span style=3D"color:#000"> </span><span s=
tyle=3D"color:#008">unsigned</span><span style=3D"color:#000"> </span><span=
 style=3D"color:#008">int</span><span style=3D"color:#000"> n </span><span =
style=3D"color:#660">=3D</span><span style=3D"color:#000"> </span><span sty=
le=3D"color:#066">1</span><span style=3D"color:#660">)</span><span style=3D=
"color:#000"> <br></span><span style=3D"color:#660">{</span><span style=3D"=
color:#000"> <br>=C2=A0 =C2=A0 std</span><span style=3D"color:#660">::</spa=
n><span style=3D"color:#000">move_backward</span><span style=3D"color:#660"=
>(</span><span style=3D"color:#000">first</span><span style=3D"color:#660">=
,</span><span style=3D"color:#000"> </span><span style=3D"color:#008">last<=
/span><span style=3D"color:#000"> </span><span style=3D"color:#660">-</span=
><span style=3D"color:#000"> n</span><span style=3D"color:#660">,</span><sp=
an style=3D"color:#000"> </span><span style=3D"color:#008">last</span><span=
 style=3D"color:#660">);</span><span style=3D"color:#000"> <br></span><span=
 style=3D"color:#660">}</span><span style=3D"color:#000"><br></span></div><=
/code></div><div><br></div><div>This demonstrates that while std::shift is =
implementable with std::move/std::move_backward,</div><div>1) It isn&#39;t =
immediately clear from the code (at least to my eyes) that this is a shift =
right, unless you are intimately familiar with std::move_backward.</div><di=
v>2) Different calls, either to std::move or to std::move_backward, are req=
uired, depending on the shift direction.</div><div><br></div><div>So, imple=
menting std::shift would allow writing more readable code.</div><div><br></=
div><div>Thanks,</div><div>Dan</div></div></blockquote></span></div></div><=
span class=3D"">

<p></p>

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161b-f0c5-4d81-<wbr>ad1d-882425e7bf8a%40isocpp.org</a><wbr>.<br>
</blockquote></div><br></div>

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whatever I will add these algorithms to Boost.Algorithm (i am=20
Boost.Algorithm developer). If you have some prototype of proposal already,=
=20
pls send it me. We can discuss, improve your solution and after that i will=
=20
implement it to Boost.Algorithm.=20

=D1=81=D1=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=D1=8E=D0=BB=D1=8F 2017 =D0=B3., 1=
6:56:34 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=B5=
=D0=BB=D1=8C Dan Raviv =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=BB:
>
> Sure, it can return an iterator (or at least have an overload which does)=
=20
> similar to std::rotate / std::move.
> I agree about constexpr, but I guess that would come with the rest of the=
=20
> <algorithm> algorithms become constexpr.
>
> Since it's such a simple algorithm, with the main benefit of adding it to=
=20
> the STL being adding readability/efficiency/concise, I'm not whether=20
> submitting it to boost.algorithm first would be a more effective way to g=
o=20
> than just making a proposal. What do you think?
>
> Thanks,
> Dan
>
> On Wed, Jul 12, 2017 at 2:18 PM, Alexander Zaitsev <zamaz...@gmail.com=20
> <javascript:>> wrote:
>
>> Hello.
>>
>> Really nice idea! But i have some suggestions:
>> * shift should return iterator (or two)
>> * it should be constexpr
>>
>> Also i suggest you create PR to Boost.Algorithm (or we can work together=
=20
>> - i will help you as mush as possible). And after including into=20
>> Bost.Algorithm we can write proposal to C++ Standard.
>>
>> =D1=81=D1=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=D1=8E=D0=BB=D1=8F 2017 =D0=B3.=
, 12:53:19 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=
=B5=D0=BB=D1=8C d...@soundradix.com=20
>> =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=BB:
>>>
>>> Hi,
>>>
>>> Would anyone be interested in adding std::shift to <algorithm>?=20
>>>
>>> It would be similar to both:
>>> - std::rotate, but without moving the head elements back to the tail.=
=20
>>> This would allow a more efficient implementation and clearer semantics =
in=20
>>> case rotation is not needed as well as correctness in case rotation is=
=20
>>> undesired.
>>> - <algorithm>'s std::move/std::move_backward (depending on the shift=20
>>> direction).
>>>
>>> std::shift should probably accommodate both left and right shifts by on=
e=20
>>> of:
>>> - giving it either begin() and end(), or rbegin() and rend(), similar t=
o=20
>>> how std::rotate works for both left and right rotations. The advantage =
is=20
>>> compactness of the implementation.
>>> - allowing the shift count parameter to be either positive or negative.=
=20
>>> The advantage is compactness, though it might not be clear which direct=
ion=20
>>> is which - to be consistent with rotate, positive integers should shift=
 to=20
>>> the left.
>>> - having std::shift_right and std::shift_left functions. The advantage=
=20
>>> is clarity when calling the methods, although the same argument could b=
e=20
>>> made for having separate std::rotate_left and std::rotate_right instead=
 of=20
>>> std::rotate, which we don't have.
>>>
>>> Here's a sample implementation of a shift to the right direction:
>>>
>>> template<class BidirIt>=20
>>> void shift_right(BidirIt first, BidirIt last, unsigned int n =3D 1)=20
>>> {=20
>>>     std::move_backward(first, last - n, last);=20
>>> }
>>>
>>> This demonstrates that while std::shift is implementable with=20
>>> std::move/std::move_backward,
>>> 1) It isn't immediately clear from the code (at least to my eyes) that=
=20
>>> this is a shift right, unless you are intimately familiar with=20
>>> std::move_backward.
>>> 2) Different calls, either to std::move or to std::move_backward, are=
=20
>>> required, depending on the shift direction.
>>>
>>> So, implementing std::shift would allow writing more readable code.
>>>
>>> Thanks,
>>> Dan
>>>
>> --=20
>> You received this message because you are subscribed to the Google Group=
s=20
>> "ISO C++ Standard - Future Proposals" group.
>> To unsubscribe from this group and stop receiving emails from it, send a=
n=20
>> email to std-proposal...@isocpp.org <javascript:>.
>> To post to this group, send email to std-pr...@isocpp.org <javascript:>.
>> To view this discussion on the web visit=20
>> https://groups.google.com/a/isocpp.org/d/msgid/std-proposals/55df161b-f0=
c5-4d81-ad1d-882425e7bf8a%40isocpp.org=20
>> <https://groups.google.com/a/isocpp.org/d/msgid/std-proposals/55df161b-f=
0c5-4d81-ad1d-882425e7bf8a%40isocpp.org?utm_medium=3Demail&utm_source=3Dfoo=
ter>
>> .
>>
>
>

--=20
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<div dir=3D"ltr"><span style=3D"color: rgb(0, 0, 0); font-family: arial, sa=
ns-serif; white-space: nowrap; text-decoration: underline;">whatever=C2=A0<=
/span>I will add these algorithms to Boost.Algorithm (i am Boost.Algorithm =
developer). If you have some prototype of proposal already, pls send it me.=
 We can discuss, improve your solution and after that i will implement it t=
o Boost.Algorithm.=C2=A0<br><br>=D1=81=D1=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=
=D1=8E=D0=BB=D1=8F 2017 =D0=B3., 16:56:34 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=
=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=B5=D0=BB=D1=8C Dan Raviv =D0=BD=D0=B0=D0=BF=
=D0=B8=D1=81=D0=B0=D0=BB:<blockquote class=3D"gmail_quote" style=3D"margin:=
 0;margin-left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div =
dir=3D"ltr">Sure, it can return an iterator (or at least have an overload w=
hich does) similar to std::rotate / std::move.<div>I agree about constexpr,=
 but I guess that would come with the rest of the &lt;algorithm&gt; algorit=
hms become constexpr.</div><div><br></div><div>Since it&#39;s such a simple=
 algorithm, with the main benefit of adding it to the STL being adding read=
ability/efficiency/<wbr>concise, I&#39;m not whether submitting it to boost=
..algorithm first would be a more effective way to go than just making a pro=
posal. What do you think?</div><div><br></div><div>Thanks,</div><div>Dan</d=
iv></div><div><br><div class=3D"gmail_quote">On Wed, Jul 12, 2017 at 2:18 P=
M, Alexander Zaitsev <span dir=3D"ltr">&lt;<a href=3D"javascript:" target=
=3D"_blank" gdf-obfuscated-mailto=3D"ZR_Ya3IUBgAJ" rel=3D"nofollow" onmouse=
down=3D"this.href=3D&#39;javascript:&#39;;return true;" onclick=3D"this.hre=
f=3D&#39;javascript:&#39;;return true;">zamaz...@gmail.com</a>&gt;</span> w=
rote:<br><blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;borde=
r-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">Hello.<div><br></d=
iv><div>Really nice idea! But i have some suggestions:</div><div>* shift sh=
ould return iterator (or two)</div><div>* it should be constexpr</div><div>=
<br></div><div>Also i suggest you create PR to Boost.Algorithm (or we can w=
ork together - i will help you as mush as possible). And after including in=
to Bost.Algorithm we can write proposal to C++ Standard.<br><br>=D1=81=D1=
=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=D1=8E=D0=BB=D1=8F 2017 =D0=B3., 12:53:19 U=
TC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=B5=D0=BB=D1=
=8C <a>d...@soundradix.com</a> =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=BB:<=
span><blockquote class=3D"gmail_quote" style=3D"margin:0;margin-left:0.8ex;=
border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">Hi,<div><br><=
/div><div>Would anyone be interested in adding std::shift to &lt;algorithm&=
gt;?=C2=A0</div><div><br></div><div>It would be similar to both:</div><div>=
- std::rotate, but without moving the head elements back to the tail. This =
would allow a more efficient implementation and clearer semantics in case r=
otation is not needed as well as correctness in case rotation is undesired.=
</div><div>- &lt;algorithm&gt;&#39;s std::move/std::move_backward (dependin=
g on the shift direction).</div><div><br></div><div>std::shift should proba=
bly accommodate both left and right shifts by one of:</div><div>- giving it=
 either begin() and end(), or rbegin() and rend(), similar to how std::rota=
te works for both left and right rotations. The advantage is compactness of=
 the implementation.</div><div>- allowing the shift count parameter to be e=
ither positive or negative. The advantage is compactness, though it might n=
ot be clear which direction is which - to be consistent with rotate, positi=
ve integers should shift to the left.<br></div><div><div>- having std::shif=
t_right and std::shift_left functions. The advantage is clarity when callin=
g the methods, although the same argument could be made for having separate=
 std::rotate_left and std::rotate_right instead of std::rotate, which we do=
n&#39;t have.</div></div><div><br></div><div>Here&#39;s a sample implementa=
tion of a shift to the right direction:</div><br><div style=3D"background-c=
olor:rgb(250,250,250);border:1px solid rgb(187,187,187);word-wrap:break-wor=
d"><code><div><span style=3D"color:#008">template</span><span style=3D"colo=
r:#660">&lt;</span><span style=3D"color:#008">class</span><span style=3D"co=
lor:#000"> </span><span style=3D"color:#606">BidirIt</span><span style=3D"c=
olor:#660">&gt;</span><span style=3D"color:#000"> <br></span><span style=3D=
"color:#008">void</span><span style=3D"color:#000"> shift_right</span><span=
 style=3D"color:#660">(</span><span style=3D"color:#606">BidirIt</span><spa=
n style=3D"color:#000"> first</span><span style=3D"color:#660">,</span><spa=
n style=3D"color:#000"> </span><span style=3D"color:#606">BidirIt</span><sp=
an style=3D"color:#000"> </span><span style=3D"color:#008">last</span><span=
 style=3D"color:#660">,</span><span style=3D"color:#000"> </span><span styl=
e=3D"color:#008">unsigned</span><span style=3D"color:#000"> </span><span st=
yle=3D"color:#008">int</span><span style=3D"color:#000"> n </span><span sty=
le=3D"color:#660">=3D</span><span style=3D"color:#000"> </span><span style=
=3D"color:#066">1</span><span style=3D"color:#660">)</span><span style=3D"c=
olor:#000"> <br></span><span style=3D"color:#660">{</span><span style=3D"co=
lor:#000"> <br>=C2=A0 =C2=A0 std</span><span style=3D"color:#660">::</span>=
<span style=3D"color:#000">move_backward</span><span style=3D"color:#660">(=
</span><span style=3D"color:#000">first</span><span style=3D"color:#660">,<=
/span><span style=3D"color:#000"> </span><span style=3D"color:#008">last</s=
pan><span style=3D"color:#000"> </span><span style=3D"color:#660">-</span><=
span style=3D"color:#000"> n</span><span style=3D"color:#660">,</span><span=
 style=3D"color:#000"> </span><span style=3D"color:#008">last</span><span s=
tyle=3D"color:#660">);</span><span style=3D"color:#000"> <br></span><span s=
tyle=3D"color:#660">}</span><span style=3D"color:#000"><br></span></div></c=
ode></div><div><br></div><div>This demonstrates that while std::shift is im=
plementable with std::move/std::move_backward,</div><div>1) It isn&#39;t im=
mediately clear from the code (at least to my eyes) that this is a shift ri=
ght, unless you are intimately familiar with std::move_backward.</div><div>=
2) Different calls, either to std::move or to std::move_backward, are requi=
red, depending on the shift direction.</div><div><br></div><div>So, impleme=
nting std::shift would allow writing more readable code.</div><div><br></di=
v><div>Thanks,</div><div>Dan</div></div></blockquote></span></div></div><sp=
an>

<p></p>

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A couple additional comments about your sample implementation:

`n` should be `std::iterator_traits<BidirIt>::difference_type`, which is a
signed type (usually `std::ptrdiff_t`), instead of `unsigned`.

Bidirectional iterators aren't required to implement `operator-`, so the
second argument to `std::move_backward` should be `std::prev(last, n)`
instead of `last - n`.

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<div dir=3D"ltr">A couple additional comments about your sample implementat=
ion:<div><br></div><div><font face=3D"arial, sans-serif">`</font><font face=
=3D"courier new, monospace">n</font><font face=3D"arial, sans-serif">`=C2=
=A0should be `</font><font face=3D"courier new, monospace">std::iterator_tr=
aits&lt;BidirIt&gt;::difference_type</font><span style=3D"font-family: aria=
l, sans-serif;">`, which is a signed type (usually `</span><font face=3D"co=
urier new, monospace">std::ptrdiff_t</font><span style=3D"font-family: aria=
l, sans-serif;">`), i</span><font face=3D"arial, sans-serif">nstead of `</f=
ont><font face=3D"courier new, monospace">unsigned</font><font face=3D"aria=
l, sans-serif">`</font><span style=3D"font-family: arial, sans-serif;">.</s=
pan></div><div><span style=3D"font-family: arial, sans-serif;"><br></span><=
/div><div><span style=3D"font-family: arial, sans-serif;">Bidirectional ite=
rators aren&#39;t required to implement `</span><font face=3D"courier new, =
monospace">operator-</font><span style=3D"font-family: arial, sans-serif;">=
`, so the second argument to `</span><font face=3D"courier new, monospace">=
std::move_backward</font><span style=3D"font-family: arial, sans-serif;">` =
should be `</span><font face=3D"courier new, monospace">std::prev(last, n)<=
/font><span style=3D"font-family: arial, sans-serif;">` instead of `</span>=
<font face=3D"courier new, monospace">last - n</font><span style=3D"font-fa=
mily: arial, sans-serif;">`.</span></div></div>

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Yeah, you are right :)

We should create the most general implementation and efficient=20
implementation for any iterator type.=20

Also we should decide about type of shifting: circular and/or logical=20
shifting ( https://en.wikipedia.org/wiki/Circular_shift ).

=D1=81=D1=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=D1=8E=D0=BB=D1=8F 2017 =D0=B3., 2=
0:10:39 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=B5=
=D0=BB=D1=8C Ray Hamel =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=BB:
>
> A couple additional comments about your sample implementation:
>
> `n` should be `std::iterator_traits<BidirIt>::difference_type`, which is=
=20
> a signed type (usually `std::ptrdiff_t`), instead of `unsigned`.
>
> Bidirectional iterators aren't required to implement `operator-`, so the=
=20
> second argument to `std::move_backward` should be `std::prev(last, n)`=20
> instead of `last - n`.
>

--=20
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<div dir=3D"ltr">Yeah, you are right :)<div><br></div><div>We should create=
 the most general implementation and efficient implementation for any itera=
tor type.=C2=A0<br><br>Also we should decide about type of shifting: circul=
ar and/or logical shifting ( https://en.wikipedia.org/wiki/Circular_shift=
=C2=A0).<br><br>=D1=81=D1=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=D1=8E=D0=BB=D1=8F=
 2017 =D0=B3., 20:10:39 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=
=B0=D1=82=D0=B5=D0=BB=D1=8C Ray Hamel =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=
=D0=BB:<blockquote class=3D"gmail_quote" style=3D"margin: 0;margin-left: 0.=
8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"ltr">A coup=
le additional comments about your sample implementation:<div><br></div><div=
><font face=3D"arial, sans-serif">`</font><font face=3D"courier new, monosp=
ace">n</font><font face=3D"arial, sans-serif">`=C2=A0should be `</font><fon=
t face=3D"courier new, monospace">std::iterator_traits&lt;BidirIt&gt;<wbr>:=
:difference_type</font><span style=3D"font-family:arial,sans-serif">`, whic=
h is a signed type (usually `</span><font face=3D"courier new, monospace">s=
td::ptrdiff_t</font><span style=3D"font-family:arial,sans-serif">`), i</spa=
n><font face=3D"arial, sans-serif">nstead of `</font><font face=3D"courier =
new, monospace">unsigned</font><font face=3D"arial, sans-serif">`</font><sp=
an style=3D"font-family:arial,sans-serif">.</span></div><div><span style=3D=
"font-family:arial,sans-serif"><br></span></div><div><span style=3D"font-fa=
mily:arial,sans-serif">Bidirectional iterators aren&#39;t required to imple=
ment `</span><font face=3D"courier new, monospace">operator-</font><span st=
yle=3D"font-family:arial,sans-serif">`, so the second argument to `</span><=
font face=3D"courier new, monospace">std::move_backward</font><span style=
=3D"font-family:arial,sans-serif">` should be `</span><font face=3D"courier=
 new, monospace">std::prev(last, n)</font><span style=3D"font-family:arial,=
sans-serif">` instead of `</span><font face=3D"courier new, monospace">last=
 - n</font><span style=3D"font-family:arial,sans-serif">`.</span></div></di=
v></blockquote></div></div>

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On Wednesday, July 12, 2017 at 1:17:30 PM UTC-4, Alexander Zaitsev wrote:
>
> Yeah, you are right :)
>
> We should create the most general implementation and efficient
> implementation for any iterator type.
>
> Also we should decide about type of shifting: circular and/or logical
> shifting ( https://en.wikipedia.org/wiki/Circular_shift ).
>

Isn't circular shift just `std::rotate
<http://en.cppreference.com/w/cpp/algorithm/rotate>`?

And how would a logical shift work? Would it value-initialize all of the
empty entries? Would it take a value to copy into them? Would it leave them
in the moved-from state?

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<div dir=3D"ltr">On Wednesday, July 12, 2017 at 1:17:30 PM UTC-4, Alexander=
 Zaitsev wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;margin-=
left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"ltr=
">Yeah, you are right :)<div><br></div><div>We should create the most gener=
al implementation and efficient implementation for any iterator type.=C2=A0=
<br><br>Also we should decide about type of shifting: circular and/or logic=
al shifting ( <a href=3D"https://en.wikipedia.org/wiki/Circular_shift" targ=
et=3D"_blank" rel=3D"nofollow" onmousedown=3D"this.href=3D&#39;https://www.=
google.com/url?q\x3dhttps%3A%2F%2Fen.wikipedia.org%2Fwiki%2FCircular_shift\=
x26sa\x3dD\x26sntz\x3d1\x26usg\x3dAFQjCNGhhryP9byJ1Xvxy2Ow0ybk9f0MYw&#39;;r=
eturn true;" onclick=3D"this.href=3D&#39;https://www.google.com/url?q\x3dht=
tps%3A%2F%2Fen.wikipedia.org%2Fwiki%2FCircular_shift\x26sa\x3dD\x26sntz\x3d=
1\x26usg\x3dAFQjCNGhhryP9byJ1Xvxy2Ow0ybk9f0MYw&#39;;return true;">https://e=
n.wikipedia.org/wiki/<wbr>Circular_shift</a>=C2=A0).<br></div></div></block=
quote><div><br>Isn&#39;t circular shift just `<a href=3D"http://en.cpprefer=
ence.com/w/cpp/algorithm/rotate">std::rotate</a>`?<br><br>And how would a l=
ogical shift work? Would it value-initialize all of the empty entries? Woul=
d it take a value to copy into them? Would it leave them in the moved-from =
state?<br></div></div>

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Indeed, circular shift is just std::rotate.

For the 'logical' shift,  I was thinking leaving them in the moved-from
state. Filling them with some value would both 1) have a cost 2) not
necessarily be desired.
So I'm for the same behavior as the equivalent std::move[_backward], at
least by default.

It is possible to add an optional fill-in value parameter, if that's
something that would be deemed useful enough.

On Wed, Jul 12, 2017 at 9:46 PM, Nicol Bolas <jmckesson@gmail.com> wrote:

> On Wednesday, July 12, 2017 at 1:17:30 PM UTC-4, Alexander Zaitsev wrote:
>>
>> Yeah, you are right :)
>>
>> We should create the most general implementation and efficient
>> implementation for any iterator type.
>>
>> Also we should decide about type of shifting: circular and/or logical
>> shifting ( https://en.wikipedia.org/wiki/Circular_shift ).
>>
>
> Isn't circular shift just `std::rotate
> <http://en.cppreference.com/w/cpp/algorithm/rotate>`?
>
> And how would a logical shift work? Would it value-initialize all of the
> empty entries? Would it take a value to copy into them? Would it leave them
> in the moved-from state?
>

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<div dir=3D"ltr">Indeed, circular shift is just std::rotate.<div><br></div>=
<div>For the &#39;logical&#39; shift, =C2=A0I was thinking leaving them in =
the moved-from state. Filling them with some value would both 1) have a cos=
t 2) not necessarily be desired.=C2=A0</div><div>So I&#39;m for the same be=
havior as the equivalent std::move[_backward], at least by default.</div><d=
iv><br></div><div>It is possible to add an optional fill-in value parameter=
, if that&#39;s something that would be deemed useful enough.</div></div><d=
iv class=3D"gmail_extra"><br><div class=3D"gmail_quote">On Wed, Jul 12, 201=
7 at 9:46 PM, Nicol Bolas <span dir=3D"ltr">&lt;<a href=3D"mailto:jmckesson=
@gmail.com" target=3D"_blank">jmckesson@gmail.com</a>&gt;</span> wrote:<br>=
<blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1p=
x #ccc solid;padding-left:1ex"><div dir=3D"ltr"><span class=3D"">On Wednesd=
ay, July 12, 2017 at 1:17:30 PM UTC-4, Alexander Zaitsev wrote:<blockquote =
class=3D"gmail_quote" style=3D"margin:0;margin-left:0.8ex;border-left:1px #=
ccc solid;padding-left:1ex"><div dir=3D"ltr">Yeah, you are right :)<div><br=
></div><div>We should create the most general implementation and efficient =
implementation for any iterator type.=C2=A0<br><br>Also we should decide ab=
out type of shifting: circular and/or logical shifting ( <a href=3D"https:/=
/en.wikipedia.org/wiki/Circular_shift" rel=3D"nofollow" target=3D"_blank">h=
ttps://en.wikipedia.org/wiki/<wbr>Circular_shift</a>=C2=A0).<br></div></div=
></blockquote></span><div><br>Isn&#39;t circular shift just `<a href=3D"htt=
p://en.cppreference.com/w/cpp/algorithm/rotate" target=3D"_blank">std::rota=
te</a>`?<br><br>And how would a logical shift work? Would it value-initiali=
ze all of the empty entries? Would it take a value to copy into them? Would=
 it leave them in the moved-from state?<br></div></div></blockquote></div><=
br></div>

<p></p>

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On Wednesday, July 12, 2017 at 3:11:27 PM UTC-4, Dan Raviv wrote:
>
> Indeed, circular shift is just std::rotate.
>
> For the 'logical' shift,  I was thinking leaving them in the moved-from
> state. Filling them with some value would both 1) have a cost 2) not
> necessarily be desired.
>

But logical bitshifts do fill in a specific, well-defined value. So if this
is going to be separate from `move[_backward]`, then it ought to have the
behavior a user would expect.

So I'm for the same behavior as the equivalent std::move[_backward], at
> least by default.
>

> It is possible to add an optional fill-in value parameter, if that's
> something that would be deemed useful enough.
>

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<div dir=3D"ltr">On Wednesday, July 12, 2017 at 3:11:27 PM UTC-4, Dan Raviv=
 wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;margin-left: 0.=
8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"ltr">Indeed=
, circular shift is just std::rotate.<div><br></div><div>For the &#39;logic=
al&#39; shift, =C2=A0I was thinking leaving them in the moved-from state. F=
illing them with some value would both 1) have a cost 2) not necessarily be=
 desired.</div></div></blockquote><div><br>But logical bitshifts do fill in=
 a specific, well-defined value. So if this is going to be separate from `m=
ove[_backward]`, then it ought to have the behavior a user would expect.<br=
><br></div><blockquote class=3D"gmail_quote" style=3D"margin: 0;margin-left=
: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"ltr"><d=
iv>So I&#39;m for the same behavior as the equivalent std::move[_backward],=
 at least by default.</div></div></blockquote><div></div><blockquote class=
=3D"gmail_quote" style=3D"margin: 0;margin-left: 0.8ex;border-left: 1px #cc=
c solid;padding-left: 1ex;"><div dir=3D"ltr"><div><br></div><div>It is poss=
ible to add an optional fill-in value parameter, if that&#39;s something th=
at would be deemed useful enough.</div></div></blockquote><br></div>

<p></p>

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I guess I shouldn't have consented to use the term 'logical' shift which
Alexander used, I was just mirroring his term, but I see it just resulted
in confusion.
I'm discussing a shift of elements inside a generic container. It isn't
'logical' in any numeric sense.

Implementing a logical shift (say for vector<bool>), which would handle
positive and negative numbers correctly, is out of the scope for this
proposal idea, I think.



On Wed, Jul 12, 2017 at 10:51 PM, Nicol Bolas <jmckesson@gmail.com> wrote:

> On Wednesday, July 12, 2017 at 3:11:27 PM UTC-4, Dan Raviv wrote:
>>
>> Indeed, circular shift is just std::rotate.
>>
>> For the 'logical' shift,  I was thinking leaving them in the moved-from
>> state. Filling them with some value would both 1) have a cost 2) not
>> necessarily be desired.
>>
>
> But logical bitshifts do fill in a specific, well-defined value. So if
> this is going to be separate from `move[_backward]`, then it ought to have
> the behavior a user would expect.
>
> So I'm for the same behavior as the equivalent std::move[_backward], at
>> least by default.
>>
>
>> It is possible to add an optional fill-in value parameter, if that's
>> something that would be deemed useful enough.
>>
>
> --
> You received this message because you are subscribed to the Google Groups
> "ISO C++ Standard - Future Proposals" group.
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> isocpp.org/d/msgid/std-proposals/df32b9a3-9215-4517-
> 9bba-ba42654c55ee%40isocpp.org
> <https://groups.google.com/a/isocpp.org/d/msgid/std-proposals/df32b9a3-9215-4517-9bba-ba42654c55ee%40isocpp.org?utm_medium=email&utm_source=footer>
> .
>

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<div dir=3D"ltr"><div>I guess I shouldn&#39;t have consented to use the ter=
m &#39;logical&#39; shift which Alexander used, I was just mirroring his te=
rm, but I see it just resulted in confusion.</div><div>I&#39;m discussing a=
 shift of elements inside a generic container. It isn&#39;t &#39;logical&#3=
9; in any numeric sense.</div><div><br></div><div>Implementing a logical sh=
ift (say for vector&lt;bool&gt;), which would handle positive and negative =
numbers correctly, is out of the scope for this proposal idea, I think.</di=
v><div><br></div><div><br></div></div><div class=3D"gmail_extra"><br><div c=
lass=3D"gmail_quote">On Wed, Jul 12, 2017 at 10:51 PM, Nicol Bolas <span di=
r=3D"ltr">&lt;<a href=3D"mailto:jmckesson@gmail.com" target=3D"_blank">jmck=
esson@gmail.com</a>&gt;</span> wrote:<br><blockquote class=3D"gmail_quote" =
style=3D"margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><di=
v dir=3D"ltr"><span class=3D"">On Wednesday, July 12, 2017 at 3:11:27 PM UT=
C-4, Dan Raviv wrote:<blockquote class=3D"gmail_quote" style=3D"margin:0;ma=
rgin-left:0.8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"lt=
r">Indeed, circular shift is just std::rotate.<div><br></div><div>For the &=
#39;logical&#39; shift, =C2=A0I was thinking leaving them in the moved-from=
 state. Filling them with some value would both 1) have a cost 2) not neces=
sarily be desired.</div></div></blockquote></span><div><br>But logical bits=
hifts do fill in a specific, well-defined value. So if this is going to be =
separate from `move[_backward]`, then it ought to have the behavior a user =
would expect.<br><br></div><span class=3D""><blockquote class=3D"gmail_quot=
e" style=3D"margin:0;margin-left:0.8ex;border-left:1px #ccc solid;padding-l=
eft:1ex"><div dir=3D"ltr"><div>So I&#39;m for the same behavior as the equi=
valent std::move[_backward], at least by default.</div></div></blockquote><=
div></div><blockquote class=3D"gmail_quote" style=3D"margin:0;margin-left:0=
..8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr"><div><br=
></div><div>It is possible to add an optional fill-in value parameter, if t=
hat&#39;s something that would be deemed useful enough.</div></div></blockq=
uote><br></span></div><span class=3D"">

<p></p>

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b9a3-9215-4517-<wbr>9bba-ba42654c55ee%40isocpp.org</a><wbr>.<br>
</blockquote></div><br></div>

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Yes, i agree with your point of view. I meant this way - function with=20
optional fill parameter.

=D1=81=D1=80=D0=B5=D0=B4=D0=B0, 12 =D0=B8=D1=8E=D0=BB=D1=8F 2017 =D0=B3., 2=
2:11:27 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=B5=
=D0=BB=D1=8C Dan Raviv =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=BB:
>
> Indeed, circular shift is just std::rotate.
>
> For the 'logical' shift,  I was thinking leaving them in the moved-from=
=20
> state. Filling them with some value would both 1) have a cost 2) not=20
> necessarily be desired.=20
> So I'm for the same behavior as the equivalent std::move[_backward], at=
=20
> least by default.
>
> It is possible to add an optional fill-in value parameter, if that's=20
> something that would be deemed useful enough.
>
> On Wed, Jul 12, 2017 at 9:46 PM, Nicol Bolas <jmck...@gmail.com=20
> <javascript:>> wrote:
>
>> On Wednesday, July 12, 2017 at 1:17:30 PM UTC-4, Alexander Zaitsev wrote=
:
>>>
>>> Yeah, you are right :)
>>>
>>> We should create the most general implementation and efficient=20
>>> implementation for any iterator type.=20
>>>
>>> Also we should decide about type of shifting: circular and/or logical=
=20
>>> shifting ( https://en.wikipedia.org/wiki/Circular_shift ).
>>>
>>
>> Isn't circular shift just `std::rotate=20
>> <http://en.cppreference.com/w/cpp/algorithm/rotate>`?
>>
>> And how would a logical shift work? Would it value-initialize all of the=
=20
>> empty entries? Would it take a value to copy into them? Would it leave t=
hem=20
>> in the moved-from state?
>>
>
>

--=20
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<div dir=3D"ltr">Yes, i agree with your point of view. I meant this way - f=
unction with optional fill parameter.<br><br>=D1=81=D1=80=D0=B5=D0=B4=D0=B0=
, 12 =D0=B8=D1=8E=D0=BB=D1=8F 2017 =D0=B3., 22:11:27 UTC+3 =D0=BF=D0=BE=D0=
=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=B5=D0=BB=D1=8C Dan Raviv =D0=BD=
=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=BB:<blockquote class=3D"gmail_quote" styl=
e=3D"margin: 0;margin-left: 0.8ex;border-left: 1px #ccc solid;padding-left:=
 1ex;"><div dir=3D"ltr">Indeed, circular shift is just std::rotate.<div><br=
></div><div>For the &#39;logical&#39; shift, =C2=A0I was thinking leaving t=
hem in the moved-from state. Filling them with some value would both 1) hav=
e a cost 2) not necessarily be desired.=C2=A0</div><div>So I&#39;m for the =
same behavior as the equivalent std::move[_backward], at least by default.<=
/div><div><br></div><div>It is possible to add an optional fill-in value pa=
rameter, if that&#39;s something that would be deemed useful enough.</div><=
/div><div><br><div class=3D"gmail_quote">On Wed, Jul 12, 2017 at 9:46 PM, N=
icol Bolas <span dir=3D"ltr">&lt;<a href=3D"javascript:" target=3D"_blank" =
gdf-obfuscated-mailto=3D"dRWtPKElBgAJ" rel=3D"nofollow" onmousedown=3D"this=
..href=3D&#39;javascript:&#39;;return true;" onclick=3D"this.href=3D&#39;jav=
ascript:&#39;;return true;">jmck...@gmail.com</a>&gt;</span> wrote:<br><blo=
ckquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1px #c=
cc solid;padding-left:1ex"><div dir=3D"ltr"><span>On Wednesday, July 12, 20=
17 at 1:17:30 PM UTC-4, Alexander Zaitsev wrote:<blockquote class=3D"gmail_=
quote" style=3D"margin:0;margin-left:0.8ex;border-left:1px #ccc solid;paddi=
ng-left:1ex"><div dir=3D"ltr">Yeah, you are right :)<div><br></div><div>We =
should create the most general implementation and efficient implementation =
for any iterator type.=C2=A0<br><br>Also we should decide about type of shi=
fting: circular and/or logical shifting ( <a href=3D"https://en.wikipedia.o=
rg/wiki/Circular_shift" rel=3D"nofollow" target=3D"_blank" onmousedown=3D"t=
his.href=3D&#39;https://www.google.com/url?q\x3dhttps%3A%2F%2Fen.wikipedia.=
org%2Fwiki%2FCircular_shift\x26sa\x3dD\x26sntz\x3d1\x26usg\x3dAFQjCNGhhryP9=
byJ1Xvxy2Ow0ybk9f0MYw&#39;;return true;" onclick=3D"this.href=3D&#39;https:=
//www.google.com/url?q\x3dhttps%3A%2F%2Fen.wikipedia.org%2Fwiki%2FCircular_=
shift\x26sa\x3dD\x26sntz\x3d1\x26usg\x3dAFQjCNGhhryP9byJ1Xvxy2Ow0ybk9f0MYw&=
#39;;return true;">https://en.wikipedia.org/wiki/<wbr>Circular_shift</a>=C2=
=A0).<br></div></div></blockquote></span><div><br>Isn&#39;t circular shift =
just `<a href=3D"http://en.cppreference.com/w/cpp/algorithm/rotate" target=
=3D"_blank" rel=3D"nofollow" onmousedown=3D"this.href=3D&#39;http://www.goo=
gle.com/url?q\x3dhttp%3A%2F%2Fen.cppreference.com%2Fw%2Fcpp%2Falgorithm%2Fr=
otate\x26sa\x3dD\x26sntz\x3d1\x26usg\x3dAFQjCNGYb2gKbPU9UXJskeGPZjb9ddZgcQ&=
#39;;return true;" onclick=3D"this.href=3D&#39;http://www.google.com/url?q\=
x3dhttp%3A%2F%2Fen.cppreference.com%2Fw%2Fcpp%2Falgorithm%2Frotate\x26sa\x3=
dD\x26sntz\x3d1\x26usg\x3dAFQjCNGYb2gKbPU9UXJskeGPZjb9ddZgcQ&#39;;return tr=
ue;">std::rotate</a>`?<br><br>And how would a logical shift work? Would it =
value-initialize all of the empty entries? Would it take a value to copy in=
to them? Would it leave them in the moved-from state?<br></div></div></bloc=
kquote></div><br></div>
</blockquote></div>

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On Wednesday, July 12, 2017 at 2:53:19 AM UTC-7, d...@soundradix.com wrote:
>
> Hi,
>
> Would anyone be interested in adding std::shift to <algorithm>?=20
>
> It would be similar to both:
> - std::rotate, but without moving the head elements back to the tail. Thi=
s=20
> would allow a more efficient implementation and clearer semantics in case=
=20
> rotation is not needed as well as correctness in case rotation is undesir=
ed.
> - <algorithm>'s std::move/std::move_backward (depending on the shift=20
> direction).
>
> std::shift should probably accommodate both left and right shifts by one=
=20
> of:
> - giving it either begin() and end(), or rbegin() and rend(), similar to=
=20
> how std::rotate works for both left and right rotations. The advantage is=
=20
> compactness of the implementation.
> - allowing the shift count parameter to be either positive or negative.=
=20
> The advantage is compactness, though it might not be clear which directio=
n=20
> is which - to be consistent with rotate, positive integers should shift t=
o=20
> the left.
> - having std::shift_right and std::shift_left functions. The advantage is=
=20
> clarity when calling the methods, although the same argument could be mad=
e=20
> for having separate std::rotate_left and std::rotate_right instead of=20
> std::rotate, which we don't have.
>

std::rotate is actually just a rotation; it doesn't need "left" or "right"=
=20
qualification because they're 100% equivalent. Consider a classroom globe=
=20
with London in front, facing you. Now "rotate" the globe until Beijing is=
=20
in front. It doesn't matter if you rotate left or rotate right; the outcome=
=20
is exactly the same either way.
=20

> Here's a sample implementation of a shift to the right direction:
>
> template<class BidirIt>=20
> void shift_right(BidirIt first, BidirIt last, unsigned int n =3D 1)=20
> {=20
>     std::move_backward(first, last - n, last);=20
> }
>
> This demonstrates that while std::shift is implementable with=20
> std::move/std::move_backward,
> 1) It isn't immediately clear from the code (at least to my eyes) that=20
> this is a shift right, unless you are intimately familiar with=20
> std::move_backward.
> 2) Different calls, either to std::move or to std::move_backward, are=20
> required, depending on the shift direction.
>

If you're shifting the whole container's contents, you could use either of=
=20
these:
    std::move(ctr.rbegin() + n, ctr.rend(), ctr.rbegin());
    std::move_backward(ctr.begin(), ctr.end() - n, ctr.end())?
I don't currently see the use-case for this "shift just a piece of a=20
container" algorithm, I mean as distinct from std::move and=20
std::move_backward which already exist. Do you have a use-case?

Re naming, notice in passing that std::valarray::shift() exists, and=20
std::left_shift<T> and std::right_shift<T> do *not* exist but obviously=20
should. The name std::shift itself is indeed still available. I question=20
whether it should be used for this purpose, though.

=E2=80=93Arthur

--=20
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<div dir=3D"ltr">On Wednesday, July 12, 2017 at 2:53:19 AM UTC-7, d...@soun=
dradix.com wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;margi=
n-left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"l=
tr">Hi,<div><br></div><div>Would anyone be interested in adding std::shift =
to &lt;algorithm&gt;?=C2=A0</div><div><br></div><div>It would be similar to=
 both:</div><div>- std::rotate, but without moving the head elements back t=
o the tail. This would allow a more efficient implementation and clearer se=
mantics in case rotation is not needed as well as correctness in case rotat=
ion is undesired.</div><div>- &lt;algorithm&gt;&#39;s std::move/std::move_b=
ackward (depending on the shift direction).</div><div><br></div><div>std::s=
hift should probably accommodate both left and right shifts by one of:</div=
><div>- giving it either begin() and end(), or rbegin() and rend(), similar=
 to how std::rotate works for both left and right rotations. The advantage =
is compactness of the implementation.</div><div>- allowing the shift count =
parameter to be either positive or negative. The advantage is compactness, =
though it might not be clear which direction is which - to be consistent wi=
th rotate, positive integers should shift to the left.<br></div><div><div>-=
 having std::shift_right and std::shift_left functions. The advantage is cl=
arity when calling the methods, although the same argument could be made fo=
r having separate std::rotate_left and std::rotate_right instead of std::ro=
tate, which we don&#39;t have.</div></div></div></blockquote><div><br></div=
><div>std::rotate is actually just a rotation; it doesn&#39;t need &quot;le=
ft&quot; or &quot;right&quot; qualification because they&#39;re 100% equiva=
lent. Consider a classroom globe with London in front, facing you. Now &quo=
t;rotate&quot; the globe until Beijing is in front. It doesn&#39;t matter i=
f you rotate left or rotate right; the outcome is exactly the same either w=
ay.</div><div>=C2=A0</div><blockquote class=3D"gmail_quote" style=3D"margin=
: 0;margin-left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div=
 dir=3D"ltr"><div>Here&#39;s a sample implementation of a shift to the righ=
t direction:<br></div><br><div style=3D"background-color:rgb(250,250,250);b=
order:1px solid rgb(187,187,187);word-wrap:break-word"><code><div><span sty=
le=3D"color:#008">template</span><span style=3D"color:#660">&lt;</span><spa=
n style=3D"color:#008">class</span><span style=3D"color:#000"> </span><span=
 style=3D"color:#606">BidirIt</span><span style=3D"color:#660">&gt;</span><=
span style=3D"color:#000"> <br></span><span style=3D"color:#008">void</span=
><span style=3D"color:#000"> shift_right</span><span style=3D"color:#660">(=
</span><span style=3D"color:#606">BidirIt</span><span style=3D"color:#000">=
 first</span><span style=3D"color:#660">,</span><span style=3D"color:#000">=
 </span><span style=3D"color:#606">BidirIt</span><span style=3D"color:#000"=
> </span><span style=3D"color:#008">last</span><span style=3D"color:#660">,=
</span><span style=3D"color:#000"> </span><span style=3D"color:#008">unsign=
ed</span><span style=3D"color:#000"> </span><span style=3D"color:#008">int<=
/span><span style=3D"color:#000"> n </span><span style=3D"color:#660">=3D</=
span><span style=3D"color:#000"> </span><span style=3D"color:#066">1</span>=
<span style=3D"color:#660">)</span><span style=3D"color:#000"> <br></span><=
span style=3D"color:#660">{</span><span style=3D"color:#000"> <br>=C2=A0 =
=C2=A0 std</span><span style=3D"color:#660">::</span><span style=3D"color:#=
000">move_backward</span><span style=3D"color:#660">(</span><span style=3D"=
color:#000">first</span><span style=3D"color:#660">,</span><span style=3D"c=
olor:#000"> </span><span style=3D"color:#008">last</span><span style=3D"col=
or:#000"> </span><span style=3D"color:#660">-</span><span style=3D"color:#0=
00"> n</span><span style=3D"color:#660">,</span><span style=3D"color:#000">=
 </span><span style=3D"color:#008">last</span><span style=3D"color:#660">);=
</span><span style=3D"color:#000"> <br></span><span style=3D"color:#660">}<=
/span><span style=3D"color:#000"><br></span></div></code></div><div><br></d=
iv><div>This demonstrates that while std::shift is implementable with std::=
move/std::move_backward,</div><div>1) It isn&#39;t immediately clear from t=
he code (at least to my eyes) that this is a shift right, unless you are in=
timately familiar with std::move_backward.</div><div>2) Different calls, ei=
ther to std::move or to std::move_backward, are required, depending on the =
shift direction.</div></div></blockquote><div><br></div><div>If you&#39;re =
shifting the whole container&#39;s contents, you could use either of these:=
</div><div>=C2=A0 =C2=A0 std::move(ctr.rbegin() + n, ctr.rend(), ctr.rbegin=
());</div><div>=C2=A0 =C2=A0 std::move_backward(ctr.begin(), ctr.end() - n,=
 ctr.end())?</div><div>I don&#39;t currently see the use-case for this &quo=
t;shift just a piece of a container&quot; algorithm, I mean as distinct fro=
m std::move and std::move_backward which already exist. Do you have a use-c=
ase?</div><div><br></div><div>Re naming, notice in passing that std::valarr=
ay::shift() exists, and std::left_shift&lt;T&gt; and std::right_shift&lt;T&=
gt; do <i><b>not</b></i> exist but obviously should. The name std::shift it=
self is indeed still available. I question whether it should be used for th=
is purpose, though.</div><div><br></div><div>=E2=80=93Arthur</div></div>

<p></p>

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On Wednesday, July 12, 2017 at 7:47:05 PM UTC-4, Arthur O'Dwyer wrote:
>
> On Wednesday, July 12, 2017 at 2:53:19 AM UTC-7, d...@soundradix.com
> wrote:
>>
>> Hi,
>>
>> Would anyone be interested in adding std::shift to <algorithm>?
>>
>> It would be similar to both:
>> - std::rotate, but without moving the head elements back to the tail.
>> This would allow a more efficient implementation and clearer semantics in
>> case rotation is not needed as well as correctness in case rotation is
>> undesired.
>> - <algorithm>'s std::move/std::move_backward (depending on the shift
>> direction).
>>
>> std::shift should probably accommodate both left and right shifts by one
>> of:
>> - giving it either begin() and end(), or rbegin() and rend(), similar to
>> how std::rotate works for both left and right rotations. The advantage is
>> compactness of the implementation.
>> - allowing the shift count parameter to be either positive or negative.
>> The advantage is compactness, though it might not be clear which direction
>> is which - to be consistent with rotate, positive integers should shift to
>> the left.
>> - having std::shift_right and std::shift_left functions. The advantage is
>> clarity when calling the methods, although the same argument could be made
>> for having separate std::rotate_left and std::rotate_right instead of
>> std::rotate, which we don't have.
>>
>
> std::rotate is actually just a rotation; it doesn't need "left" or "right"
> qualification because they're 100% equivalent. Consider a classroom globe
> with London in front, facing you. Now "rotate" the globe until Beijing is
> in front. It doesn't matter if you rotate left or rotate right; the outcome
> is exactly the same either way.
>
>
>> Here's a sample implementation of a shift to the right direction:
>>
>> template<class BidirIt>
>> void shift_right(BidirIt first, BidirIt last, unsigned int n = 1)
>> {
>>     std::move_backward(first, last - n, last);
>> }
>>
>> This demonstrates that while std::shift is implementable with
>> std::move/std::move_backward,
>> 1) It isn't immediately clear from the code (at least to my eyes) that
>> this is a shift right, unless you are intimately familiar with
>> std::move_backward.
>> 2) Different calls, either to std::move or to std::move_backward, are
>> required, depending on the shift direction.
>>
>
> If you're shifting the whole container's contents, you could use either of
> these:
>     std::move(ctr.rbegin() + n, ctr.rend(), ctr.rbegin());
>     std::move_backward(ctr.begin(), ctr.end() - n, ctr.end())?
> I don't currently see the use-case for this "shift just a piece of a
> container" algorithm, I mean as distinct from std::move and
> std::move_backward which already exist. Do you have a use-case?
>

The use-case would be anytime you'd want to use the code you just wrote.
When you have a range and N, and you want to do a shift N units in that
direction.

The point of having it is one of clarification and user expectations. Yes,
you can use `move` and `move_backward` to accomplish a shift. But consider
the two function calls:

//A
std::shift(rng.begin(), rng.end(), N);

//B
auto rrng = std::make_reverse_range(rng);
std::move(rrng.begin() + N, rrng.end(), rrng.begin());

A and B both do the same thing. But it's a *lot easier* to figure out what
the code is actually accomplishing from looking at A than B.

B gets even more obtuse confusing in a range-based world:

//A
std::shift(rng, N);

//B
auto rrng = std::make_reverse_range(rng);
std::move(std::make_range(rrng.begin + N, rrng.end()), rrng.begin());

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<div dir=3D"ltr">On Wednesday, July 12, 2017 at 7:47:05 PM UTC-4, Arthur O&=
#39;Dwyer wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;margin=
-left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"lt=
r">On Wednesday, July 12, 2017 at 2:53:19 AM UTC-7, <a>d...@soundradix.com<=
/a> wrote:<blockquote class=3D"gmail_quote" style=3D"margin:0;margin-left:0=
..8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">Hi,<div>=
<br></div><div>Would anyone be interested in adding std::shift to &lt;algor=
ithm&gt;?=C2=A0</div><div><br></div><div>It would be similar to both:</div>=
<div>- std::rotate, but without moving the head elements back to the tail. =
This would allow a more efficient implementation and clearer semantics in c=
ase rotation is not needed as well as correctness in case rotation is undes=
ired.</div><div>- &lt;algorithm&gt;&#39;s std::move/std::move_backward (dep=
ending on the shift direction).</div><div><br></div><div>std::shift should =
probably accommodate both left and right shifts by one of:</div><div>- givi=
ng it either begin() and end(), or rbegin() and rend(), similar to how std:=
:rotate works for both left and right rotations. The advantage is compactne=
ss of the implementation.</div><div>- allowing the shift count parameter to=
 be either positive or negative. The advantage is compactness, though it mi=
ght not be clear which direction is which - to be consistent with rotate, p=
ositive integers should shift to the left.<br></div><div><div>- having std:=
:shift_right and std::shift_left functions. The advantage is clarity when c=
alling the methods, although the same argument could be made for having sep=
arate std::rotate_left and std::rotate_right instead of std::rotate, which =
we don&#39;t have.</div></div></div></blockquote><div><br></div><div>std::r=
otate is actually just a rotation; it doesn&#39;t need &quot;left&quot; or =
&quot;right&quot; qualification because they&#39;re 100% equivalent. Consid=
er a classroom globe with London in front, facing you. Now &quot;rotate&quo=
t; the globe until Beijing is in front. It doesn&#39;t matter if you rotate=
 left or rotate right; the outcome is exactly the same either way.</div><di=
v>=C2=A0</div><blockquote class=3D"gmail_quote" style=3D"margin:0;margin-le=
ft:0.8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr"><div=
>Here&#39;s a sample implementation of a shift to the right direction:<br><=
/div><br><div style=3D"background-color:rgb(250,250,250);border:1px solid r=
gb(187,187,187);word-wrap:break-word"><code><div><span style=3D"color:#008"=
>template</span><span style=3D"color:#660">&lt;</span><span style=3D"color:=
#008">class</span><span style=3D"color:#000"> </span><span style=3D"color:#=
606">BidirIt</span><span style=3D"color:#660">&gt;</span><span style=3D"col=
or:#000"> <br></span><span style=3D"color:#008">void</span><span style=3D"c=
olor:#000"> shift_right</span><span style=3D"color:#660">(</span><span styl=
e=3D"color:#606">BidirIt</span><span style=3D"color:#000"> first</span><spa=
n style=3D"color:#660">,</span><span style=3D"color:#000"> </span><span sty=
le=3D"color:#606">BidirIt</span><span style=3D"color:#000"> </span><span st=
yle=3D"color:#008">last</span><span style=3D"color:#660">,</span><span styl=
e=3D"color:#000"> </span><span style=3D"color:#008">unsigned</span><span st=
yle=3D"color:#000"> </span><span style=3D"color:#008">int</span><span style=
=3D"color:#000"> n </span><span style=3D"color:#660">=3D</span><span style=
=3D"color:#000"> </span><span style=3D"color:#066">1</span><span style=3D"c=
olor:#660">)</span><span style=3D"color:#000"> <br></span><span style=3D"co=
lor:#660">{</span><span style=3D"color:#000"> <br>=C2=A0 =C2=A0 std</span><=
span style=3D"color:#660">::</span><span style=3D"color:#000">move_backward=
</span><span style=3D"color:#660">(</span><span style=3D"color:#000">first<=
/span><span style=3D"color:#660">,</span><span style=3D"color:#000"> </span=
><span style=3D"color:#008">last</span><span style=3D"color:#000"> </span><=
span style=3D"color:#660">-</span><span style=3D"color:#000"> n</span><span=
 style=3D"color:#660">,</span><span style=3D"color:#000"> </span><span styl=
e=3D"color:#008">last</span><span style=3D"color:#660">);</span><span style=
=3D"color:#000"> <br></span><span style=3D"color:#660">}</span><span style=
=3D"color:#000"><br></span></div></code></div><div><br></div><div>This demo=
nstrates that while std::shift is implementable with std::move/std::move_ba=
ckward,</div><div>1) It isn&#39;t immediately clear from the code (at least=
 to my eyes) that this is a shift right, unless you are intimately familiar=
 with std::move_backward.</div><div>2) Different calls, either to std::move=
 or to std::move_backward, are required, depending on the shift direction.<=
/div></div></blockquote><div><br></div><div>If you&#39;re shifting the whol=
e container&#39;s contents, you could use either of these:</div><div>=C2=A0=
 =C2=A0 std::move(ctr.rbegin() + n, ctr.rend(), ctr.rbegin());</div><div>=
=C2=A0 =C2=A0 std::move_backward(ctr.begin()<wbr>, ctr.end() - n, ctr.end()=
)?</div><div>I don&#39;t currently see the use-case for this &quot;shift ju=
st a piece of a container&quot; algorithm, I mean as distinct from std::mov=
e and std::move_backward which already exist. Do you have a use-case?</div>=
</div></blockquote><div><br>The use-case would be anytime you&#39;d want to=
 use the code you just wrote. When you have a range and N, and you want to =
do a shift N units in that direction.<br><br>The point of having it is one =
of clarification and user expectations. Yes, you can use `move` and `move_b=
ackward` to accomplish a shift. But consider the two function calls:<br><br=
><div style=3D"background-color: rgb(250, 250, 250); border-color: rgb(187,=
 187, 187); border-style: solid; border-width: 1px; overflow-wrap: break-wo=
rd;" class=3D"prettyprint"><code class=3D"prettyprint"><div class=3D"subpre=
ttyprint"><span style=3D"color: #800;" class=3D"styled-by-prettify">//A</sp=
an><span style=3D"color: #000;" class=3D"styled-by-prettify"><br>std</span>=
<span style=3D"color: #660;" class=3D"styled-by-prettify">::</span><span st=
yle=3D"color: #000;" class=3D"styled-by-prettify">shift</span><span style=
=3D"color: #660;" class=3D"styled-by-prettify">(</span><span style=3D"color=
: #000;" class=3D"styled-by-prettify">rng</span><span style=3D"color: #660;=
" class=3D"styled-by-prettify">.</span><span style=3D"color: #008;" class=
=3D"styled-by-prettify">begin</span><span style=3D"color: #660;" class=3D"s=
tyled-by-prettify">(),</span><span style=3D"color: #000;" class=3D"styled-b=
y-prettify"> rng</span><span style=3D"color: #660;" class=3D"styled-by-pret=
tify">.</span><span style=3D"color: #008;" class=3D"styled-by-prettify">end=
</span><span style=3D"color: #660;" class=3D"styled-by-prettify">(),</span>=
<span style=3D"color: #000;" class=3D"styled-by-prettify"> N</span><span st=
yle=3D"color: #660;" class=3D"styled-by-prettify">);</span><span style=3D"c=
olor: #000;" class=3D"styled-by-prettify"><br><br></span><span style=3D"col=
or: #800;" class=3D"styled-by-prettify">//B</span><span style=3D"color: #00=
0;" class=3D"styled-by-prettify"><br></span><span style=3D"color: #008;" cl=
ass=3D"styled-by-prettify">auto</span><span style=3D"color: #000;" class=3D=
"styled-by-prettify"> rrng </span><span style=3D"color: #660;" class=3D"sty=
led-by-prettify">=3D</span><span style=3D"color: #000;" class=3D"styled-by-=
prettify"> std</span><span style=3D"color: #660;" class=3D"styled-by-pretti=
fy">::</span><span style=3D"color: #000;" class=3D"styled-by-prettify">make=
_reverse_range</span><span style=3D"color: #660;" class=3D"styled-by-pretti=
fy">(</span><span style=3D"color: #000;" class=3D"styled-by-prettify">rng</=
span><span style=3D"color: #660;" class=3D"styled-by-prettify">);</span><sp=
an style=3D"color: #000;" class=3D"styled-by-prettify"><br>std</span><span =
style=3D"color: #660;" class=3D"styled-by-prettify">::</span><span style=3D=
"color: #000;" class=3D"styled-by-prettify">move</span><span style=3D"color=
: #660;" class=3D"styled-by-prettify">(</span><span style=3D"color: #000;" =
class=3D"styled-by-prettify">rrng</span><span style=3D"color: #660;" class=
=3D"styled-by-prettify">.</span><span style=3D"color: #008;" class=3D"style=
d-by-prettify">begin</span><span style=3D"color: #660;" class=3D"styled-by-=
prettify">()</span><span style=3D"color: #000;" class=3D"styled-by-prettify=
"> </span><span style=3D"color: #660;" class=3D"styled-by-prettify">+</span=
><span style=3D"color: #000;" class=3D"styled-by-prettify"> N</span><span s=
tyle=3D"color: #660;" class=3D"styled-by-prettify">,</span><span style=3D"c=
olor: #000;" class=3D"styled-by-prettify"> rrng</span><span style=3D"color:=
 #660;" class=3D"styled-by-prettify">.</span><span style=3D"color: #008;" c=
lass=3D"styled-by-prettify">end</span><span style=3D"color: #660;" class=3D=
"styled-by-prettify">(),</span><span style=3D"color: #000;" class=3D"styled=
-by-prettify"> rrng</span><span style=3D"color: #660;" class=3D"styled-by-p=
rettify">.</span><span style=3D"color: #008;" class=3D"styled-by-prettify">=
begin</span><span style=3D"color: #660;" class=3D"styled-by-prettify">());<=
/span></div></code></div><br>A and B both do the same thing. But it&#39;s a=
 <i>lot easier</i> to figure out what the code is actually accomplishing fr=
om looking at A than B.<br><br>B gets even more obtuse confusing in a range=
-based world:<br><br><div style=3D"background-color: rgb(250, 250, 250); bo=
rder-color: rgb(187, 187, 187); border-style: solid; border-width: 1px; ove=
rflow-wrap: break-word;" class=3D"prettyprint"><code class=3D"prettyprint">=
<div class=3D"subprettyprint"><span style=3D"color: #800;" class=3D"styled-=
by-prettify">//A</span><span style=3D"color: #000;" class=3D"styled-by-pret=
tify"><br>std</span><span style=3D"color: #660;" class=3D"styled-by-prettif=
y">::</span><span style=3D"color: #000;" class=3D"styled-by-prettify">shift=
</span><span style=3D"color: #660;" class=3D"styled-by-prettify">(</span><s=
pan style=3D"color: #000;" class=3D"styled-by-prettify">rng</span><span sty=
le=3D"color: #660;" class=3D"styled-by-prettify">,</span><span style=3D"col=
or: #000;" class=3D"styled-by-prettify"> N</span><span style=3D"color: #660=
;" class=3D"styled-by-prettify">);</span><span style=3D"color: #000;" class=
=3D"styled-by-prettify"><br><br></span><span style=3D"color: #800;" class=
=3D"styled-by-prettify">//B</span><span style=3D"color: #000;" class=3D"sty=
led-by-prettify"><br></span><span style=3D"color: #008;" class=3D"styled-by=
-prettify">auto</span><span style=3D"color: #000;" class=3D"styled-by-prett=
ify"> rrng </span><span style=3D"color: #660;" class=3D"styled-by-prettify"=
>=3D</span><span style=3D"color: #000;" class=3D"styled-by-prettify"> std</=
span><span style=3D"color: #660;" class=3D"styled-by-prettify">::</span><sp=
an style=3D"color: #000;" class=3D"styled-by-prettify">make_reverse_range</=
span><span style=3D"color: #660;" class=3D"styled-by-prettify">(</span><spa=
n style=3D"color: #000;" class=3D"styled-by-prettify">rng</span><span style=
=3D"color: #660;" class=3D"styled-by-prettify">);</span><span style=3D"colo=
r: #000;" class=3D"styled-by-prettify"><br>std</span><span style=3D"color: =
#660;" class=3D"styled-by-prettify">::</span><span style=3D"color: #000;" c=
lass=3D"styled-by-prettify">move</span><span style=3D"color: #660;" class=
=3D"styled-by-prettify">(</span><span style=3D"color: #000;" class=3D"style=
d-by-prettify">std</span><span style=3D"color: #660;" class=3D"styled-by-pr=
ettify">::</span><span style=3D"color: #000;" class=3D"styled-by-prettify">=
make_range</span><span style=3D"color: #660;" class=3D"styled-by-prettify">=
(</span><span style=3D"color: #000;" class=3D"styled-by-prettify">rrng</spa=
n><span style=3D"color: #660;" class=3D"styled-by-prettify">.</span><span s=
tyle=3D"color: #008;" class=3D"styled-by-prettify">begin</span><span style=
=3D"color: #000;" class=3D"styled-by-prettify"> </span><span style=3D"color=
: #660;" class=3D"styled-by-prettify">+</span><span style=3D"color: #000;" =
class=3D"styled-by-prettify"> N</span><span style=3D"color: #660;" class=3D=
"styled-by-prettify">,</span><span style=3D"color: #000;" class=3D"styled-b=
y-prettify"> rrng</span><span style=3D"color: #660;" class=3D"styled-by-pre=
ttify">.</span><span style=3D"color: #008;" class=3D"styled-by-prettify">en=
d</span><span style=3D"color: #660;" class=3D"styled-by-prettify">()),</spa=
n><span style=3D"color: #000;" class=3D"styled-by-prettify"> rrng</span><sp=
an style=3D"color: #660;" class=3D"styled-by-prettify">.</span><span style=
=3D"color: #008;" class=3D"styled-by-prettify">begin</span><span style=3D"c=
olor: #660;" class=3D"styled-by-prettify">());</span></div></code></div></d=
iv></div>

<p></p>

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Thanks for phrasing the motivation so well Nicol.

Arthur, regarding specific use cases, any algorithm doing time series analy=
sis (e.g. temperature the last 20 days) could use this.

(A cyclical buffer is an alternative, but one which isn't always preferrabl=
e.)

> On 13 Jul 2017, at 4:43, Nicol Bolas <jmckesson@gmail.com> wrote:
>=20
>> On Wednesday, July 12, 2017 at 7:47:05 PM UTC-4, Arthur O'Dwyer wrote:
>>> On Wednesday, July 12, 2017 at 2:53:19 AM UTC-7, d...@soundradix.com wr=
ote:
>>> Hi,
>>>=20
>>> Would anyone be interested in adding std::shift to <algorithm>?=20
>>>=20
>>> It would be similar to both:
>>> - std::rotate, but without moving the head elements back to the tail. T=
his would allow a more efficient implementation and clearer semantics in ca=
se rotation is not needed as well as correctness in case rotation is undesi=
red.
>>> - <algorithm>'s std::move/std::move_backward (depending on the shift di=
rection).
>>>=20
>>> std::shift should probably accommodate both left and right shifts by on=
e of:
>>> - giving it either begin() and end(), or rbegin() and rend(), similar t=
o how std::rotate works for both left and right rotations. The advantage is=
 compactness of the implementation.
>>> - allowing the shift count parameter to be either positive or negative.=
 The advantage is compactness, though it might not be clear which direction=
 is which - to be consistent with rotate, positive integers should shift to=
 the left.
>>> - having std::shift_right and std::shift_left functions. The advantage =
is clarity when calling the methods, although the same argument could be ma=
de for having separate std::rotate_left and std::rotate_right instead of st=
d::rotate, which we don't have.
>>=20
>> std::rotate is actually just a rotation; it doesn't need "left" or "righ=
t" qualification because they're 100% equivalent. Consider a classroom glob=
e with London in front, facing you. Now "rotate" the globe until Beijing is=
 in front. It doesn't matter if you rotate left or rotate right; the outcom=
e is exactly the same either way.
>> =20
>>> Here's a sample implementation of a shift to the right direction:
>>>=20
>>> template<class BidirIt>=20
>>> void shift_right(BidirIt first, BidirIt last, unsigned int n =3D 1)=20
>>> {=20
>>>     std::move_backward(first, last - n, last);=20
>>> }
>>>=20
>>> This demonstrates that while std::shift is implementable with std::move=
/std::move_backward,
>>> 1) It isn't immediately clear from the code (at least to my eyes) that =
this is a shift right, unless you are intimately familiar with std::move_ba=
ckward.
>>> 2) Different calls, either to std::move or to std::move_backward, are r=
equired, depending on the shift direction.
>>=20
>> If you're shifting the whole container's contents, you could use either =
of these:
>>     std::move(ctr.rbegin() + n, ctr.rend(), ctr.rbegin());
>>     std::move_backward(ctr.begin(), ctr.end() - n, ctr.end())?
>> I don't currently see the use-case for this "shift just a piece of a con=
tainer" algorithm, I mean as distinct from std::move and std::move_backward=
 which already exist. Do you have a use-case?
>=20
> The use-case would be anytime you'd want to use the code you just wrote. =
When you have a range and N, and you want to do a shift N units in that dir=
ection.
>=20
> The point of having it is one of clarification and user expectations. Yes=
, you can use `move` and `move_backward` to accomplish a shift. But conside=
r the two function calls:
>=20
> //A
> std::shift(rng.begin(), rng.end(), N);
>=20
> //B
> auto rrng =3D std::make_reverse_range(rng);
> std::move(rrng.begin() + N, rrng.end(), rrng.begin());
>=20
> A and B both do the same thing. But it's a lot easier to figure out what =
the code is actually accomplishing from looking at A than B.
>=20
> B gets even more obtuse confusing in a range-based world:
>=20
> //A
> std::shift(rng, N);
>=20
> //B
> auto rrng =3D std::make_reverse_range(rng);
> std::move(std::make_range(rrng.begin + N, rrng.end()), rrng.begin());
> --=20
> You received this message because you are subscribed to the Google Groups=
 "ISO C++ Standard - Future Proposals" group.
> To unsubscribe from this group and stop receiving emails from it, send an=
 email to std-proposals+unsubscribe@isocpp.org.
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pp.org/d/msgid/std-proposals/c722a201-5c9c-4ac5-a1bd-e50beb6d7860%40isocpp.=
org.

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<html><head><meta http-equiv=3D"content-type" content=3D"text/html; charset=
=3Dutf-8"></head><body dir=3D"auto"><div></div><div>Thanks for phrasing the=
 motivation so well Nicol.</div><div><br></div><div>Arthur, regarding speci=
fic use cases, any algorithm doing time series analysis (e.g. temperature t=
he last 20 days) could use this.</div><div><br></div><div>(A cyclical buffe=
r is an alternative, but one which isn't always preferrable.)</div><div><br=
>On 13 Jul 2017, at 4:43, Nicol Bolas &lt;<a href=3D"mailto:jmckesson@gmail=
..com">jmckesson@gmail.com</a>&gt; wrote:<br><br></div><blockquote type=3D"c=
ite"><div><div dir=3D"ltr">On Wednesday, July 12, 2017 at 7:47:05 PM UTC-4,=
 Arthur O'Dwyer wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;=
margin-left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=
=3D"ltr">On Wednesday, July 12, 2017 at 2:53:19 AM UTC-7, <a>d...@soundradi=
x.com</a> wrote:<blockquote class=3D"gmail_quote" style=3D"margin:0;margin-=
left:0.8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">Hi=
,<div><br></div><div>Would anyone be interested in adding std::shift to &lt=
;algorithm&gt;?&nbsp;</div><div><br></div><div>It would be similar to both:=
</div><div>- std::rotate, but without moving the head elements back to the =
tail. This would allow a more efficient implementation and clearer semantic=
s in case rotation is not needed as well as correctness in case rotation is=
 undesired.</div><div>- &lt;algorithm&gt;'s std::move/std::move_backward (d=
epending on the shift direction).</div><div><br></div><div>std::shift shoul=
d probably accommodate both left and right shifts by one of:</div><div>- gi=
ving it either begin() and end(), or rbegin() and rend(), similar to how st=
d::rotate works for both left and right rotations. The advantage is compact=
ness of the implementation.</div><div>- allowing the shift count parameter =
to be either positive or negative. The advantage is compactness, though it =
might not be clear which direction is which - to be consistent with rotate,=
 positive integers should shift to the left.<br></div><div><div>- having st=
d::shift_right and std::shift_left functions. The advantage is clarity when=
 calling the methods, although the same argument could be made for having s=
eparate std::rotate_left and std::rotate_right instead of std::rotate, whic=
h we don't have.</div></div></div></blockquote><div><br></div><div>std::rot=
ate is actually just a rotation; it doesn't need "left" or "right" qualific=
ation because they're 100% equivalent. Consider a classroom globe with Lond=
on in front, facing you. Now "rotate" the globe until Beijing is in front. =
It doesn't matter if you rotate left or rotate right; the outcome is exactl=
y the same either way.</div><div>&nbsp;</div><blockquote class=3D"gmail_quo=
te" style=3D"margin:0;margin-left:0.8ex;border-left:1px #ccc solid;padding-=
left:1ex"><div dir=3D"ltr"><div>Here's a sample implementation of a shift t=
o the right direction:<br></div><br><div style=3D"background-color:rgb(250,=
250,250);border:1px solid rgb(187,187,187);word-wrap:break-word"><code><div=
><span style=3D"color:#008">template</span><span style=3D"color:#660">&lt;<=
/span><span style=3D"color:#008">class</span><span style=3D"color:#000"> </=
span><span style=3D"color:#606">BidirIt</span><span style=3D"color:#660">&g=
t;</span><span style=3D"color:#000"> <br></span><span style=3D"color:#008">=
void</span><span style=3D"color:#000"> shift_right</span><span style=3D"col=
or:#660">(</span><span style=3D"color:#606">BidirIt</span><span style=3D"co=
lor:#000"> first</span><span style=3D"color:#660">,</span><span style=3D"co=
lor:#000"> </span><span style=3D"color:#606">BidirIt</span><span style=3D"c=
olor:#000"> </span><span style=3D"color:#008">last</span><span style=3D"col=
or:#660">,</span><span style=3D"color:#000"> </span><span style=3D"color:#0=
08">unsigned</span><span style=3D"color:#000"> </span><span style=3D"color:=
#008">int</span><span style=3D"color:#000"> n </span><span style=3D"color:#=
660">=3D</span><span style=3D"color:#000"> </span><span style=3D"color:#066=
">1</span><span style=3D"color:#660">)</span><span style=3D"color:#000"> <b=
r></span><span style=3D"color:#660">{</span><span style=3D"color:#000"> <br=
>&nbsp; &nbsp; std</span><span style=3D"color:#660">::</span><span style=3D=
"color:#000">move_backward</span><span style=3D"color:#660">(</span><span s=
tyle=3D"color:#000">first</span><span style=3D"color:#660">,</span><span st=
yle=3D"color:#000"> </span><span style=3D"color:#008">last</span><span styl=
e=3D"color:#000"> </span><span style=3D"color:#660">-</span><span style=3D"=
color:#000"> n</span><span style=3D"color:#660">,</span><span style=3D"colo=
r:#000"> </span><span style=3D"color:#008">last</span><span style=3D"color:=
#660">);</span><span style=3D"color:#000"> <br></span><span style=3D"color:=
#660">}</span><span style=3D"color:#000"><br></span></div></code></div><div=
><br></div><div>This demonstrates that while std::shift is implementable wi=
th std::move/std::move_backward,</div><div>1) It isn't immediately clear fr=
om the code (at least to my eyes) that this is a shift right, unless you ar=
e intimately familiar with std::move_backward.</div><div>2) Different calls=
, either to std::move or to std::move_backward, are required, depending on =
the shift direction.</div></div></blockquote><div><br></div><div>If you're =
shifting the whole container's contents, you could use either of these:</di=
v><div>&nbsp; &nbsp; std::move(ctr.rbegin() + n, ctr.rend(), ctr.rbegin());=
</div><div>&nbsp; &nbsp; std::move_backward(ctr.begin()<wbr>, ctr.end() - n=
, ctr.end())?</div><div>I don't currently see the use-case for this "shift =
just a piece of a container" algorithm, I mean as distinct from std::move a=
nd std::move_backward which already exist. Do you have a use-case?</div></d=
iv></blockquote><div><br>The use-case would be anytime you'd want to use th=
e code you just wrote. When you have a range and N, and you want to do a sh=
ift N units in that direction.<br><br>The point of having it is one of clar=
ification and user expectations. Yes, you can use `move` and `move_backward=
` to accomplish a shift. But consider the two function calls:<br><br><div s=
tyle=3D"background-color: rgb(250, 250, 250); border-color: rgb(187, 187, 1=
87); border-style: solid; border-width: 1px; overflow-wrap: break-word;" cl=
ass=3D"prettyprint"><code class=3D"prettyprint"><div class=3D"subprettyprin=
t"><span style=3D"color: #800;" class=3D"styled-by-prettify">//A</span><spa=
n style=3D"color: #000;" class=3D"styled-by-prettify"><br>std</span><span s=
tyle=3D"color: #660;" class=3D"styled-by-prettify">::</span><span style=3D"=
color: #000;" class=3D"styled-by-prettify">shift</span><span style=3D"color=
: #660;" class=3D"styled-by-prettify">(</span><span style=3D"color: #000;" =
class=3D"styled-by-prettify">rng</span><span style=3D"color: #660;" class=
=3D"styled-by-prettify">.</span><span style=3D"color: #008;" class=3D"style=
d-by-prettify">begin</span><span style=3D"color: #660;" class=3D"styled-by-=
prettify">(),</span><span style=3D"color: #000;" class=3D"styled-by-prettif=
y"> rng</span><span style=3D"color: #660;" class=3D"styled-by-prettify">.</=
span><span style=3D"color: #008;" class=3D"styled-by-prettify">end</span><s=
pan style=3D"color: #660;" class=3D"styled-by-prettify">(),</span><span sty=
le=3D"color: #000;" class=3D"styled-by-prettify"> N</span><span style=3D"co=
lor: #660;" class=3D"styled-by-prettify">);</span><span style=3D"color: #00=
0;" class=3D"styled-by-prettify"><br><br></span><span style=3D"color: #800;=
" class=3D"styled-by-prettify">//B</span><span style=3D"color: #000;" class=
=3D"styled-by-prettify"><br></span><span style=3D"color: #008;" class=3D"st=
yled-by-prettify">auto</span><span style=3D"color: #000;" class=3D"styled-b=
y-prettify"> rrng </span><span style=3D"color: #660;" class=3D"styled-by-pr=
ettify">=3D</span><span style=3D"color: #000;" class=3D"styled-by-prettify"=
> std</span><span style=3D"color: #660;" class=3D"styled-by-prettify">::</s=
pan><span style=3D"color: #000;" class=3D"styled-by-prettify">make_reverse_=
range</span><span style=3D"color: #660;" class=3D"styled-by-prettify">(</sp=
an><span style=3D"color: #000;" class=3D"styled-by-prettify">rng</span><spa=
n style=3D"color: #660;" class=3D"styled-by-prettify">);</span><span style=
=3D"color: #000;" class=3D"styled-by-prettify"><br>std</span><span style=3D=
"color: #660;" class=3D"styled-by-prettify">::</span><span style=3D"color: =
#000;" class=3D"styled-by-prettify">move</span><span style=3D"color: #660;"=
 class=3D"styled-by-prettify">(</span><span style=3D"color: #000;" class=3D=
"styled-by-prettify">rrng</span><span style=3D"color: #660;" class=3D"style=
d-by-prettify">.</span><span style=3D"color: #008;" class=3D"styled-by-pret=
tify">begin</span><span style=3D"color: #660;" class=3D"styled-by-prettify"=
>()</span><span style=3D"color: #000;" class=3D"styled-by-prettify"> </span=
><span style=3D"color: #660;" class=3D"styled-by-prettify">+</span><span st=
yle=3D"color: #000;" class=3D"styled-by-prettify"> N</span><span style=3D"c=
olor: #660;" class=3D"styled-by-prettify">,</span><span style=3D"color: #00=
0;" class=3D"styled-by-prettify"> rrng</span><span style=3D"color: #660;" c=
lass=3D"styled-by-prettify">.</span><span style=3D"color: #008;" class=3D"s=
tyled-by-prettify">end</span><span style=3D"color: #660;" class=3D"styled-b=
y-prettify">(),</span><span style=3D"color: #000;" class=3D"styled-by-prett=
ify"> rrng</span><span style=3D"color: #660;" class=3D"styled-by-prettify">=
..</span><span style=3D"color: #008;" class=3D"styled-by-prettify">begin</sp=
an><span style=3D"color: #660;" class=3D"styled-by-prettify">());</span></d=
iv></code></div><br>A and B both do the same thing. But it's a <i>lot easie=
r</i> to figure out what the code is actually accomplishing from looking at=
 A than B.<br><br>B gets even more obtuse confusing in a range-based world:=
<br><br><div style=3D"background-color: rgb(250, 250, 250); border-color: r=
gb(187, 187, 187); border-style: solid; border-width: 1px; overflow-wrap: b=
reak-word;" class=3D"prettyprint"><code class=3D"prettyprint"><div class=3D=
"subprettyprint"><span style=3D"color: #800;" class=3D"styled-by-prettify">=
//A</span><span style=3D"color: #000;" class=3D"styled-by-prettify"><br>std=
</span><span style=3D"color: #660;" class=3D"styled-by-prettify">::</span><=
span style=3D"color: #000;" class=3D"styled-by-prettify">shift</span><span =
style=3D"color: #660;" class=3D"styled-by-prettify">(</span><span style=3D"=
color: #000;" class=3D"styled-by-prettify">rng</span><span style=3D"color: =
#660;" class=3D"styled-by-prettify">,</span><span style=3D"color: #000;" cl=
ass=3D"styled-by-prettify"> N</span><span style=3D"color: #660;" class=3D"s=
tyled-by-prettify">);</span><span style=3D"color: #000;" class=3D"styled-by=
-prettify"><br><br></span><span style=3D"color: #800;" class=3D"styled-by-p=
rettify">//B</span><span style=3D"color: #000;" class=3D"styled-by-prettify=
"><br></span><span style=3D"color: #008;" class=3D"styled-by-prettify">auto=
</span><span style=3D"color: #000;" class=3D"styled-by-prettify"> rrng </sp=
an><span style=3D"color: #660;" class=3D"styled-by-prettify">=3D</span><spa=
n style=3D"color: #000;" class=3D"styled-by-prettify"> std</span><span styl=
e=3D"color: #660;" class=3D"styled-by-prettify">::</span><span style=3D"col=
or: #000;" class=3D"styled-by-prettify">make_reverse_range</span><span styl=
e=3D"color: #660;" class=3D"styled-by-prettify">(</span><span style=3D"colo=
r: #000;" class=3D"styled-by-prettify">rng</span><span style=3D"color: #660=
;" class=3D"styled-by-prettify">);</span><span style=3D"color: #000;" class=
=3D"styled-by-prettify"><br>std</span><span style=3D"color: #660;" class=3D=
"styled-by-prettify">::</span><span style=3D"color: #000;" class=3D"styled-=
by-prettify">move</span><span style=3D"color: #660;" class=3D"styled-by-pre=
ttify">(</span><span style=3D"color: #000;" class=3D"styled-by-prettify">st=
d</span><span style=3D"color: #660;" class=3D"styled-by-prettify">::</span>=
<span style=3D"color: #000;" class=3D"styled-by-prettify">make_range</span>=
<span style=3D"color: #660;" class=3D"styled-by-prettify">(</span><span sty=
le=3D"color: #000;" class=3D"styled-by-prettify">rrng</span><span style=3D"=
color: #660;" class=3D"styled-by-prettify">.</span><span style=3D"color: #0=
08;" class=3D"styled-by-prettify">begin</span><span style=3D"color: #000;" =
class=3D"styled-by-prettify"> </span><span style=3D"color: #660;" class=3D"=
styled-by-prettify">+</span><span style=3D"color: #000;" class=3D"styled-by=
-prettify"> N</span><span style=3D"color: #660;" class=3D"styled-by-prettif=
y">,</span><span style=3D"color: #000;" class=3D"styled-by-prettify"> rrng<=
/span><span style=3D"color: #660;" class=3D"styled-by-prettify">.</span><sp=
an style=3D"color: #008;" class=3D"styled-by-prettify">end</span><span styl=
e=3D"color: #660;" class=3D"styled-by-prettify">()),</span><span style=3D"c=
olor: #000;" class=3D"styled-by-prettify"> rrng</span><span style=3D"color:=
 #660;" class=3D"styled-by-prettify">.</span><span style=3D"color: #008;" c=
lass=3D"styled-by-prettify">begin</span><span style=3D"color: #660;" class=
=3D"styled-by-prettify">());</span></div></code></div></div></div>

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Can you write proposal about std::shift? Need you any help with writing=20
proposal and/or implementation?

=D1=87=D0=B5=D1=82=D0=B2=D0=B5=D1=80=D0=B3, 13 =D0=B8=D1=8E=D0=BB=D1=8F 201=
7 =D0=B3., 14:41:34 UTC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=
=D1=82=D0=B5=D0=BB=D1=8C Dan Raviv =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=
=BB:
>
> Thanks for phrasing the motivation so well Nicol.
>
> Arthur, regarding specific use cases, any algorithm doing time series=20
> analysis (e.g. temperature the last 20 days) could use this.
>
> (A cyclical buffer is an alternative, but one which isn't always=20
> preferrable.)
>
> On 13 Jul 2017, at 4:43, Nicol Bolas <jmck...@gmail.com <javascript:>>=20
> wrote:
>
> On Wednesday, July 12, 2017 at 7:47:05 PM UTC-4, Arthur O'Dwyer wrote:
>>
>> On Wednesday, July 12, 2017 at 2:53:19 AM UTC-7, d...@soundradix.com=20
>> wrote:
>>>
>>> Hi,
>>>
>>> Would anyone be interested in adding std::shift to <algorithm>?=20
>>>
>>> It would be similar to both:
>>> - std::rotate, but without moving the head elements back to the tail.=
=20
>>> This would allow a more efficient implementation and clearer semantics =
in=20
>>> case rotation is not needed as well as correctness in case rotation is=
=20
>>> undesired.
>>> - <algorithm>'s std::move/std::move_backward (depending on the shift=20
>>> direction).
>>>
>>> std::shift should probably accommodate both left and right shifts by on=
e=20
>>> of:
>>> - giving it either begin() and end(), or rbegin() and rend(), similar t=
o=20
>>> how std::rotate works for both left and right rotations. The advantage =
is=20
>>> compactness of the implementation.
>>> - allowing the shift count parameter to be either positive or negative.=
=20
>>> The advantage is compactness, though it might not be clear which direct=
ion=20
>>> is which - to be consistent with rotate, positive integers should shift=
 to=20
>>> the left.
>>> - having std::shift_right and std::shift_left functions. The advantage=
=20
>>> is clarity when calling the methods, although the same argument could b=
e=20
>>> made for having separate std::rotate_left and std::rotate_right instead=
 of=20
>>> std::rotate, which we don't have.
>>>
>>
>> std::rotate is actually just a rotation; it doesn't need "left" or=20
>> "right" qualification because they're 100% equivalent. Consider a classr=
oom=20
>> globe with London in front, facing you. Now "rotate" the globe until=20
>> Beijing is in front. It doesn't matter if you rotate left or rotate righ=
t;=20
>> the outcome is exactly the same either way.
>> =20
>>
>>> Here's a sample implementation of a shift to the right direction:
>>>
>>> template<class BidirIt>=20
>>> void shift_right(BidirIt first, BidirIt last, unsigned int n =3D 1)=20
>>> {=20
>>>     std::move_backward(first, last - n, last);=20
>>> }
>>>
>>> This demonstrates that while std::shift is implementable with=20
>>> std::move/std::move_backward,
>>> 1) It isn't immediately clear from the code (at least to my eyes) that=
=20
>>> this is a shift right, unless you are intimately familiar with=20
>>> std::move_backward.
>>> 2) Different calls, either to std::move or to std::move_backward, are=
=20
>>> required, depending on the shift direction.
>>>
>>
>> If you're shifting the whole container's contents, you could use either=
=20
>> of these:
>>     std::move(ctr.rbegin() + n, ctr.rend(), ctr.rbegin());
>>     std::move_backward(ctr.begin(), ctr.end() - n, ctr.end())?
>> I don't currently see the use-case for this "shift just a piece of a=20
>> container" algorithm, I mean as distinct from std::move and=20
>> std::move_backward which already exist. Do you have a use-case?
>>
>
> The use-case would be anytime you'd want to use the code you just wrote.=
=20
> When you have a range and N, and you want to do a shift N units in that=
=20
> direction.
>
> The point of having it is one of clarification and user expectations. Yes=
,=20
> you can use `move` and `move_backward` to accomplish a shift. But conside=
r=20
> the two function calls:
>
> //A
> std::shift(rng.begin(), rng.end(), N);
>
> //B
> auto rrng =3D std::make_reverse_range(rng);
> std::move(rrng.begin() + N, rrng.end(), rrng.begin());
>
> A and B both do the same thing. But it's a *lot easier* to figure out=20
> what the code is actually accomplishing from looking at A than B.
>
> B gets even more obtuse confusing in a range-based world:
>
> //A
> std::shift(rng, N);
>
> //B
> auto rrng =3D std::make_reverse_range(rng);
> std::move(std::make_range(rrng.begin + N, rrng.end()), rrng.begin());
>
> --=20
> You received this message because you are subscribed to the Google Groups=
=20
> "ISO C++ Standard - Future Proposals" group.
> To unsubscribe from this group and stop receiving emails from it, send an=
=20
> email to std-proposal...@isocpp.org <javascript:>.
> To post to this group, send email to std-pr...@isocpp.org <javascript:>.
> To view this discussion on the web visit=20
> https://groups.google.com/a/isocpp.org/d/msgid/std-proposals/c722a201-5c9=
c-4ac5-a1bd-e50beb6d7860%40isocpp.org=20
> <https://groups.google.com/a/isocpp.org/d/msgid/std-proposals/c722a201-5c=
9c-4ac5-a1bd-e50beb6d7860%40isocpp.org?utm_medium=3Demail&utm_source=3Dfoot=
er>
> .
>
>

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<div dir=3D"ltr">Can you write proposal about std::shift? Need you any help=
 with writing proposal and/or implementation?<br><br>=D1=87=D0=B5=D1=82=D0=
=B2=D0=B5=D1=80=D0=B3, 13 =D0=B8=D1=8E=D0=BB=D1=8F 2017 =D0=B3., 14:41:34 U=
TC+3 =D0=BF=D0=BE=D0=BB=D1=8C=D0=B7=D0=BE=D0=B2=D0=B0=D1=82=D0=B5=D0=BB=D1=
=8C Dan Raviv =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=BB:<blockquote class=
=3D"gmail_quote" style=3D"margin: 0;margin-left: 0.8ex;border-left: 1px #cc=
c solid;padding-left: 1ex;"><div dir=3D"auto"><div></div><div>Thanks for ph=
rasing the motivation so well Nicol.</div><div><br></div><div>Arthur, regar=
ding specific use cases, any algorithm doing time series analysis (e.g. tem=
perature the last 20 days) could use this.</div><div><br></div><div>(A cycl=
ical buffer is an alternative, but one which isn&#39;t always preferrable.)=
</div><div><br>On 13 Jul 2017, at 4:43, Nicol Bolas &lt;<a href=3D"javascri=
pt:" target=3D"_blank" gdf-obfuscated-mailto=3D"ZSNIAKlbBgAJ" rel=3D"nofoll=
ow" onmousedown=3D"this.href=3D&#39;javascript:&#39;;return true;" onclick=
=3D"this.href=3D&#39;javascript:&#39;;return true;">jmck...@gmail.com</a>&g=
t; wrote:<br><br></div><blockquote type=3D"cite"><div><div dir=3D"ltr">On W=
ednesday, July 12, 2017 at 7:47:05 PM UTC-4, Arthur O&#39;Dwyer wrote:<bloc=
kquote class=3D"gmail_quote" style=3D"margin:0;margin-left:0.8ex;border-lef=
t:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">On Wednesday, July 12, =
2017 at 2:53:19 AM UTC-7, <a>d...@soundradix.com</a> wrote:<blockquote clas=
s=3D"gmail_quote" style=3D"margin:0;margin-left:0.8ex;border-left:1px #ccc =
solid;padding-left:1ex"><div dir=3D"ltr">Hi,<div><br></div><div>Would anyon=
e be interested in adding std::shift to &lt;algorithm&gt;?=C2=A0</div><div>=
<br></div><div>It would be similar to both:</div><div>- std::rotate, but wi=
thout moving the head elements back to the tail. This would allow a more ef=
ficient implementation and clearer semantics in case rotation is not needed=
 as well as correctness in case rotation is undesired.</div><div>- &lt;algo=
rithm&gt;&#39;s std::move/std::move_backward (depending on the shift direct=
ion).</div><div><br></div><div>std::shift should probably accommodate both =
left and right shifts by one of:</div><div>- giving it either begin() and e=
nd(), or rbegin() and rend(), similar to how std::rotate works for both lef=
t and right rotations. The advantage is compactness of the implementation.<=
/div><div>- allowing the shift count parameter to be either positive or neg=
ative. The advantage is compactness, though it might not be clear which dir=
ection is which - to be consistent with rotate, positive integers should sh=
ift to the left.<br></div><div><div>- having std::shift_right and std::shif=
t_left functions. The advantage is clarity when calling the methods, althou=
gh the same argument could be made for having separate std::rotate_left and=
 std::rotate_right instead of std::rotate, which we don&#39;t have.</div></=
div></div></blockquote><div><br></div><div>std::rotate is actually just a r=
otation; it doesn&#39;t need &quot;left&quot; or &quot;right&quot; qualific=
ation because they&#39;re 100% equivalent. Consider a classroom globe with =
London in front, facing you. Now &quot;rotate&quot; the globe until Beijing=
 is in front. It doesn&#39;t matter if you rotate left or rotate right; the=
 outcome is exactly the same either way.</div><div>=C2=A0</div><blockquote =
class=3D"gmail_quote" style=3D"margin:0;margin-left:0.8ex;border-left:1px #=
ccc solid;padding-left:1ex"><div dir=3D"ltr"><div>Here&#39;s a sample imple=
mentation of a shift to the right direction:<br></div><br><div style=3D"bac=
kground-color:rgb(250,250,250);border:1px solid rgb(187,187,187);word-wrap:=
break-word"><code><div><span style=3D"color:#008">template</span><span styl=
e=3D"color:#660">&lt;</span><span style=3D"color:#008">class</span><span st=
yle=3D"color:#000"> </span><span style=3D"color:#606">BidirIt</span><span s=
tyle=3D"color:#660">&gt;</span><span style=3D"color:#000"> <br></span><span=
 style=3D"color:#008">void</span><span style=3D"color:#000"> shift_right</s=
pan><span style=3D"color:#660">(</span><span style=3D"color:#606">BidirIt</=
span><span style=3D"color:#000"> first</span><span style=3D"color:#660">,</=
span><span style=3D"color:#000"> </span><span style=3D"color:#606">BidirIt<=
/span><span style=3D"color:#000"> </span><span style=3D"color:#008">last</s=
pan><span style=3D"color:#660">,</span><span style=3D"color:#000"> </span><=
span style=3D"color:#008">unsigned</span><span style=3D"color:#000"> </span=
><span style=3D"color:#008">int</span><span style=3D"color:#000"> n </span>=
<span style=3D"color:#660">=3D</span><span style=3D"color:#000"> </span><sp=
an style=3D"color:#066">1</span><span style=3D"color:#660">)</span><span st=
yle=3D"color:#000"> <br></span><span style=3D"color:#660">{</span><span sty=
le=3D"color:#000"> <br>=C2=A0 =C2=A0 std</span><span style=3D"color:#660">:=
:</span><span style=3D"color:#000">move_backward</span><span style=3D"color=
:#660">(</span><span style=3D"color:#000">first</span><span style=3D"color:=
#660">,</span><span style=3D"color:#000"> </span><span style=3D"color:#008"=
>last</span><span style=3D"color:#000"> </span><span style=3D"color:#660">-=
</span><span style=3D"color:#000"> n</span><span style=3D"color:#660">,</sp=
an><span style=3D"color:#000"> </span><span style=3D"color:#008">last</span=
><span style=3D"color:#660">);</span><span style=3D"color:#000"> <br></span=
><span style=3D"color:#660">}</span><span style=3D"color:#000"><br></span><=
/div></code></div><div><br></div><div>This demonstrates that while std::shi=
ft is implementable with std::move/std::move_backward,</div><div>1) It isn&=
#39;t immediately clear from the code (at least to my eyes) that this is a =
shift right, unless you are intimately familiar with std::move_backward.</d=
iv><div>2) Different calls, either to std::move or to std::move_backward, a=
re required, depending on the shift direction.</div></div></blockquote><div=
><br></div><div>If you&#39;re shifting the whole container&#39;s contents, =
you could use either of these:</div><div>=C2=A0 =C2=A0 std::move(ctr.rbegin=
() + n, ctr.rend(), ctr.rbegin());</div><div>=C2=A0 =C2=A0 std::move_backwa=
rd(ctr.begin()<wbr>, ctr.end() - n, ctr.end())?</div><div>I don&#39;t curre=
ntly see the use-case for this &quot;shift just a piece of a container&quot=
; algorithm, I mean as distinct from std::move and std::move_backward which=
 already exist. Do you have a use-case?</div></div></blockquote><div><br>Th=
e use-case would be anytime you&#39;d want to use the code you just wrote. =
When you have a range and N, and you want to do a shift N units in that dir=
ection.<br><br>The point of having it is one of clarification and user expe=
ctations. Yes, you can use `move` and `move_backward` to accomplish a shift=
.. But consider the two function calls:<br><br><div style=3D"background-colo=
r:rgb(250,250,250);border-color:rgb(187,187,187);border-style:solid;border-=
width:1px"><code><div><span style=3D"color:#800">//A</span><span style=3D"c=
olor:#000"><br>std</span><span style=3D"color:#660">::</span><span style=3D=
"color:#000">shift</span><span style=3D"color:#660">(</span><span style=3D"=
color:#000">rng</span><span style=3D"color:#660">.</span><span style=3D"col=
or:#008">begin</span><span style=3D"color:#660">(),</span><span style=3D"co=
lor:#000"> rng</span><span style=3D"color:#660">.</span><span style=3D"colo=
r:#008">end</span><span style=3D"color:#660">(),</span><span style=3D"color=
:#000"> N</span><span style=3D"color:#660">);</span><span style=3D"color:#0=
00"><br><br></span><span style=3D"color:#800">//B</span><span style=3D"colo=
r:#000"><br></span><span style=3D"color:#008">auto</span><span style=3D"col=
or:#000"> rrng </span><span style=3D"color:#660">=3D</span><span style=3D"c=
olor:#000"> std</span><span style=3D"color:#660">::</span><span style=3D"co=
lor:#000">make_reverse_range</span><span style=3D"color:#660">(</span><span=
 style=3D"color:#000">rng</span><span style=3D"color:#660">);</span><span s=
tyle=3D"color:#000"><br>std</span><span style=3D"color:#660">::</span><span=
 style=3D"color:#000">move</span><span style=3D"color:#660">(</span><span s=
tyle=3D"color:#000">rrng</span><span style=3D"color:#660">.</span><span sty=
le=3D"color:#008">begin</span><span style=3D"color:#660">()</span><span sty=
le=3D"color:#000"> </span><span style=3D"color:#660">+</span><span style=3D=
"color:#000"> N</span><span style=3D"color:#660">,</span><span style=3D"col=
or:#000"> rrng</span><span style=3D"color:#660">.</span><span style=3D"colo=
r:#008">end</span><span style=3D"color:#660">(),</span><span style=3D"color=
:#000"> rrng</span><span style=3D"color:#660">.</span><span style=3D"color:=
#008">begin</span><span style=3D"color:#660">());</span></div></code></div>=
<br>A and B both do the same thing. But it&#39;s a <i>lot easier</i> to fig=
ure out what the code is actually accomplishing from looking at A than B.<b=
r><br>B gets even more obtuse confusing in a range-based world:<br><br><div=
 style=3D"background-color:rgb(250,250,250);border-color:rgb(187,187,187);b=
order-style:solid;border-width:1px"><code><div><span style=3D"color:#800">/=
/A</span><span style=3D"color:#000"><br>std</span><span style=3D"color:#660=
">::</span><span style=3D"color:#000">shift</span><span style=3D"color:#660=
">(</span><span style=3D"color:#000">rng</span><span style=3D"color:#660">,=
</span><span style=3D"color:#000"> N</span><span style=3D"color:#660">);</s=
pan><span style=3D"color:#000"><br><br></span><span style=3D"color:#800">//=
B</span><span style=3D"color:#000"><br></span><span style=3D"color:#008">au=
to</span><span style=3D"color:#000"> rrng </span><span style=3D"color:#660"=
>=3D</span><span style=3D"color:#000"> std</span><span style=3D"color:#660"=
>::</span><span style=3D"color:#000">make_reverse_range</span><span style=
=3D"color:#660">(</span><span style=3D"color:#000">rng</span><span style=3D=
"color:#660">);</span><span style=3D"color:#000"><br>std</span><span style=
=3D"color:#660">::</span><span style=3D"color:#000">move</span><span style=
=3D"color:#660">(</span><span style=3D"color:#000">std</span><span style=3D=
"color:#660">::</span><span style=3D"color:#000">make_range</span><span sty=
le=3D"color:#660">(</span><span style=3D"color:#000">rrng</span><span style=
=3D"color:#660"><wbr>.</span><span style=3D"color:#008">begin</span><span s=
tyle=3D"color:#000"> </span><span style=3D"color:#660">+</span><span style=
=3D"color:#000"> N</span><span style=3D"color:#660">,</span><span style=3D"=
color:#000"> rrng</span><span style=3D"color:#660">.</span><span style=3D"c=
olor:#008">end</span><span style=3D"color:#660">()),</span><span style=3D"c=
olor:#000"> rrng</span><span style=3D"color:#660">.</span><span style=3D"co=
lor:#008">begin</span><span style=3D"color:#660">());</span></div></code></=
div></div></div>

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/a/<wbr>isocpp.org/d/msgid/std-<wbr>proposals/c722a201-5c9c-4ac5-<wbr>a1bd-=
e50beb6d7860%40isocpp.org</a><wbr>.<br>
</div></blockquote></div></blockquote></div>

<p></p>

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On Wednesday, July 12, 2017 at 6:43:11 PM UTC-7, Nicol Bolas wrote:
>
> On Wednesday, July 12, 2017 at 7:47:05 PM UTC-4, Arthur O'Dwyer wrote:
>>
>> On Wednesday, July 12, 2017 at 2:53:19 AM UTC-7, d...@soundradix.com=20
>> wrote:
>>>
>>> Hi,
>>>
>>> Would anyone be interested in adding std::shift to <algorithm>?=20
>>>
>>> It would be similar to both:
>>> - std::rotate, but without moving the head elements back to the tail.=
=20
>>> This would allow a more efficient implementation and clearer semantics =
in=20
>>> case rotation is not needed as well as correctness in case rotation is=
=20
>>> undesired.
>>> - <algorithm>'s std::move/std::move_backward (depending on the shift=20
>>> direction).
>>>
>>> std::shift should probably accommodate both left and right shifts by on=
e=20
>>> of:
>>> - giving it either begin() and end(), or rbegin() and rend(), similar t=
o=20
>>> how std::rotate works for both left and right rotations. The advantage =
is=20
>>> compactness of the implementation.
>>> - allowing the shift count parameter to be either positive or negative.=
=20
>>> The advantage is compactness, though it might not be clear which direct=
ion=20
>>> is which - to be consistent with rotate, positive integers should shift=
 to=20
>>> the left.
>>> - having std::shift_right and std::shift_left functions. The advantage=
=20
>>> is clarity when calling the methods, although the same argument could b=
e=20
>>> made for having separate std::rotate_left and std::rotate_right instead=
 of=20
>>> std::rotate, which we don't have.
>>>
>>
>> std::rotate is actually just a rotation; it doesn't need "left" or=20
>> "right" qualification because they're 100% equivalent. Consider a classr=
oom=20
>> globe with London in front, facing you. Now "rotate" the globe until=20
>> Beijing is in front. It doesn't matter if you rotate left or rotate righ=
t;=20
>> the outcome is exactly the same either way.
>> =20
>>
>>> Here's a sample implementation of a shift to the right direction:
>>>
>>> template<class BidirIt>=20
>>> void shift_right(BidirIt first, BidirIt last, unsigned int n =3D 1)=20
>>> {=20
>>>     std::move_backward(first, last - n, last);=20
>>> }
>>>
>>> This demonstrates that while std::shift is implementable with=20
>>> std::move/std::move_backward,
>>> 1) It isn't immediately clear from the code (at least to my eyes) that=
=20
>>> this is a shift right, unless you are intimately familiar with=20
>>> std::move_backward.
>>> 2) Different calls, either to std::move or to std::move_backward, are=
=20
>>> required, depending on the shift direction.
>>>
>>
>> If you're shifting the whole container's contents, you could use either=
=20
>> of these:
>>     std::move(ctr.rbegin() + n, ctr.rend(), ctr.rbegin());
>>     std::move_backward(ctr.begin(), ctr.end() - n, ctr.end())?
>> I don't currently see the use-case for this "shift just a piece of a=20
>> container" algorithm, I mean as distinct from std::move and=20
>> std::move_backward which already exist. Do you have a use-case?
>>
>
> The use-case would be anytime you'd want to use the code you just wrote.=
=20
> When you have a range and N, and you want to do a shift N units in that=
=20
> direction.
>
> The point of having it is one of clarification and user expectations. Yes=
,=20
> you can use `move` and `move_backward` to accomplish a shift. But conside=
r=20
> the two function calls:
>
> //A
> std::shift(rng.begin(), rng.end(), N);
>
> //B
> auto rrng =3D std::make_reverse_range(rng);
> std::move(rrng.begin() + N, rrng.end(), rrng.begin());
>
> A and B both do the same thing. But it's a *lot easier* to figure out=20
> what the code is actually accomplishing from looking at A than B.
>

Do you have a use-case for either of these?
I recall your admonition cross-thread that generally in the STL we *don't*=
=20
want to operate on containers but rather on ranges (or iterator-pairs); so=
=20
if I had a range that I wanted to "shift", I would first consider whether I=
=20
could do something like

    // OLD: shift_in_place(range, n); operate_on(range.begin(),=20
range.end());
    // NEW: operate_on(range.begin() + n, range.end());

That is, instead of moving the actual data, which might be slow, I'd move=
=20
one or the other "endpoint" while leaving the data in place.
In his reply, Dan Raviv mentioned that this is exactly the kind of thing=20
that a circular buffer does, and he's right (see proposal P0059).



B gets even more obtuse confusing in a range-based world:
>
> //A
> std::shift(rng, N);
>
> //B
> auto rrng =3D std::make_reverse_range(rng);
> std::move(std::make_range(rrng.begin + N, rrng.end()), rrng.begin());
>

In a range-based world, I would write this as

    auto output =3D input | rng::drop(n);

for a "left-shift", or... okay, the "right-shift" version is messy, at=20
least in my version, because it involves concatenating ranges one of which=
=20
needs to be created out of whole cloth, with n objects, each of which is in=
=20
a "valid but unspecified" state.  (I'd bet *money* you can't give me a=20
use-case for *that* one.)

I'd still like to see a use-case for O(n) "shifting" a sequence of elements=
=20
in-place (as opposed to using one of these range-based approaches, or using=
=20
a circular buffer, or "shifting the endpoints").  I agree that sometimes=20
you do want to copy/move the second part of a sequence over the first part,=
=20
but I would always express that in terms of "I'm std::copy'ing /=20
std::move'ing data." Expressing it as a "shift" doesn't feel natural to me=
=20
in any of the (extremely rare) use-cases I've thought of. Do you have a=20
use-case?

=E2=80=93Arthur

--=20
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<div dir=3D"ltr">On Wednesday, July 12, 2017 at 6:43:11 PM UTC-7, Nicol Bol=
as wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;margin-left: =
0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"ltr">On W=
ednesday, July 12, 2017 at 7:47:05 PM UTC-4, Arthur O&#39;Dwyer wrote:<bloc=
kquote class=3D"gmail_quote" style=3D"margin:0;margin-left:0.8ex;border-lef=
t:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">On Wednesday, July 12, =
2017 at 2:53:19 AM UTC-7, <a>d...@soundradix.com</a> wrote:<blockquote clas=
s=3D"gmail_quote" style=3D"margin:0;margin-left:0.8ex;border-left:1px #ccc =
solid;padding-left:1ex"><div dir=3D"ltr">Hi,<div><br></div><div>Would anyon=
e be interested in adding std::shift to &lt;algorithm&gt;?=C2=A0</div><div>=
<br></div><div>It would be similar to both:</div><div>- std::rotate, but wi=
thout moving the head elements back to the tail. This would allow a more ef=
ficient implementation and clearer semantics in case rotation is not needed=
 as well as correctness in case rotation is undesired.</div><div>- &lt;algo=
rithm&gt;&#39;s std::move/std::move_backward (depending on the shift direct=
ion).</div><div><br></div><div>std::shift should probably accommodate both =
left and right shifts by one of:</div><div>- giving it either begin() and e=
nd(), or rbegin() and rend(), similar to how std::rotate works for both lef=
t and right rotations. The advantage is compactness of the implementation.<=
/div><div>- allowing the shift count parameter to be either positive or neg=
ative. The advantage is compactness, though it might not be clear which dir=
ection is which - to be consistent with rotate, positive integers should sh=
ift to the left.<br></div><div><div>- having std::shift_right and std::shif=
t_left functions. The advantage is clarity when calling the methods, althou=
gh the same argument could be made for having separate std::rotate_left and=
 std::rotate_right instead of std::rotate, which we don&#39;t have.</div></=
div></div></blockquote><div><br></div><div>std::rotate is actually just a r=
otation; it doesn&#39;t need &quot;left&quot; or &quot;right&quot; qualific=
ation because they&#39;re 100% equivalent. Consider a classroom globe with =
London in front, facing you. Now &quot;rotate&quot; the globe until Beijing=
 is in front. It doesn&#39;t matter if you rotate left or rotate right; the=
 outcome is exactly the same either way.</div><div>=C2=A0</div><blockquote =
class=3D"gmail_quote" style=3D"margin:0;margin-left:0.8ex;border-left:1px #=
ccc solid;padding-left:1ex"><div dir=3D"ltr"><div>Here&#39;s a sample imple=
mentation of a shift to the right direction:<br></div><br><div style=3D"bac=
kground-color:rgb(250,250,250);border:1px solid rgb(187,187,187);word-wrap:=
break-word"><code><div><span style=3D"color:#008">template</span><span styl=
e=3D"color:#660">&lt;</span><span style=3D"color:#008">class</span><span st=
yle=3D"color:#000"> </span><span style=3D"color:#606">BidirIt</span><span s=
tyle=3D"color:#660">&gt;</span><span style=3D"color:#000"> <br></span><span=
 style=3D"color:#008">void</span><span style=3D"color:#000"> shift_right</s=
pan><span style=3D"color:#660">(</span><span style=3D"color:#606">BidirIt</=
span><span style=3D"color:#000"> first</span><span style=3D"color:#660">,</=
span><span style=3D"color:#000"> </span><span style=3D"color:#606">BidirIt<=
/span><span style=3D"color:#000"> </span><span style=3D"color:#008">last</s=
pan><span style=3D"color:#660">,</span><span style=3D"color:#000"> </span><=
span style=3D"color:#008">unsigned</span><span style=3D"color:#000"> </span=
><span style=3D"color:#008">int</span><span style=3D"color:#000"> n </span>=
<span style=3D"color:#660">=3D</span><span style=3D"color:#000"> </span><sp=
an style=3D"color:#066">1</span><span style=3D"color:#660">)</span><span st=
yle=3D"color:#000"> <br></span><span style=3D"color:#660">{</span><span sty=
le=3D"color:#000"> <br>=C2=A0 =C2=A0 std</span><span style=3D"color:#660">:=
:</span><span style=3D"color:#000">move_backward</span><span style=3D"color=
:#660">(</span><span style=3D"color:#000">first</span><span style=3D"color:=
#660">,</span><span style=3D"color:#000"> </span><span style=3D"color:#008"=
>last</span><span style=3D"color:#000"> </span><span style=3D"color:#660">-=
</span><span style=3D"color:#000"> n</span><span style=3D"color:#660">,</sp=
an><span style=3D"color:#000"> </span><span style=3D"color:#008">last</span=
><span style=3D"color:#660">);</span><span style=3D"color:#000"> <br></span=
><span style=3D"color:#660">}</span><span style=3D"color:#000"><br></span><=
/div></code></div><div><br></div><div>This demonstrates that while std::shi=
ft is implementable with std::move/std::move_backward,</div><div>1) It isn&=
#39;t immediately clear from the code (at least to my eyes) that this is a =
shift right, unless you are intimately familiar with std::move_backward.</d=
iv><div>2) Different calls, either to std::move or to std::move_backward, a=
re required, depending on the shift direction.</div></div></blockquote><div=
><br></div><div>If you&#39;re shifting the whole container&#39;s contents, =
you could use either of these:</div><div>=C2=A0 =C2=A0 std::move(ctr.rbegin=
() + n, ctr.rend(), ctr.rbegin());</div><div>=C2=A0 =C2=A0 std::move_backwa=
rd(ctr.begin()<wbr>, ctr.end() - n, ctr.end())?</div><div>I don&#39;t curre=
ntly see the use-case for this &quot;shift just a piece of a container&quot=
; algorithm, I mean as distinct from std::move and std::move_backward which=
 already exist. Do you have a use-case?</div></div></blockquote><div><br>Th=
e use-case would be anytime you&#39;d want to use the code you just wrote. =
When you have a range and N, and you want to do a shift N units in that dir=
ection.<br><br>The point of having it is one of clarification and user expe=
ctations. Yes, you can use `move` and `move_backward` to accomplish a shift=
.. But consider the two function calls:<br><br><div style=3D"background-colo=
r:rgb(250,250,250);border-color:rgb(187,187,187);border-style:solid;border-=
width:1px"><code><div><span style=3D"color:#800">//A</span><span style=3D"c=
olor:#000"><br>std</span><span style=3D"color:#660">::</span><span style=3D=
"color:#000">shift</span><span style=3D"color:#660">(</span><span style=3D"=
color:#000">rng</span><span style=3D"color:#660">.</span><span style=3D"col=
or:#008">begin</span><span style=3D"color:#660">(),</span><span style=3D"co=
lor:#000"> rng</span><span style=3D"color:#660">.</span><span style=3D"colo=
r:#008">end</span><span style=3D"color:#660">(),</span><span style=3D"color=
:#000"> N</span><span style=3D"color:#660">);</span><span style=3D"color:#0=
00"><br><br></span><span style=3D"color:#800">//B</span><span style=3D"colo=
r:#000"><br></span><span style=3D"color:#008">auto</span><span style=3D"col=
or:#000"> rrng </span><span style=3D"color:#660">=3D</span><span style=3D"c=
olor:#000"> std</span><span style=3D"color:#660">::</span><span style=3D"co=
lor:#000">make_reverse_range</span><span style=3D"color:#660">(</span><span=
 style=3D"color:#000">rng</span><span style=3D"color:#660">);</span><span s=
tyle=3D"color:#000"><br>std</span><span style=3D"color:#660">::</span><span=
 style=3D"color:#000">move</span><span style=3D"color:#660">(</span><span s=
tyle=3D"color:#000">rrng</span><span style=3D"color:#660">.</span><span sty=
le=3D"color:#008">begin</span><span style=3D"color:#660">()</span><span sty=
le=3D"color:#000"> </span><span style=3D"color:#660">+</span><span style=3D=
"color:#000"> N</span><span style=3D"color:#660">,</span><span style=3D"col=
or:#000"> rrng</span><span style=3D"color:#660">.</span><span style=3D"colo=
r:#008">end</span><span style=3D"color:#660">(),</span><span style=3D"color=
:#000"> rrng</span><span style=3D"color:#660">.</span><span style=3D"color:=
#008">begin</span><span style=3D"color:#660">());</span></div></code></div>=
<br>A and B both do the same thing. But it&#39;s a <i>lot easier</i> to fig=
ure out what the code is actually accomplishing from looking at A than B.<b=
r></div></div></blockquote><div><br></div><div>Do you have a use-case for e=
ither of these?</div><div>I recall your admonition cross-thread that genera=
lly in the STL we *don&#39;t* want to operate on containers but rather on r=
anges (or iterator-pairs); so if I had a range that I wanted to &quot;shift=
&quot;, I would first consider whether I could do something like</div><div>=
<br></div><div>=C2=A0 =C2=A0 // OLD: shift_in_place(range, n); operate_on(r=
ange.begin(), range.end());</div><div>=C2=A0 =C2=A0 // NEW: operate_on(rang=
e.begin() + n, range.end());</div><div><br></div><div>That is, instead of m=
oving the actual data, which might be slow, I&#39;d move one or the other &=
quot;endpoint&quot; while leaving the data in place.</div><div>In his reply=
, Dan Raviv mentioned that this is exactly the kind of thing that a circula=
r buffer does, and he&#39;s right (see proposal P0059).</div><div><br></div=
><div><br></div><div><br></div><blockquote class=3D"gmail_quote" style=3D"m=
argin: 0;margin-left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"=
><div dir=3D"ltr"><div>B gets even more obtuse confusing in a range-based w=
orld:<br><br><div style=3D"background-color:rgb(250,250,250);border-color:r=
gb(187,187,187);border-style:solid;border-width:1px"><code><div><span style=
=3D"color:#800">//A</span><span style=3D"color:#000"><br>std</span><span st=
yle=3D"color:#660">::</span><span style=3D"color:#000">shift</span><span st=
yle=3D"color:#660">(</span><span style=3D"color:#000">rng</span><span style=
=3D"color:#660">,</span><span style=3D"color:#000"> N</span><span style=3D"=
color:#660">);</span><span style=3D"color:#000"><br><br></span><span style=
=3D"color:#800">//B</span><span style=3D"color:#000"><br></span><span style=
=3D"color:#008">auto</span><span style=3D"color:#000"> rrng </span><span st=
yle=3D"color:#660">=3D</span><span style=3D"color:#000"> std</span><span st=
yle=3D"color:#660">::</span><span style=3D"color:#000">make_reverse_range</=
span><span style=3D"color:#660">(</span><span style=3D"color:#000">rng</spa=
n><span style=3D"color:#660">);</span><span style=3D"color:#000"><br>std</s=
pan><span style=3D"color:#660">::</span><span style=3D"color:#000">move</sp=
an><span style=3D"color:#660">(</span><span style=3D"color:#000">std</span>=
<span style=3D"color:#660">::</span><span style=3D"color:#000">make_range</=
span><span style=3D"color:#660">(</span><span style=3D"color:#000">rrng</sp=
an><span style=3D"color:#660"><wbr>.</span><span style=3D"color:#008">begin=
</span><span style=3D"color:#000"> </span><span style=3D"color:#660">+</spa=
n><span style=3D"color:#000"> N</span><span style=3D"color:#660">,</span><s=
pan style=3D"color:#000"> rrng</span><span style=3D"color:#660">.</span><sp=
an style=3D"color:#008">end</span><span style=3D"color:#660">()),</span><sp=
an style=3D"color:#000"> rrng</span><span style=3D"color:#660">.</span><spa=
n style=3D"color:#008">begin</span><span style=3D"color:#660">());</span></=
div></code></div></div></div></blockquote><div><br></div><div>In a range-ba=
sed world, I would write this as</div><div><br></div><div>=C2=A0 =C2=A0 aut=
o output =3D input | rng::drop(n);</div><div><br></div><div>for a &quot;lef=
t-shift&quot;, or... okay, the &quot;right-shift&quot; version is messy, at=
 least in my version, because it involves concatenating ranges one of which=
 needs to be created out of whole cloth, with n objects, each of which is i=
n a &quot;valid but unspecified&quot; state. =C2=A0(I&#39;d bet <i>money</i=
> you can&#39;t give me a use-case for <i>that</i> one.)</div><div><br></di=
v><div>I&#39;d still like to see a use-case for O(n) &quot;shifting&quot; a=
 sequence of elements in-place (as opposed to using one of these range-base=
d approaches, or using a circular buffer, or &quot;shifting the endpoints&q=
uot;). =C2=A0I agree that sometimes you do want to copy/move the second par=
t of a sequence over the first part, but I would always express that in ter=
ms of &quot;I&#39;m std::copy&#39;ing / std::move&#39;ing data.&quot; Expre=
ssing it as a &quot;shift&quot; doesn&#39;t feel natural to me in any of th=
e (extremely rare) use-cases I&#39;ve thought of. Do you have a use-case?</=
div><div><br></div><div>=E2=80=93Arthur</div></div>

<p></p>

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On Thu, Jul 13, 2017 at 8:21 PM, Arthur O'Dwyer <arthur.j.odwyer@gmail.com>
wrote:

> On Wednesday, July 12, 2017 at 6:43:11 PM UTC-7, Nicol Bolas wrote:
>>
>> On Wednesday, July 12, 2017 at 7:47:05 PM UTC-4, Arthur O'Dwyer wrote:
>>>
>>> On Wednesday, July 12, 2017 at 2:53:19 AM UTC-7, d...@soundradix.com
>>> wrote:
>>>>
>>>> Hi,
>>>>
>>>> Would anyone be interested in adding std::shift to <algorithm>?
>>>>
>>>> It would be similar to both:
>>>> - std::rotate, but without moving the head elements back to the tail.
>>>> This would allow a more efficient implementation and clearer semantics=
 in
>>>> case rotation is not needed as well as correctness in case rotation is
>>>> undesired.
>>>> - <algorithm>'s std::move/std::move_backward (depending on the shift
>>>> direction).
>>>>
>>>> std::shift should probably accommodate both left and right shifts by
>>>> one of:
>>>> - giving it either begin() and end(), or rbegin() and rend(), similar
>>>> to how std::rotate works for both left and right rotations. The advant=
age
>>>> is compactness of the implementation.
>>>> - allowing the shift count parameter to be either positive or negative=
..
>>>> The advantage is compactness, though it might not be clear which direc=
tion
>>>> is which - to be consistent with rotate, positive integers should shif=
t to
>>>> the left.
>>>> - having std::shift_right and std::shift_left functions. The advantage
>>>> is clarity when calling the methods, although the same argument could =
be
>>>> made for having separate std::rotate_left and std::rotate_right instea=
d of
>>>> std::rotate, which we don't have.
>>>>
>>>
>>> std::rotate is actually just a rotation; it doesn't need "left" or
>>> "right" qualification because they're 100% equivalent. Consider a class=
room
>>> globe with London in front, facing you. Now "rotate" the globe until
>>> Beijing is in front. It doesn't matter if you rotate left or rotate rig=
ht;
>>> the outcome is exactly the same either way.
>>>
>>>
>>>> Here's a sample implementation of a shift to the right direction:
>>>>
>>>> template<class BidirIt>
>>>> void shift_right(BidirIt first, BidirIt last, unsigned int n =3D 1)
>>>> {
>>>>     std::move_backward(first, last - n, last);
>>>> }
>>>>
>>>> This demonstrates that while std::shift is implementable with
>>>> std::move/std::move_backward,
>>>> 1) It isn't immediately clear from the code (at least to my eyes) that
>>>> this is a shift right, unless you are intimately familiar with
>>>> std::move_backward.
>>>> 2) Different calls, either to std::move or to std::move_backward, are
>>>> required, depending on the shift direction.
>>>>
>>>
>>> If you're shifting the whole container's contents, you could use either
>>> of these:
>>>     std::move(ctr.rbegin() + n, ctr.rend(), ctr.rbegin());
>>>     std::move_backward(ctr.begin(), ctr.end() - n, ctr.end())?
>>> I don't currently see the use-case for this "shift just a piece of a
>>> container" algorithm, I mean as distinct from std::move and
>>> std::move_backward which already exist. Do you have a use-case?
>>>
>>
>> The use-case would be anytime you'd want to use the code you just wrote.
>> When you have a range and N, and you want to do a shift N units in that
>> direction.
>>
>> The point of having it is one of clarification and user expectations.
>> Yes, you can use `move` and `move_backward` to accomplish a shift. But
>> consider the two function calls:
>>
>> //A
>> std::shift(rng.begin(), rng.end(), N);
>>
>> //B
>> auto rrng =3D std::make_reverse_range(rng);
>> std::move(rrng.begin() + N, rrng.end(), rrng.begin());
>>
>> A and B both do the same thing. But it's a *lot easier* to figure out
>> what the code is actually accomplishing from looking at A than B.
>>
>
> Do you have a use-case for either of these?
> I recall your admonition cross-thread that generally in the STL we *don't=
*
> want to operate on containers but rather on ranges (or iterator-pairs); s=
o
> if I had a range that I wanted to "shift", I would first consider whether=
 I
> could do something like
>
>     // OLD: shift_in_place(range, n); operate_on(range.begin(),
> range.end());
>     // NEW: operate_on(range.begin() + n, range.end());
>
> That is, instead of moving the actual data, which might be slow, I'd move
> one or the other "endpoint" while leaving the data in place.
> In his reply, Dan Raviv mentioned that this is exactly the kind of thing
> that a circular buffer does, and he's right (see proposal P0059).
>
> I also wrote that sometimes the circular buffer is less desirable than
just shifting the data.


>
> B gets even more obtuse confusing in a range-based world:
>>
>> //A
>> std::shift(rng, N);
>>
>> //B
>> auto rrng =3D std::make_reverse_range(rng);
>> std::move(std::make_range(rrng.begin + N, rrng.end()), rrng.begin());
>>
>
> In a range-based world, I would write this as
>
>     auto output =3D input | rng::drop(n);
>
> for a "left-shift", or... okay, the "right-shift" version is messy, at
> least in my version, because it involves concatenating ranges one of whic=
h
> needs to be created out of whole cloth, with n objects, each of which is =
in
> a "valid but unspecified" state.  (I'd bet *money* you can't give me a
> use-case for *that* one.)
>
> I'd still like to see a use-case for O(n) "shifting" a sequence of
> elements in-place (as opposed to using one of these range-based approache=
s,
> or using a circular buffer, or "shifting the endpoints").  I agree that
> sometimes you do want to copy/move the second part of a sequence over the
> first part, but I would always express that in terms of "I'm std::copy'in=
g
> / std::move'ing data." Expressing it as a "shift" doesn't feel natural to
> me in any of the (extremely rare) use-cases I've thought of. Do you have =
a
> use-case?
>
> Expressing a shift (either forward or backward) seems more natural to me
then copying or moving, which are generic operations, but require more
effort on the reader's part in case they are used for a simple shift. And
as I mentioned, a common use case in DSP for shifting is time series
analysis.


> =E2=80=93Arthur
>
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<div dir=3D"ltr"><br><div class=3D"gmail_extra"><br><div class=3D"gmail_quo=
te">On Thu, Jul 13, 2017 at 8:21 PM, Arthur O&#39;Dwyer <span dir=3D"ltr">&=
lt;<a href=3D"mailto:arthur.j.odwyer@gmail.com" target=3D"_blank">arthur.j.=
odwyer@gmail.com</a>&gt;</span> wrote:<br><blockquote class=3D"gmail_quote"=
 style=3D"margin:0px 0px 0px 0.8ex;border-left-width:1px;border-left-style:=
solid;border-left-color:rgb(204,204,204);padding-left:1ex"><div dir=3D"ltr"=
><div><div class=3D"gmail-h5">On Wednesday, July 12, 2017 at 6:43:11 PM UTC=
-7, Nicol Bolas wrote:<blockquote class=3D"gmail_quote" style=3D"margin:0px=
 0px 0px 0.8ex;border-left-width:1px;border-left-style:solid;border-left-co=
lor:rgb(204,204,204);padding-left:1ex"><div dir=3D"ltr">On Wednesday, July =
12, 2017 at 7:47:05 PM UTC-4, Arthur O&#39;Dwyer wrote:<blockquote class=3D=
"gmail_quote" style=3D"margin:0px 0px 0px 0.8ex;border-left-width:1px;borde=
r-left-style:solid;border-left-color:rgb(204,204,204);padding-left:1ex"><di=
v dir=3D"ltr">On Wednesday, July 12, 2017 at 2:53:19 AM UTC-7, <a>d...@soun=
dradix.com</a> wrote:<blockquote class=3D"gmail_quote" style=3D"margin:0px =
0px 0px 0.8ex;border-left-width:1px;border-left-style:solid;border-left-col=
or:rgb(204,204,204);padding-left:1ex"><div dir=3D"ltr">Hi,<div><br></div><d=
iv>Would anyone be interested in adding std::shift to &lt;algorithm&gt;?=C2=
=A0</div><div><br></div><div>It would be similar to both:</div><div>- std::=
rotate, but without moving the head elements back to the tail. This would a=
llow a more efficient implementation and clearer semantics in case rotation=
 is not needed as well as correctness in case rotation is undesired.</div><=
div>- &lt;algorithm&gt;&#39;s std::move/std::move_backward (depending on th=
e shift direction).</div><div><br></div><div>std::shift should probably acc=
ommodate both left and right shifts by one of:</div><div>- giving it either=
 begin() and end(), or rbegin() and rend(), similar to how std::rotate work=
s for both left and right rotations. The advantage is compactness of the im=
plementation.</div><div>- allowing the shift count parameter to be either p=
ositive or negative. The advantage is compactness, though it might not be c=
lear which direction is which - to be consistent with rotate, positive inte=
gers should shift to the left.<br></div><div><div>- having std::shift_right=
 and std::shift_left functions. The advantage is clarity when calling the m=
ethods, although the same argument could be made for having separate std::r=
otate_left and std::rotate_right instead of std::rotate, which we don&#39;t=
 have.</div></div></div></blockquote><div><br></div><div>std::rotate is act=
ually just a rotation; it doesn&#39;t need &quot;left&quot; or &quot;right&=
quot; qualification because they&#39;re 100% equivalent. Consider a classro=
om globe with London in front, facing you. Now &quot;rotate&quot; the globe=
 until Beijing is in front. It doesn&#39;t matter if you rotate left or rot=
ate right; the outcome is exactly the same either way.</div><div>=C2=A0</di=
v><blockquote class=3D"gmail_quote" style=3D"margin:0px 0px 0px 0.8ex;borde=
r-left-width:1px;border-left-style:solid;border-left-color:rgb(204,204,204)=
;padding-left:1ex"><div dir=3D"ltr"><div>Here&#39;s a sample implementation=
 of a shift to the right direction:<br></div><br><div style=3D"background-c=
olor:rgb(250,250,250);border:1px solid rgb(187,187,187);word-wrap:break-wor=
d"><code><div><span style=3D"color:rgb(0,0,136)">template</span><span style=
=3D"color:rgb(102,102,0)">&lt;</span><span style=3D"color:rgb(0,0,136)">cla=
ss</span><span style=3D"color:rgb(0,0,0)"> </span><span style=3D"color:rgb(=
102,0,102)">BidirIt</span><span style=3D"color:rgb(102,102,0)">&gt;</span><=
span style=3D"color:rgb(0,0,0)"> <br></span><span style=3D"color:rgb(0,0,13=
6)">void</span><span style=3D"color:rgb(0,0,0)"> shift_right</span><span st=
yle=3D"color:rgb(102,102,0)">(</span><span style=3D"color:rgb(102,0,102)">B=
idirIt</span><span style=3D"color:rgb(0,0,0)"> first</span><span style=3D"c=
olor:rgb(102,102,0)">,</span><span style=3D"color:rgb(0,0,0)"> </span><span=
 style=3D"color:rgb(102,0,102)">BidirIt</span><span style=3D"color:rgb(0,0,=
0)"> </span><span style=3D"color:rgb(0,0,136)">last</span><span style=3D"co=
lor:rgb(102,102,0)">,</span><span style=3D"color:rgb(0,0,0)"> </span><span =
style=3D"color:rgb(0,0,136)">unsigned</span><span style=3D"color:rgb(0,0,0)=
"> </span><span style=3D"color:rgb(0,0,136)">int</span><span style=3D"color=
:rgb(0,0,0)"> n </span><span style=3D"color:rgb(102,102,0)">=3D</span><span=
 style=3D"color:rgb(0,0,0)"> </span><span style=3D"color:rgb(0,102,102)">1<=
/span><span style=3D"color:rgb(102,102,0)">)</span><span style=3D"color:rgb=
(0,0,0)"> <br></span><span style=3D"color:rgb(102,102,0)">{</span><span sty=
le=3D"color:rgb(0,0,0)"> <br>=C2=A0 =C2=A0 std</span><span style=3D"color:r=
gb(102,102,0)">::</span><span style=3D"color:rgb(0,0,0)">move_backward</spa=
n><span style=3D"color:rgb(102,102,0)">(</span><span style=3D"color:rgb(0,0=
,0)">first</span><span style=3D"color:rgb(102,102,0)">,</span><span style=
=3D"color:rgb(0,0,0)"> </span><span style=3D"color:rgb(0,0,136)">last</span=
><span style=3D"color:rgb(0,0,0)"> </span><span style=3D"color:rgb(102,102,=
0)">-</span><span style=3D"color:rgb(0,0,0)"> n</span><span style=3D"color:=
rgb(102,102,0)">,</span><span style=3D"color:rgb(0,0,0)"> </span><span styl=
e=3D"color:rgb(0,0,136)">last</span><span style=3D"color:rgb(102,102,0)">);=
</span><span style=3D"color:rgb(0,0,0)"> <br></span><span style=3D"color:rg=
b(102,102,0)">}</span><span style=3D"color:rgb(0,0,0)"><br></span></div></c=
ode></div><div><br></div><div>This demonstrates that while std::shift is im=
plementable with std::move/std::move_backward,</div><div>1) It isn&#39;t im=
mediately clear from the code (at least to my eyes) that this is a shift ri=
ght, unless you are intimately familiar with std::move_backward.</div><div>=
2) Different calls, either to std::move or to std::move_backward, are requi=
red, depending on the shift direction.</div></div></blockquote><div><br></d=
iv><div>If you&#39;re shifting the whole container&#39;s contents, you coul=
d use either of these:</div><div>=C2=A0 =C2=A0 std::move(ctr.rbegin() + n, =
ctr.rend(), ctr.rbegin());</div><div>=C2=A0 =C2=A0 std::move_backward(ctr.b=
egin()<wbr>, ctr.end() - n, ctr.end())?</div><div>I don&#39;t currently see=
 the use-case for this &quot;shift just a piece of a container&quot; algori=
thm, I mean as distinct from std::move and std::move_backward which already=
 exist. Do you have a use-case?</div></div></blockquote><div><br>The use-ca=
se would be anytime you&#39;d want to use the code you just wrote. When you=
 have a range and N, and you want to do a shift N units in that direction.<=
br><br>The point of having it is one of clarification and user expectations=
.. Yes, you can use `move` and `move_backward` to accomplish a shift. But co=
nsider the two function calls:<br><br><div style=3D"background-color:rgb(25=
0,250,250);border:1px solid rgb(187,187,187)"><code><div><span style=3D"col=
or:rgb(136,0,0)">//A</span><span style=3D"color:rgb(0,0,0)"><br>std</span><=
span style=3D"color:rgb(102,102,0)">::</span><span style=3D"color:rgb(0,0,0=
)">shift</span><span style=3D"color:rgb(102,102,0)">(</span><span style=3D"=
color:rgb(0,0,0)">rng</span><span style=3D"color:rgb(102,102,0)">.</span><s=
pan style=3D"color:rgb(0,0,136)">begin</span><span style=3D"color:rgb(102,1=
02,0)">(),</span><span style=3D"color:rgb(0,0,0)"> rng</span><span style=3D=
"color:rgb(102,102,0)">.</span><span style=3D"color:rgb(0,0,136)">end</span=
><span style=3D"color:rgb(102,102,0)">(),</span><span style=3D"color:rgb(0,=
0,0)"> N</span><span style=3D"color:rgb(102,102,0)">);</span><span style=3D=
"color:rgb(0,0,0)"><br><br></span><span style=3D"color:rgb(136,0,0)">//B</s=
pan><span style=3D"color:rgb(0,0,0)"><br></span><span style=3D"color:rgb(0,=
0,136)">auto</span><span style=3D"color:rgb(0,0,0)"> rrng </span><span styl=
e=3D"color:rgb(102,102,0)">=3D</span><span style=3D"color:rgb(0,0,0)"> std<=
/span><span style=3D"color:rgb(102,102,0)">::</span><span style=3D"color:rg=
b(0,0,0)">make_reverse_range</span><span style=3D"color:rgb(102,102,0)">(</=
span><span style=3D"color:rgb(0,0,0)">rng</span><span style=3D"color:rgb(10=
2,102,0)">);</span><span style=3D"color:rgb(0,0,0)"><br>std</span><span sty=
le=3D"color:rgb(102,102,0)">::</span><span style=3D"color:rgb(0,0,0)">move<=
/span><span style=3D"color:rgb(102,102,0)">(</span><span style=3D"color:rgb=
(0,0,0)">rrng</span><span style=3D"color:rgb(102,102,0)">.</span><span styl=
e=3D"color:rgb(0,0,136)">begin</span><span style=3D"color:rgb(102,102,0)">(=
)</span><span style=3D"color:rgb(0,0,0)"> </span><span style=3D"color:rgb(1=
02,102,0)">+</span><span style=3D"color:rgb(0,0,0)"> N</span><span style=3D=
"color:rgb(102,102,0)">,</span><span style=3D"color:rgb(0,0,0)"> rrng</span=
><span style=3D"color:rgb(102,102,0)">.</span><span style=3D"color:rgb(0,0,=
136)">end</span><span style=3D"color:rgb(102,102,0)">(),</span><span style=
=3D"color:rgb(0,0,0)"> rrng</span><span style=3D"color:rgb(102,102,0)">.</s=
pan><span style=3D"color:rgb(0,0,136)">begin</span><span style=3D"color:rgb=
(102,102,0)">());</span></div></code></div><br>A and B both do the same thi=
ng. But it&#39;s a <i>lot easier</i> to figure out what the code is actuall=
y accomplishing from looking at A than B.<br></div></div></blockquote><div>=
<br></div></div></div><div>Do you have a use-case for either of these?</div=
><div>I recall your admonition cross-thread that generally in the STL we *d=
on&#39;t* want to operate on containers but rather on ranges (or iterator-p=
airs); so if I had a range that I wanted to &quot;shift&quot;, I would firs=
t consider whether I could do something like</div><div><br></div><div>=C2=
=A0 =C2=A0 // OLD: shift_in_place(range, n); operate_on(range.begin(), rang=
e.end());</div><div>=C2=A0 =C2=A0 // NEW: operate_on(range.begin() + n, ran=
ge.end());</div><div><br></div><div>That is, instead of moving the actual d=
ata, which might be slow, I&#39;d move one or the other &quot;endpoint&quot=
; while leaving the data in place.</div><div>In his reply, Dan Raviv mentio=
ned that this is exactly the kind of thing that a circular buffer does, and=
 he&#39;s right (see proposal P0059).</div><span class=3D"gmail-"><div><br>=
</div></span></div></blockquote><div><span style=3D"font-size:12.8000001907=
34863px">I also wrote that sometimes the circular buffer is less desirable =
than just shifting the data.</span></div><div><span style=3D"font-size:12.8=
00000190734863px"><br></span></div><blockquote class=3D"gmail_quote" style=
=3D"margin:0px 0px 0px 0.8ex;border-left-width:1px;border-left-style:solid;=
border-left-color:rgb(204,204,204);padding-left:1ex"><div dir=3D"ltr"><span=
 class=3D"gmail-"><div></div><div><br></div><div><br></div><blockquote clas=
s=3D"gmail_quote" style=3D"margin:0px 0px 0px 0.8ex;border-left-width:1px;b=
order-left-style:solid;border-left-color:rgb(204,204,204);padding-left:1ex"=
><div dir=3D"ltr"><div>B gets even more obtuse confusing in a range-based w=
orld:<br><br><div style=3D"background-color:rgb(250,250,250);border:1px sol=
id rgb(187,187,187)"><code><div><span style=3D"color:rgb(136,0,0)">//A</spa=
n><span style=3D"color:rgb(0,0,0)"><br>std</span><span style=3D"color:rgb(1=
02,102,0)">::</span><span style=3D"color:rgb(0,0,0)">shift</span><span styl=
e=3D"color:rgb(102,102,0)">(</span><span style=3D"color:rgb(0,0,0)">rng</sp=
an><span style=3D"color:rgb(102,102,0)">,</span><span style=3D"color:rgb(0,=
0,0)"> N</span><span style=3D"color:rgb(102,102,0)">);</span><span style=3D=
"color:rgb(0,0,0)"><br><br></span><span style=3D"color:rgb(136,0,0)">//B</s=
pan><span style=3D"color:rgb(0,0,0)"><br></span><span style=3D"color:rgb(0,=
0,136)">auto</span><span style=3D"color:rgb(0,0,0)"> rrng </span><span styl=
e=3D"color:rgb(102,102,0)">=3D</span><span style=3D"color:rgb(0,0,0)"> std<=
/span><span style=3D"color:rgb(102,102,0)">::</span><span style=3D"color:rg=
b(0,0,0)">make_reverse_range</span><span style=3D"color:rgb(102,102,0)">(</=
span><span style=3D"color:rgb(0,0,0)">rng</span><span style=3D"color:rgb(10=
2,102,0)">);</span><span style=3D"color:rgb(0,0,0)"><br>std</span><span sty=
le=3D"color:rgb(102,102,0)">::</span><span style=3D"color:rgb(0,0,0)">move<=
/span><span style=3D"color:rgb(102,102,0)">(</span><span style=3D"color:rgb=
(0,0,0)">std</span><span style=3D"color:rgb(102,102,0)">::</span><span styl=
e=3D"color:rgb(0,0,0)">make_range</span><span style=3D"color:rgb(102,102,0)=
">(</span><span style=3D"color:rgb(0,0,0)">rrng</span><span style=3D"color:=
rgb(102,102,0)"><wbr>.</span><span style=3D"color:rgb(0,0,136)">begin</span=
><span style=3D"color:rgb(0,0,0)"> </span><span style=3D"color:rgb(102,102,=
0)">+</span><span style=3D"color:rgb(0,0,0)"> N</span><span style=3D"color:=
rgb(102,102,0)">,</span><span style=3D"color:rgb(0,0,0)"> rrng</span><span =
style=3D"color:rgb(102,102,0)">.</span><span style=3D"color:rgb(0,0,136)">e=
nd</span><span style=3D"color:rgb(102,102,0)">()),</span><span style=3D"col=
or:rgb(0,0,0)"> rrng</span><span style=3D"color:rgb(102,102,0)">.</span><sp=
an style=3D"color:rgb(0,0,136)">begin</span><span style=3D"color:rgb(102,10=
2,0)">());</span></div></code></div></div></div></blockquote><div><br></div=
></span><div>In a range-based world, I would write this as</div><div><br></=
div><div>=C2=A0 =C2=A0 auto output =3D input | rng::drop(n);</div><div><br>=
</div><div>for a &quot;left-shift&quot;, or... okay, the &quot;right-shift&=
quot; version is messy, at least in my version, because it involves concate=
nating ranges one of which needs to be created out of whole cloth, with n o=
bjects, each of which is in a &quot;valid but unspecified&quot; state. =C2=
=A0(I&#39;d bet <i>money</i> you can&#39;t give me a use-case for <i>that</=
i> one.)</div><div><br></div><div>I&#39;d still like to see a use-case for =
O(n) &quot;shifting&quot; a sequence of elements in-place (as opposed to us=
ing one of these range-based approaches, or using a circular buffer, or &qu=
ot;shifting the endpoints&quot;).=C2=A0 I agree that sometimes you do want =
to copy/move the second part of a sequence over the first part, but I would=
 always express that in terms of &quot;I&#39;m std::copy&#39;ing / std::mov=
e&#39;ing data.&quot; Expressing it as a &quot;shift&quot; doesn&#39;t feel=
 natural to me in any of the (extremely rare) use-cases I&#39;ve thought of=
.. Do you have a use-case?</div><div><br></div></div></blockquote><div>Expre=
ssing a shift (either forward or backward) seems more natural to me then co=
pying or moving, which are generic operations, but require more effort on t=
he reader&#39;s part in case they are used for a simple shift. And as I men=
tioned, a common use case in DSP for shifting is time series analysis.</div=
><div>=C2=A0</div><blockquote class=3D"gmail_quote" style=3D"margin:0px 0px=
 0px 0.8ex;border-left-width:1px;border-left-style:solid;border-left-color:=
rgb(204,204,204);padding-left:1ex"><div dir=3D"ltr"><div></div><div>=E2=80=
=93Arthur</div></div><span class=3D"gmail-">

<p></p>

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Does anyone know if there was a specific motivation for adding
std::move_backward() to <algorithm>? It seems that using std::move() with
rbegin(),rend() iterators (for the basic use case) would have the same
effect.

On Wednesday, July 12, 2017 at 12:53:19 PM UTC+3, d...@soundradix.com wrote:
>
> Hi,
>
> Would anyone be interested in adding std::shift to <algorithm>?
>
> It would be similar to both:
> - std::rotate, but without moving the head elements back to the tail. This
> would allow a more efficient implementation and clearer semantics in case
> rotation is not needed as well as correctness in case rotation is undesired.
> - <algorithm>'s std::move/std::move_backward (depending on the shift
> direction).
>
> std::shift should probably accommodate both left and right shifts by one
> of:
> - giving it either begin() and end(), or rbegin() and rend(), similar to
> how std::rotate works for both left and right rotations. The advantage is
> compactness of the implementation.
> - allowing the shift count parameter to be either positive or negative.
> The advantage is compactness, though it might not be clear which direction
> is which - to be consistent with rotate, positive integers should shift to
> the left.
> - having std::shift_right and std::shift_left functions. The advantage is
> clarity when calling the methods, although the same argument could be made
> for having separate std::rotate_left and std::rotate_right instead of
> std::rotate, which we don't have.
>
> Here's a sample implementation of a shift to the right direction:
>
> template<class BidirIt>
> void shift_right(BidirIt first, BidirIt last, unsigned int n = 1)
> {
>     std::move_backward(first, last - n, last);
> }
>
> This demonstrates that while std::shift is implementable with
> std::move/std::move_backward,
> 1) It isn't immediately clear from the code (at least to my eyes) that
> this is a shift right, unless you are intimately familiar with
> std::move_backward.
> 2) Different calls, either to std::move or to std::move_backward, are
> required, depending on the shift direction.
>
> So, implementing std::shift would allow writing more readable code.
>
> Thanks,
> Dan
>

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<div dir=3D"ltr">Does anyone know if there was a specific motivation for ad=
ding std::move_backward() to &lt;algorithm&gt;? It seems that using std::mo=
ve() with rbegin(),rend() iterators (for the basic use case) would have the=
 same effect.<br><br>On Wednesday, July 12, 2017 at 12:53:19 PM UTC+3, d...=
@soundradix.com wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;=
margin-left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=
=3D"ltr">Hi,<div><br></div><div>Would anyone be interested in adding std::s=
hift to &lt;algorithm&gt;?=C2=A0</div><div><br></div><div>It would be simil=
ar to both:</div><div>- std::rotate, but without moving the head elements b=
ack to the tail. This would allow a more efficient implementation and clear=
er semantics in case rotation is not needed as well as correctness in case =
rotation is undesired.</div><div>- &lt;algorithm&gt;&#39;s std::move/std::m=
ove_backward (depending on the shift direction).</div><div><br></div><div>s=
td::shift should probably accommodate both left and right shifts by one of:=
</div><div>- giving it either begin() and end(), or rbegin() and rend(), si=
milar to how std::rotate works for both left and right rotations. The advan=
tage is compactness of the implementation.</div><div>- allowing the shift c=
ount parameter to be either positive or negative. The advantage is compactn=
ess, though it might not be clear which direction is which - to be consiste=
nt with rotate, positive integers should shift to the left.<br></div><div><=
div>- having std::shift_right and std::shift_left functions. The advantage =
is clarity when calling the methods, although the same argument could be ma=
de for having separate std::rotate_left and std::rotate_right instead of st=
d::rotate, which we don&#39;t have.</div></div><div><br></div><div>Here&#39=
;s a sample implementation of a shift to the right direction:</div><br><div=
 style=3D"background-color:rgb(250,250,250);border:1px solid rgb(187,187,18=
7);word-wrap:break-word"><code><div><span style=3D"color:#008">template</sp=
an><span style=3D"color:#660">&lt;</span><span style=3D"color:#008">class</=
span><span style=3D"color:#000"> </span><span style=3D"color:#606">BidirIt<=
/span><span style=3D"color:#660">&gt;</span><span style=3D"color:#000"> <br=
></span><span style=3D"color:#008">void</span><span style=3D"color:#000"> s=
hift_right</span><span style=3D"color:#660">(</span><span style=3D"color:#6=
06">BidirIt</span><span style=3D"color:#000"> first</span><span style=3D"co=
lor:#660">,</span><span style=3D"color:#000"> </span><span style=3D"color:#=
606">BidirIt</span><span style=3D"color:#000"> </span><span style=3D"color:=
#008">last</span><span style=3D"color:#660">,</span><span style=3D"color:#0=
00"> </span><span style=3D"color:#008">unsigned</span><span style=3D"color:=
#000"> </span><span style=3D"color:#008">int</span><span style=3D"color:#00=
0"> n </span><span style=3D"color:#660">=3D</span><span style=3D"color:#000=
"> </span><span style=3D"color:#066">1</span><span style=3D"color:#660">)</=
span><span style=3D"color:#000"> <br></span><span style=3D"color:#660">{</s=
pan><span style=3D"color:#000"> <br>=C2=A0 =C2=A0 std</span><span style=3D"=
color:#660">::</span><span style=3D"color:#000">move_backward</span><span s=
tyle=3D"color:#660">(</span><span style=3D"color:#000">first</span><span st=
yle=3D"color:#660">,</span><span style=3D"color:#000"> </span><span style=
=3D"color:#008">last</span><span style=3D"color:#000"> </span><span style=
=3D"color:#660">-</span><span style=3D"color:#000"> n</span><span style=3D"=
color:#660">,</span><span style=3D"color:#000"> </span><span style=3D"color=
:#008">last</span><span style=3D"color:#660">);</span><span style=3D"color:=
#000"> <br></span><span style=3D"color:#660">}</span><span style=3D"color:#=
000"><br></span></div></code></div><div><br></div><div>This demonstrates th=
at while std::shift is implementable with std::move/std::move_backward,</di=
v><div>1) It isn&#39;t immediately clear from the code (at least to my eyes=
) that this is a shift right, unless you are intimately familiar with std::=
move_backward.</div><div>2) Different calls, either to std::move or to std:=
:move_backward, are required, depending on the shift direction.</div><div><=
br></div><div>So, implementing std::shift would allow writing more readable=
 code.</div><div><br></div><div>Thanks,</div><div>Dan</div></div></blockquo=
te></div>

<p></p>

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On Friday, July 28, 2017 at 2:43:10 PM UTC-4, Dan Raviv wrote:
>
> Does anyone know if there was a specific motivation for adding
> std::move_backward() to <algorithm>? It seems that using std::move() with
> rbegin(),rend() iterators (for the basic use case) would have the same
> effect.
>

First, reverse iterators have a tendency to be opaque. That is, you can't
effectively optimize through them. If `value_type` were trivially-copyable
and move-assignable, and the iterators would have been contiguous
(pointers, etc), you wouldn't be able to move them with a memcpy/memmove.
You could only do the standard one-element-at-a-time thing.

Second, your `rbegin/rend` idea only is useful if you have a container. If
you just have a pair of iterators, then reversing them is a bit harder, and
it requires putting them in backwards. Whereas `move_backward` pretty much
tells the story of what you want.

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<div dir=3D"ltr">On Friday, July 28, 2017 at 2:43:10 PM UTC-4, Dan Raviv wr=
ote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;margin-left: 0.8ex=
;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"ltr">Does anyo=
ne know if there was a specific motivation for adding std::move_backward() =
to &lt;algorithm&gt;? It seems that using std::move() with rbegin(),rend() =
iterators (for the basic use case) would have the same effect.<br></div></b=
lockquote><div><br>First, reverse iterators have a tendency to be opaque. T=
hat is, you can&#39;t effectively optimize through them. If `value_type` we=
re trivially-copyable and move-assignable, and the iterators would have bee=
n contiguous (pointers, etc), you wouldn&#39;t be able to move them with a =
memcpy/memmove. You could only do the standard one-element-at-a-time thing.=
<br><br>Second, your `rbegin/rend` idea only is useful if you have a contai=
ner. If you just have a pair of iterators, then reversing them is a bit har=
der, and it requires putting them in backwards. Whereas `move_backward` pre=
tty much tells the story of what you want.</div></div>

<p></p>

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On Jul 28, 2017, at 2:43 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>
> Does anyone know if there was a specific motivation for adding std::move_backward() to <algorithm>? It seems that using std::move() with rbegin(),rend() iterators (for the basic use case) would have the same effect.

See http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2005/n1771.html

Section 25 - Algorithms library

Howard

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.

I see.

Then, isn't there a need for, e.g., an std::rotate_right function to augmen=
t the existing rotate(_left) algorithm, since rotating right can only be ac=
hieved through using reverse iterators? Or is the existing std::rotate desi=
gned so it can optimize for reverse iterators as well?

Thanks,
Dan

> On 28 Jul 2017, at 22:19, Howard Hinnant <howard.hinnant@gmail.com> wrote=
:
>=20
>> On Jul 28, 2017, at 2:43 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>>=20
>> Does anyone know if there was a specific motivation for adding std::move=
_backward() to <algorithm>? It seems that using std::move() with rbegin(),r=
end() iterators (for the basic use case) would have the same effect.
>=20
> See http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2005/n1771.html
>=20
> Section 25 - Algorithms library
>=20
> Howard
>=20
> --=20
> You received this message because you are subscribed to the Google Groups=
 "ISO C++ Standard - Future Proposals" group.
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 email to std-proposals+unsubscribe@isocpp.org.
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pp.org/d/msgid/std-proposals/94CDFCD7-3F9D-4D7E-BDD7-58D27561C291%40gmail.c=
om.

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..

.

It looks like that section mentions the addition of std::move_backward, but not the rationale for adding it in addition to std::move. Or am I missing something?

Thanks,
Dan

> On 28 Jul 2017, at 22:19, Howard Hinnant <howard.hinnant@gmail.com> wrote:
>
>> On Jul 28, 2017, at 2:43 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>>
>> Does anyone know if there was a specific motivation for adding std::move_backward() to <algorithm>? It seems that using std::move() with rbegin(),rend() iterators (for the basic use case) would have the same effect.
>
> See http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2005/n1771.html
>
> Section 25 - Algorithms library
>
> Howard
>
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No one is claiming that <algorithm> is a complete set of all useful functio=
ns.  But no, I don=E2=80=99t see a need for rotate_right.  I find std::rota=
te easier to visualize when I call it swap_unequal_ranges.

Howard

On Jul 28, 2017, at 4:50 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>=20
> I see.
>=20
> Then, isn't there a need for, e.g., an std::rotate_right function to augm=
ent the existing rotate(_left) algorithm, since rotating right can only be =
achieved through using reverse iterators? Or is the existing std::rotate de=
signed so it can optimize for reverse iterators as well?
>=20
> Thanks,
> Dan
>=20
>> On 28 Jul 2017, at 22:19, Howard Hinnant <howard.hinnant@gmail.com> wrot=
e:
>>=20
>>> On Jul 28, 2017, at 2:43 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>>>=20
>>> Does anyone know if there was a specific motivation for adding std::mov=
e_backward() to <algorithm>? It seems that using std::move() with rbegin(),=
rend() iterators (for the basic use case) would have the same effect.
>>=20
>> See http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2005/n1771.html
>>=20
>> Section 25 - Algorithms library
>>=20
>> Howard
>>=20
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>=20
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From the paper:

> move and move_backward are two new algorithms to augment copy and copy_ba=
ckward. They require only that the value_type be MoveAssignable (recall tha=
t CopyAssignable types are MoveAssignable). Strictly speaking the functiona=
lity could be obtained with the combination of copy (or copy_backward) and =
move_iterator, however the anticipated frequency of use of these functions =
indicates that the syntactic convenience of these functions is warranted.

The last sentence applies to both of the new algorithms.

Howard

On Jul 28, 2017, at 4:51 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>=20
> It looks like that section mentions the addition of std::move_backward, b=
ut not the rationale for adding it in addition to std::move. Or am I missin=
g something?
>=20
> Thanks,
> Dan
>=20
>> On 28 Jul 2017, at 22:19, Howard Hinnant <howard.hinnant@gmail.com> wrot=
e:
>>=20
>>> On Jul 28, 2017, at 2:43 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>>>=20
>>> Does anyone know if there was a specific motivation for adding std::mov=
e_backward() to <algorithm>? It seems that using std::move() with rbegin(),=
rend() iterators (for the basic use case) would have the same effect.
>>=20
>> See http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2005/n1771.html
>>=20
>> Section 25 - Algorithms library
>>=20
>> Howard
>>=20
>> --
>> You received this message because you are subscribed to the Google Group=
s "ISO C++ Standard - Future Proposals" group.
>> To unsubscribe from this group and stop receiving emails from it, send a=
n email to std-proposals+unsubscribe@isocpp.org.
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cpp.org/d/msgid/std-proposals/94CDFCD7-3F9D-4D7E-BDD7-58D27561C291%40gmail.=
com.
>=20
> --
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.

Ok, so why the need for copy_backward in addition to copy (since copy could=
 be used instead with reverse iterators/pointers)? Is this mostly an optimi=
zation issue, as Nicol says? (I guess so because it seems he is always corr=
ect) :) But it would be great to get your perspective on this too Howard.

Thanks!
Dan

> On 29 Jul 2017, at 0:15, Howard Hinnant <howard.hinnant@gmail.com> wrote:
>=20
> From the paper:
>=20
>> move and move_backward are two new algorithms to augment copy and copy_b=
ackward. They require only that the value_type be MoveAssignable (recall th=
at CopyAssignable types are MoveAssignable). Strictly speaking the function=
ality could be obtained with the combination of copy (or copy_backward) and=
 move_iterator, however the anticipated frequency of use of these functions=
 indicates that the syntactic convenience of these functions is warranted.
>=20
> The last sentence applies to both of the new algorithms.
>=20
> Howard
>=20
>> On Jul 28, 2017, at 4:51 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>>=20
>> It looks like that section mentions the addition of std::move_backward, =
but not the rationale for adding it in addition to std::move. Or am I missi=
ng something?
>>=20
>> Thanks,
>> Dan
>>=20
>>>> On 28 Jul 2017, at 22:19, Howard Hinnant <howard.hinnant@gmail.com> wr=
ote:
>>>>=20
>>>> On Jul 28, 2017, at 2:43 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>>>>=20
>>>> Does anyone know if there was a specific motivation for adding std::mo=
ve_backward() to <algorithm>? It seems that using std::move() with rbegin()=
,rend() iterators (for the basic use case) would have the same effect.
>>>=20
>>> See http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2005/n1771.html
>>>=20
>>> Section 25 - Algorithms library
>>>=20
>>> Howard
>>>=20
>>> --
>>> You received this message because you are subscribed to the Google Grou=
ps "ISO C++ Standard - Future Proposals" group.
>>> To unsubscribe from this group and stop receiving emails from it, send =
an email to std-proposals+unsubscribe@isocpp.org.
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ocpp.org/d/msgid/std-proposals/94CDFCD7-3F9D-4D7E-BDD7-58D27561C291%40gmail=
..com.
>>=20
>> --
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cpp.org/d/msgid/std-proposals/96DEA673-B79C-4D08-AE8E-EFFCA3C5A0E8%40gmail.=
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>=20
> --=20
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On Jul 28, 2017, at 5:45 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>=20
> Ok, so why the need for copy_backward in addition to copy (since copy cou=
ld be used instead with reverse iterators/pointers)? Is this mostly an opti=
mization issue, as Nicol says? (I guess so because it seems he is always co=
rrect) :) But it would be great to get your perspective on this too Howard.

copy_backward predates my participation in the standardization process, and=
 I would prefer not to speculate.

I do note that the code gen using the latest clang at -O3 is much worse for=
 copy+reverse_iterator than for copy_backward using int* as the base iterat=
or.

Howard

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.

------=_Part_2779_651351720.1501348741489
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Hi,

Attached a proposal draft with reasoning and sample implementation (but
still no complete design and standard wording).
Would appreciate any feedback!

Thanks,
Dan

On Wednesday, July 12, 2017 at 12:53:19 PM UTC+3, d...@soundradix.com wrote:
>
> Hi,
>
> Would anyone be interested in adding std::shift to <algorithm>?
>
> It would be similar to both:
> - std::rotate, but without moving the head elements back to the tail. This
> would allow a more efficient implementation and clearer semantics in case
> rotation is not needed as well as correctness in case rotation is undesired.
> - <algorithm>'s std::move/std::move_backward (depending on the shift
> direction).
>
> std::shift should probably accommodate both left and right shifts by one
> of:
> - giving it either begin() and end(), or rbegin() and rend(), similar to
> how std::rotate works for both left and right rotations. The advantage is
> compactness of the implementation.
> - allowing the shift count parameter to be either positive or negative.
> The advantage is compactness, though it might not be clear which direction
> is which - to be consistent with rotate, positive integers should shift to
> the left.
> - having std::shift_right and std::shift_left functions. The advantage is
> clarity when calling the methods, although the same argument could be made
> for having separate std::rotate_left and std::rotate_right instead of
> std::rotate, which we don't have.
>
> Here's a sample implementation of a shift to the right direction:
>
> template<class BidirIt>
> void shift_right(BidirIt first, BidirIt last, unsigned int n = 1)
> {
>     std::move_backward(first, last - n, last);
> }
>
> This demonstrates that while std::shift is implementable with
> std::move/std::move_backward,
> 1) It isn't immediately clear from the code (at least to my eyes) that
> this is a shift right, unless you are intimately familiar with
> std::move_backward.
> 2) Different calls, either to std::move or to std::move_backward, are
> required, depending on the shift direction.
>
> So, implementing std::shift would allow writing more readable code.
>
> Thanks,
> Dan
>

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<div dir=3D"ltr">Hi,<div><br></div><div>Attached a proposal draft with reas=
oning and sample implementation (but still no complete design and standard =
wording).<div>Would appreciate any feedback!</div><div><br></div><div>Thank=
s,</div><div>Dan<br><br>On Wednesday, July 12, 2017 at 12:53:19 PM UTC+3, d=
....@soundradix.com wrote:<blockquote class=3D"gmail_quote" style=3D"margin:=
 0;margin-left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div =
dir=3D"ltr">Hi,<div><br></div><div>Would anyone be interested in adding std=
::shift to &lt;algorithm&gt;?=C2=A0</div><div><br></div><div>It would be si=
milar to both:</div><div>- std::rotate, but without moving the head element=
s back to the tail. This would allow a more efficient implementation and cl=
earer semantics in case rotation is not needed as well as correctness in ca=
se rotation is undesired.</div><div>- &lt;algorithm&gt;&#39;s std::move/std=
::move_backward (depending on the shift direction).</div><div><br></div><di=
v>std::shift should probably accommodate both left and right shifts by one =
of:</div><div>- giving it either begin() and end(), or rbegin() and rend(),=
 similar to how std::rotate works for both left and right rotations. The ad=
vantage is compactness of the implementation.</div><div>- allowing the shif=
t count parameter to be either positive or negative. The advantage is compa=
ctness, though it might not be clear which direction is which - to be consi=
stent with rotate, positive integers should shift to the left.<br></div><di=
v><div>- having std::shift_right and std::shift_left functions. The advanta=
ge is clarity when calling the methods, although the same argument could be=
 made for having separate std::rotate_left and std::rotate_right instead of=
 std::rotate, which we don&#39;t have.</div></div><div><br></div><div>Here&=
#39;s a sample implementation of a shift to the right direction:</div><br><=
div style=3D"background-color:rgb(250,250,250);border:1px solid rgb(187,187=
,187);word-wrap:break-word"><code><div><span style=3D"color:#008">template<=
/span><span style=3D"color:#660">&lt;</span><span style=3D"color:#008">clas=
s</span><span style=3D"color:#000"> </span><span style=3D"color:#606">Bidir=
It</span><span style=3D"color:#660">&gt;</span><span style=3D"color:#000"> =
<br></span><span style=3D"color:#008">void</span><span style=3D"color:#000"=
> shift_right</span><span style=3D"color:#660">(</span><span style=3D"color=
:#606">BidirIt</span><span style=3D"color:#000"> first</span><span style=3D=
"color:#660">,</span><span style=3D"color:#000"> </span><span style=3D"colo=
r:#606">BidirIt</span><span style=3D"color:#000"> </span><span style=3D"col=
or:#008">last</span><span style=3D"color:#660">,</span><span style=3D"color=
:#000"> </span><span style=3D"color:#008">unsigned</span><span style=3D"col=
or:#000"> </span><span style=3D"color:#008">int</span><span style=3D"color:=
#000"> n </span><span style=3D"color:#660">=3D</span><span style=3D"color:#=
000"> </span><span style=3D"color:#066">1</span><span style=3D"color:#660">=
)</span><span style=3D"color:#000"> <br></span><span style=3D"color:#660">{=
</span><span style=3D"color:#000"> <br>=C2=A0 =C2=A0 std</span><span style=
=3D"color:#660">::</span><span style=3D"color:#000">move_backward</span><sp=
an style=3D"color:#660">(</span><span style=3D"color:#000">first</span><spa=
n style=3D"color:#660">,</span><span style=3D"color:#000"> </span><span sty=
le=3D"color:#008">last</span><span style=3D"color:#000"> </span><span style=
=3D"color:#660">-</span><span style=3D"color:#000"> n</span><span style=3D"=
color:#660">,</span><span style=3D"color:#000"> </span><span style=3D"color=
:#008">last</span><span style=3D"color:#660">);</span><span style=3D"color:=
#000"> <br></span><span style=3D"color:#660">}</span><span style=3D"color:#=
000"><br></span></div></code></div><div><br></div><div>This demonstrates th=
at while std::shift is implementable with std::move/std::move_backward,</di=
v><div>1) It isn&#39;t immediately clear from the code (at least to my eyes=
) that this is a shift right, unless you are intimately familiar with std::=
move_backward.</div><div>2) Different calls, either to std::move or to std:=
:move_backward, are required, depending on the shift direction.</div><div><=
br></div><div>So, implementing std::shift would allow writing more readable=
 code.</div><div><br></div><div>Thanks,</div><div>Dan</div></div></blockquo=
te></div></div></div>

<p></p>

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------=_Part_2779_651351720.1501348741489--

.

--Apple-Mail=_81AC97CD-9950-4988-9B14-10761E02E597
Content-Transfer-Encoding: quoted-printable
Content-Type: text/plain; charset="UTF-8"

Dear Mr. Raviv,=20

     Here are a thread lurker=E2=80=99s comments on your proposal.  First, =
your first footnote reads: =20

> =C2=B9 Technically, in some cases std::move can be used with reverse iter=
ators to implement a shift of elements forward, but not in all cases and it=
 is also less efficient, see https://groups.google.com/a/isocpp.org/d/msg/s=
td-proposals/I76om68B3t0/25bGu7O6AwAj <https://groups.google.com/a/isocpp.o=
rg/d/msg/std-proposals/I76om68B3t0/25bGu7O6AwAj> and https://groups.google.=
com/a/isocpp.org/d/msg/std-proposals/I76om68B3t0/SPTeZdofAQAJ <https://grou=
ps.google.com/a/isocpp.org/d/msg/std-proposals/I76om68B3t0/SPTeZdofAQAJ>. =
=20

Within this statement, the part saying, =E2=80=9Cstd::move can be used with=
 reverse iterators to implement a shift of elements forward,=E2=80=9D shoul=
d either read, =E2=80=9Cstd::move can be used with reverse iterators to imp=
lement a shift of elements backward,=E2=80=9D (emphasis added by me) or, =
=E2=80=9Cstd::move_backwards can be used with reverse iterators to implemen=
t a shift of elements forward,=E2=80=9D (emphasis here also added by me,) a=
s only one of these alternatives could render the sentence self-consistent =
with both itself and the rest of your document.  Also, your use of =E2=80=
=98in some cases=E2=80=99 should be followed by a comma, though I acknowled=
ge that two comma-suffixed dependent <https://en.wikipedia.org/wiki/Depende=
nt_clause> relative clauses <https://en.wikipedia.org/wiki/Relative_clause>=
 (at least, I think that=E2=80=99s what they=E2=80=99re called; you can cor=
rect me if my grammar=E2=80=99s off) coming one after another at the beginn=
ing of a sentence can read somewhat awkwardly.  A reasonable way around tha=
t stylistic issue would be to keep =E2=80=99Technically, =E2=80=A6=E2=80=99=
 at the beginning of the sentence, but move =E2=80=98in some cases=E2=80=99=
 later on within it=E2=80=89=E2=80=94=E2=80=89specifically, between =E2=80=
=98can=E2=80=99 and =E2=80=98be=E2=80=99 such that the resulting sentence f=
ragment would, properly using commas as delimiters, read as, =E2=80=9C=E2=
=80=A6, std::move can, in some cases, be used=E2=80=A6.=E2=80=9D  (If the t=
hought of splitting infinitives brings you distaste, I can explain myself: =
 it turns out that the validity of the rule against doing so is actually a =
matter of dispute <https://en.wikipedia.org/wiki/West_Germanic_languages>.)=
 =20
     Second, you might wish to reevaluate your use of fonts:  some function=
 names referenced within particular sentences are not in code font when the=
y should be.  Other than these concerns and those parts of your proposal wh=
ich you have yet to fill in, the document hosting it looks good so far. =20

Regards,=20
     Bryce Glover
     RandomDSdevel@gmail.com

--=20
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mail to std-proposals+unsubscribe@isocpp.org.
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..org/d/msgid/std-proposals/344B1400-86F7-4D11-A7B0-ABB44D5AF397%40gmail.com=
..

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<html><head><meta http-equiv=3D"Content-Type" content=3D"text/html charset=
=3Dutf-8"></head><body style=3D"word-wrap: break-word; -webkit-nbsp-mode: s=
pace; -webkit-line-break: after-white-space;" class=3D""><div class=3D"">De=
ar Mr. Raviv,&nbsp;</div><div class=3D""><br class=3D""></div><div class=3D=
"">&nbsp; &nbsp; &nbsp;Here are a thread lurker=E2=80=99s comments on your =
proposal. &nbsp;First, your first footnote reads: &nbsp;</div><div class=3D=
""><br class=3D""></div><div class=3D""><blockquote type=3D"cite" class=3D"=
">=C2=B9 Technically, in some cases std::move can be used with reverse iter=
ators to implement a shift of elements forward, but not in all cases and it=
 is also less efficient, see <a href=3D"https://groups.google.com/a/isocpp.=
org/d/msg/std-proposals/I76om68B3t0/25bGu7O6AwAj" class=3D"">https://groups=
..google.com/a/isocpp.org/d/msg/std-proposals/I76om68B3t0/25bGu7O6AwAj</a>&n=
bsp;and <a href=3D"https://groups.google.com/a/isocpp.org/d/msg/std-proposa=
ls/I76om68B3t0/SPTeZdofAQAJ" class=3D"">https://groups.google.com/a/isocpp.=
org/d/msg/std-proposals/I76om68B3t0/SPTeZdofAQAJ</a>. &nbsp;</blockquote></=
div><br class=3D""><div class=3D"">Within this statement, the part saying, =
=E2=80=9Cstd::move can be used with reverse iterators to implement a shift =
of elements forward,=E2=80=9D should either read, =E2=80=9Cstd::move can be=
 used with reverse iterators to implement a shift of elements <i class=3D""=
>backward</i>,=E2=80=9D (emphasis added by me) or, =E2=80=9Cstd::move<i cla=
ss=3D"">_backwards</i>&nbsp;can be used with reverse iterators to implement=
 a shift of elements forward,=E2=80=9D (emphasis here also added by me,) as=
 only one of these alternatives could render the sentence self-consistent w=
ith both itself and the rest of your document. &nbsp;Also, your use of =E2=
=80=98in some cases=E2=80=99 should be followed by a comma, though I acknow=
ledge that two comma-suffixed&nbsp;<a href=3D"https://en.wikipedia.org/wiki=
/Dependent_clause" class=3D"">dependent</a>&nbsp;<a href=3D"https://en.wiki=
pedia.org/wiki/Relative_clause" class=3D"">relative clauses</a>&nbsp;(at le=
ast, I <i class=3D"">think</i>&nbsp;that=E2=80=99s what they=E2=80=99re cal=
led; you can correct me if my grammar=E2=80=99s off) coming one after anoth=
er at the beginning of a sentence can read somewhat awkwardly. &nbsp;A reas=
onable way around that stylistic issue would be to keep =E2=80=99Technicall=
y, =E2=80=A6=E2=80=99 at the beginning of the sentence, but move =E2=80=98i=
n some cases=E2=80=99 later on within it=E2=80=89=E2=80=94=E2=80=89specific=
ally, between =E2=80=98can=E2=80=99 and =E2=80=98be=E2=80=99 such that the =
resulting sentence fragment would, properly using commas as delimiters, rea=
d as, =E2=80=9C=E2=80=A6, std::move can, in some cases, be used=E2=80=A6.=
=E2=80=9D &nbsp;(If the thought of splitting infinitives brings you distast=
e, I can explain myself: &nbsp;it turns out that the validity of the rule a=
gainst doing so is actually&nbsp;<a href=3D"https://en.wikipedia.org/wiki/W=
est_Germanic_languages" class=3D"">a matter of dispute</a>.) &nbsp;</div><d=
iv class=3D"">&nbsp; &nbsp; &nbsp;Second, you might wish to reevaluate your=
 use of fonts: &nbsp;some function names referenced within particular sente=
nces are not in code font when they should be. &nbsp;Other than these conce=
rns and those parts of your proposal which you have yet to fill in, the doc=
ument hosting it looks good so far. &nbsp;</div><div class=3D""><br class=
=3D""></div><div class=3D"">
<div style=3D"color: rgb(0, 0, 0); letter-spacing: normal; orphans: auto; t=
ext-align: start; text-indent: 0px; text-transform: none; white-space: norm=
al; widows: auto; word-spacing: 0px; -webkit-text-stroke-width: 0px; word-w=
rap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-=
space;" class=3D""><div style=3D"color: rgb(0, 0, 0); letter-spacing: norma=
l; orphans: auto; text-align: start; text-indent: 0px; text-transform: none=
; white-space: normal; widows: auto; word-spacing: 0px; -webkit-text-stroke=
-width: 0px; word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-=
break: after-white-space;" class=3D""><div style=3D"color: rgb(0, 0, 0); le=
tter-spacing: normal; orphans: auto; text-align: start; text-indent: 0px; t=
ext-transform: none; white-space: normal; widows: auto; word-spacing: 0px; =
-webkit-text-stroke-width: 0px; word-wrap: break-word; -webkit-nbsp-mode: s=
pace; -webkit-line-break: after-white-space;" class=3D""><div class=3D"">Re=
gards,&nbsp;</div><div class=3D"">&nbsp; &nbsp; &nbsp;Bryce Glover</div><di=
v class=3D"">&nbsp; &nbsp; &nbsp;<a href=3D"mailto:RandomDSdevel@gmail.com"=
 class=3D"">RandomDSdevel@gmail.com</a></div></div></div></div></div></body=
></html>

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..org">std-proposals@isocpp.org</a>.<br />
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om/a/isocpp.org/d/msgid/std-proposals/344B1400-86F7-4D11-A7B0-ABB44D5AF397%=
40gmail.com?utm_medium=3Demail&utm_source=3Dfooter">https://groups.google.c=
om/a/isocpp.org/d/msgid/std-proposals/344B1400-86F7-4D11-A7B0-ABB44D5AF397%=
40gmail.com</a>.<br />

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     Whoops, I forgot to mention one last thing about the sentence I had the most comments on in my last e-mail that it starts to turn into a run-on sentence at its end.  I can comment exactly on how you might fix that, too, if you like.

Cheers,
     Bryce Glover
     RandomDSdevel@gmail.com

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<html><head><meta http-equiv=3D"Content-Type" content=3D"text/html charset=
=3Dus-ascii"></head><body style=3D"word-wrap: break-word; -webkit-nbsp-mode=
: space; -webkit-line-break: after-white-space;" class=3D""><div class=3D""=
>&nbsp; &nbsp; &nbsp;<i class=3D"">Whoops</i>, I forgot to mention one last=
 thing about the sentence I had the most comments on in my last e-mail that=
 it starts to turn into a run-on sentence at its end. &nbsp;I can comment e=
xactly on how you might fix that, too, if you like. &nbsp;</div><br class=
=3D""><div class=3D"">
<div style=3D"color: rgb(0, 0, 0); letter-spacing: normal; orphans: auto; t=
ext-align: start; text-indent: 0px; text-transform: none; white-space: norm=
al; widows: auto; word-spacing: 0px; -webkit-text-stroke-width: 0px; word-w=
rap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-=
space;" class=3D""><div style=3D"color: rgb(0, 0, 0); letter-spacing: norma=
l; orphans: auto; text-align: start; text-indent: 0px; text-transform: none=
; white-space: normal; widows: auto; word-spacing: 0px; -webkit-text-stroke=
-width: 0px; word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-=
break: after-white-space;" class=3D""><div style=3D"color: rgb(0, 0, 0); le=
tter-spacing: normal; orphans: auto; text-align: start; text-indent: 0px; t=
ext-transform: none; white-space: normal; widows: auto; word-spacing: 0px; =
-webkit-text-stroke-width: 0px; word-wrap: break-word; -webkit-nbsp-mode: s=
pace; -webkit-line-break: after-white-space;" class=3D""><div class=3D"">Ch=
eers,&nbsp;</div><div class=3D"">&nbsp; &nbsp; &nbsp;Bryce Glover</div><div=
 class=3D"">&nbsp; &nbsp; &nbsp;<a href=3D"mailto:RandomDSdevel@gmail.com" =
class=3D"">RandomDSdevel@gmail.com</a></div></div></div></div></div></body>=
</html>

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..org">std-proposals@isocpp.org</a>.<br />
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om/a/isocpp.org/d/msgid/std-proposals/0053987C-AFAE-45BB-A947-94CF53045FA8%=
40gmail.com?utm_medium=3Demail&utm_source=3Dfooter">https://groups.google.c=
om/a/isocpp.org/d/msgid/std-proposals/0053987C-AFAE-45BB-A947-94CF53045FA8%=
40gmail.com</a>.<br />

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.

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> On Aug 10, 2017, at 4:04 AM, Dan Raviv <dan@soundradix.com> wrote:
>=20
> Hi Bryce,
>=20
> Thanks for the feedback! =E2=80=A6

     You=E2=80=99re welcome! =20

> =E2=80=A6Comments inline.
>=20
> =E2=8B=AE

     Mine will be, too, then. =20

> =E2=8B=AE
>=20
> On Sun, Jul 30, 2017 at 5:56 AM, Bryce Glover <randomdsdevel@gmail.com <m=
ailto:randomdsdevel@gmail.com>> wrote:
> Dear Mr. Raviv,=20
>=20
>      Here are a thread lurker=E2=80=99s comments on your proposal.  First=
, your first footnote reads: =20
>=20
>> =C2=B9 Technically, in some cases std::move can be used with reverse ite=
rators to implement a shift of elements forward, but not in all cases and i=
t is also less efficient, see https://groups.google.com/a/isocpp.org/d/msg/=
std-proposals/I76om68B3t0/25bGu7O6AwAj <https://groups.google.com/a/isocpp.=
org/d/msg/std-proposals/I76om68B3t0/25bGu7O6AwAj> and https://groups.google=
..com/a/isocpp.org/d/msg/std-proposals/I76om68B3t0/SPTeZdofAQAJ <https://gro=
ups.google.com/a/isocpp.org/d/msg/std-proposals/I76om68B3t0/SPTeZdofAQAJ>. =
=20
>=20
> Within this statement, the part saying, =E2=80=9Cstd::move can be used wi=
th reverse iterators to implement a shift of elements forward,=E2=80=9D sho=
uld either read, =E2=80=9Cstd::move can be used with reverse iterators to i=
mplement a shift of elements backward,=E2=80=9D (emphasis added by me) or, =
=E2=80=9Cstd::move_backwards can be used with reverse iterators to implemen=
t a shift of elements forward,=E2=80=9D (emphasis here also added by me,) a=
s only one of these alternatives could render the sentence self-consistent =
with both itself and the rest of your document.
>=20
> Either you got it backwards (no pun intended), =E2=80=A6

     No worries!  I often appreciate a good pun. =20

> =E2=80=A6or I did - in any case, this proves the proposal point of std::m=
ove[_backwards] being too confusing for implementing shift, which is great =
:)
>=20
> =E2=80=A6


     Glad to be of assistance, then. =20

> =E2=80=A6
>=20
> Take a look at my sample implementation <https://github.com/danra/shift_p=
roposal> - you'll see that, assuming non-reverse iterators are passed to sh=
ift(), std::move_backward is used for implementing a right (forward) shift =
of elements, and std::move is used for implementing a left (backward) shift=
 of elements.
>=20
> It can=E2=80=99t work correctly the other way around - if you try using s=
td::move for implementing a right (forward) shift (with regular iterators) =
then the first moved element is going to overwrite an element which still h=
asn't been shifted.
>=20
> =E2=8B=AE


     Oooo-h:  whoops, I tend to think of moving elements within data struct=
ures in terms of a circular or non-circular shifting operation, depending o=
n which kind of wrapping behavior I want.  This probably comes from how I m=
ost likely haven=E2=80=99t written nearly as much code as most of the peopl=
e participating in discussion threads here on std-proposals and was conside=
ring things based on a mental model of a diagram of a contiguous data struc=
ture, such as a simple array or multiset, drawn/written down on paper.  Now=
 that it=E2=80=99s clicked that the directionality of the move operations i=
nvolved in shifting elements around a data structure like this depends, at =
least in name, on how one iterates through it, things make more of a certai=
n kind of sense.  I=E2=80=99m still processing this miniature revelation, t=
hough, so the logic behind this still seems=E2=80=A6a bit mind-bending to m=
e, to be frank. =20

> =E2=8B=AE
> =20
>  Also, your use of =E2=80=98in some cases=E2=80=99 should be followed by =
a comma, though I acknowledge that two comma-suffixed dependent <https://en=
..wikipedia.org/wiki/Dependent_clause> relative clauses <https://en.wikipedi=
a.org/wiki/Relative_clause> (at least, I think that=E2=80=99s what they=E2=
=80=99re called; you can correct me if my grammar=E2=80=99s off) coming one=
 after another at the beginning of a sentence can read somewhat awkwardly. =
 A reasonable way around that stylistic issue would be to keep =E2=80=99Tec=
hnically, =E2=80=A6=E2=80=99 at the beginning of the sentence, but move =E2=
=80=98in some cases=E2=80=99 later on within it=E2=80=89=E2=80=94=E2=80=89s=
pecifically, between =E2=80=98can=E2=80=99 and =E2=80=98be=E2=80=99 such th=
at the resulting sentence fragment would, properly using commas as delimite=
rs, read as, =E2=80=9C=E2=80=A6, std::move can, in some cases, be used=E2=
=80=A6.=E2=80=9D  (If the thought of splitting infinitives brings you dista=
ste, I can explain myself:  it turns out that the validity of the rule agai=
nst doing so is actually a matter of dispute <https://en.wikipedia.org/wiki=
/West_Germanic_languages>.) =20
>=20
> How about this instead?
> Technically, std::move can, in some cases, be used with reverse iterators=
 to implement a shift of elements forward, but not in all cases. It is also=
 less efficient; see https://groups.google.com/a/isocpp.org/d/msg/std-propo=
sals/I76om68B3t0/25bGu7O6AwAJ <https://groups.google.com/a/isocpp.org/d/msg=
/std-proposals/I76om68B3t0/25bGu7O6AwAJ> and https://groups.google.com/a/is=
ocpp.org/d/msg/std-proposals/I76om68B3t0/SPTeZdofAQAJ <https://groups.googl=
e.com/a/isocpp.org/d/msg/std-proposals/I76om68B3t0/SPTeZdofAQAJ>.
> =20
> =E2=8B=AE


     =E2=80=98In some cases=E2=80=99 usually implies =E2=80=98but not in al=
l cases,=E2=80=99 but, yeah, that reads well enough to me. =20

> =E2=8B=AE
>=20
>      Second, you might wish to reevaluate your use of fonts:  some functi=
on names referenced within particular sentences are not in code font when t=
hey should be. =20
>=20
> Done.
>=20
> =E2=8B=AE

     Again, glad to be of service. =20

> =E2=8B=AE
> =20
> Other than these concerns and those parts of your proposal which you have=
 yet to fill in, the document hosting it looks good so far. =20
>=20
> Regards,=20
>      Bryce Glover
>      RandomDSdevel@gmail.com <mailto:RandomDSdevel@gmail.com>
>=20
> Thanks!
> Dan=20
>=20
> --=20
> You received this message because you are subscribed to a topic in the Go=
ogle Groups "ISO C++ Standard - Future Proposals" group.
> To unsubscribe from this topic, visit https://groups.google.com/a/isocpp.=
org/d/topic/std-proposals/I76om68B3t0/unsubscribe <https://groups.google.co=
m/a/isocpp.org/d/topic/std-proposals/I76om68B3t0/unsubscribe>.
> To unsubscribe from this group and all its topics, send an email to std-p=
roposals+unsubscribe@isocpp.org <mailto:std-proposals+unsubscribe@isocpp.or=
g>.
> To post to this group, send email to std-proposals@isocpp.org <mailto:std=
-proposals@isocpp.org>.
> To view this discussion on the web visit https://groups.google.com/a/isoc=
pp.org/d/msgid/std-proposals/344B1400-86F7-4D11-A7B0-ABB44D5AF397%40gmail.c=
om <https://groups.google.com/a/isocpp.org/d/msgid/std-proposals/344B1400-8=
6F7-4D11-A7B0-ABB44D5AF397%40gmail.com?utm_medium=3Demail&utm_source=3Dfoot=
er>.

     Again, you=E2=80=99re very welcome. =20

Regards,=20
     Bryce Glover
     RandomDSdevel@gmail.com

--=20
You received this message because you are subscribed to the Google Groups "=
ISO C++ Standard - Future Proposals" group.
To unsubscribe from this group and stop receiving emails from it, send an e=
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To post to this group, send email to std-proposals@isocpp.org.
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..org/d/msgid/std-proposals/B003EA60-F9B0-480A-9C1B-F40F2881621B%40gmail.com=
..

--Apple-Mail=_043565F1-B467-4D2E-807F-427BCB55FD96
Content-Transfer-Encoding: quoted-printable
Content-Type: text/html; charset="UTF-8"

<html><head><meta http-equiv=3D"Content-Type" content=3D"text/html charset=
=3Dutf-8"></head><body style=3D"word-wrap: break-word; -webkit-nbsp-mode: s=
pace; -webkit-line-break: after-white-space;" class=3D""><br class=3D""><di=
v><blockquote type=3D"cite" class=3D""><div class=3D"">On Aug 10, 2017, at =
4:04 AM, Dan Raviv &lt;<a href=3D"mailto:dan@soundradix.com" class=3D"">dan=
@soundradix.com</a>&gt; wrote:</div><br class=3D"Apple-interchange-newline"=
><div class=3D""><div dir=3D"ltr" style=3D"font-family: Helvetica; font-siz=
e: 14px; font-style: normal; font-variant-caps: normal; font-weight: normal=
; letter-spacing: normal; orphans: auto; text-align: start; text-indent: 0p=
x; text-transform: none; white-space: normal; widows: auto; word-spacing: 0=
px; -webkit-text-stroke-width: 0px;" class=3D"">Hi Bryce,<div class=3D""><b=
r class=3D""></div><div class=3D"">Thanks for the feedback! =E2=80=A6</div>=
</div></div></blockquote><div><br class=3D""></div><div>&nbsp; &nbsp; &nbsp=
;You=E2=80=99re welcome! &nbsp;</div><br class=3D""><blockquote type=3D"cit=
e" class=3D""><div class=3D""><div dir=3D"ltr" style=3D"font-family: Helvet=
ica; font-size: 14px; font-style: normal; font-variant-caps: normal; font-w=
eight: normal; letter-spacing: normal; orphans: auto; text-align: start; te=
xt-indent: 0px; text-transform: none; white-space: normal; widows: auto; wo=
rd-spacing: 0px; -webkit-text-stroke-width: 0px;" class=3D""><div class=3D"=
">=E2=80=A6Comments inline.</div></div></div></blockquote><div><blockquote =
type=3D"cite" class=3D""><br class=3D""></blockquote><blockquote type=3D"ci=
te" class=3D"">=E2=8B=AE</blockquote><br class=3D""></div><div>&nbsp; &nbsp=
; &nbsp;Mine will be, too, then. &nbsp;</div><div><br class=3D""></div><blo=
ckquote type=3D"cite" class=3D"">=E2=8B=AE</blockquote><blockquote type=3D"=
cite" class=3D""><div class=3D""><div dir=3D"ltr" style=3D"font-family: Hel=
vetica; font-size: 14px; font-style: normal; font-variant-caps: normal; fon=
t-weight: normal; letter-spacing: normal; orphans: auto; text-align: start;=
 text-indent: 0px; text-transform: none; white-space: normal; widows: auto;=
 word-spacing: 0px; -webkit-text-stroke-width: 0px;" class=3D""><div class=
=3D"gmail_extra"><br class=3D""><div class=3D"gmail_quote">On Sun, Jul 30, =
2017 at 5:56 AM, Bryce Glover<span class=3D"Apple-converted-space">&nbsp;</=
span><span dir=3D"ltr" class=3D"">&lt;<a href=3D"mailto:randomdsdevel@gmail=
..com" target=3D"_blank" class=3D"">randomdsdevel@gmail.com</a>&gt;</span><s=
pan class=3D"Apple-converted-space">&nbsp;</span>wrote:<br class=3D""><bloc=
kquote class=3D"gmail_quote" style=3D"margin: 0px 0px 0px 0.8ex; border-lef=
t-width: 1px; border-left-style: solid; border-left-color: rgb(204, 204, 20=
4); padding-left: 1ex;"><div style=3D"word-wrap: break-word;" class=3D""><d=
iv class=3D"">Dear Mr. Raviv,&nbsp;</div><div class=3D""><br class=3D""></d=
iv><div class=3D"">&nbsp; &nbsp; &nbsp;Here are a thread lurker=E2=80=99s c=
omments on your proposal.&nbsp; First, your first footnote reads: &nbsp;</d=
iv><div class=3D""><br class=3D""></div><div class=3D""><blockquote type=3D=
"cite" class=3D"">=C2=B9 Technically, in some cases std::move can be used w=
ith reverse iterators to implement a shift of elements forward, but not in =
all cases and it is also less efficient, see<span class=3D"Apple-converted-=
space">&nbsp;</span><a href=3D"https://groups.google.com/a/isocpp.org/d/msg=
/std-proposals/I76om68B3t0/25bGu7O6AwAj" target=3D"_blank" class=3D"">https=
://groups.google.com/a/<wbr class=3D"">isocpp.org/d/msg/std-<wbr class=3D""=
>proposals/I76om68B3t0/<wbr class=3D"">25bGu7O6AwAj</a>&nbsp;and<span class=
=3D"Apple-converted-space">&nbsp;</span><a href=3D"https://groups.google.co=
m/a/isocpp.org/d/msg/std-proposals/I76om68B3t0/SPTeZdofAQAJ" target=3D"_bla=
nk" class=3D"">https://groups.google.com/a/<wbr class=3D"">isocpp.org/d/msg=
/std-<wbr class=3D"">proposals/I76om68B3t0/<wbr class=3D"">SPTeZdofAQAJ</a>=
.. &nbsp;</blockquote></div><br class=3D""><div class=3D"">Within this state=
ment, the part saying, =E2=80=9Cstd::move can be used with reverse iterator=
s to implement a shift of elements forward,=E2=80=9D should either read, =
=E2=80=9Cstd::move can be used with reverse iterators to implement a shift =
of elements<span class=3D"Apple-converted-space">&nbsp;</span><i class=3D""=
>backward</i>,=E2=80=9D (emphasis added by me) or, =E2=80=9Cstd::move<i cla=
ss=3D"">_backwards</i>&nbsp;can be used with reverse iterators to implement=
 a shift of elements forward,=E2=80=9D (emphasis here also added by me,) as=
 only one of these alternatives could render the sentence self-consistent w=
ith both itself and the rest of your document.</div></div></blockquote><div=
 class=3D""><br class=3D""></div><div class=3D"">Either you got it backward=
s (no pun intended), =E2=80=A6</div></div></div></div></div></blockquote><d=
iv><br class=3D""></div><div>&nbsp; &nbsp; &nbsp;No worries! &nbsp;I often =
appreciate a good pun. &nbsp;</div><br class=3D""><blockquote type=3D"cite"=
 class=3D""><div class=3D""><div dir=3D"ltr" style=3D"font-family: Helvetic=
a; font-size: 14px; font-style: normal; font-variant-caps: normal; font-wei=
ght: normal; letter-spacing: normal; orphans: auto; text-align: start; text=
-indent: 0px; text-transform: none; white-space: normal; widows: auto; word=
-spacing: 0px; -webkit-text-stroke-width: 0px;" class=3D""><div class=3D"gm=
ail_extra"><div class=3D"gmail_quote"><div class=3D"">=E2=80=A6or I did - i=
n any case, this proves the proposal point of std::move[_backwards] being t=
oo confusing for implementing shift, which is great :)</div></div></div></d=
iv></div></blockquote><div><blockquote type=3D"cite" class=3D""><br class=
=3D""></blockquote><blockquote type=3D"cite" class=3D"">=E2=80=A6</blockquo=
te></div><div><br class=3D""></div><div>&nbsp; &nbsp; &nbsp;Glad to be of a=
ssistance, then. &nbsp;</div><div><br class=3D""></div><blockquote type=3D"=
cite" class=3D"">=E2=80=A6</blockquote><blockquote type=3D"cite" class=3D""=
><div class=3D""><div dir=3D"ltr" style=3D"font-family: Helvetica; font-siz=
e: 14px; font-style: normal; font-variant-caps: normal; font-weight: normal=
; letter-spacing: normal; orphans: auto; text-align: start; text-indent: 0p=
x; text-transform: none; white-space: normal; widows: auto; word-spacing: 0=
px; -webkit-text-stroke-width: 0px;" class=3D""><div class=3D"gmail_extra">=
<div class=3D"gmail_quote"><div class=3D""><br class=3D""></div><div class=
=3D"">Take a look at my<span class=3D"Apple-converted-space">&nbsp;</span><=
a href=3D"https://github.com/danra/shift_proposal" class=3D"">sample implem=
entation</a><span class=3D"Apple-converted-space">&nbsp;</span>- you'll see=
 that, assuming non-reverse iterators are passed to shift(), std::move_back=
ward is used for implementing a right (forward) shift of elements, and std:=
:move is used for implementing a left (backward) shift of elements.</div><d=
iv class=3D""><br class=3D""></div><div class=3D"">It can=E2=80=99t work co=
rrectly the other way around - if you try using std::move for implementing =
a right (forward) shift (with regular iterators) then the first moved eleme=
nt is going to overwrite an element which still hasn't been shifted.</div><=
/div></div></div></div></blockquote><div><blockquote type=3D"cite" class=3D=
""><br class=3D""></blockquote><blockquote type=3D"cite" class=3D"">=E2=8B=
=AE</blockquote></div><div><br class=3D""></div><div>&nbsp; &nbsp; &nbsp;<i=
 class=3D"">Oooo</i>-h: &nbsp;whoops, I tend to think of moving elements wi=
thin data structures in terms of a circular or non-circular shifting operat=
ion, depending on which kind of wrapping behavior I want. &nbsp;This probab=
ly comes from how I most likely haven=E2=80=99t written <i class=3D"">nearl=
y</i>&nbsp;as much code as most of the people participating in discussion t=
hreads here on std-proposals and was considering things based on a mental m=
odel of a diagram of a contiguous data structure, such as a simple array or=
 multiset, drawn/written down on paper. &nbsp;Now that it=E2=80=99s clicked=
 that the directionality of the move operations involved in shifting elemen=
ts around a data structure like this depends, at least in name, on how one =
<i class=3D"">iterates</i>&nbsp;through it, things make more of a certain k=
ind of sense. &nbsp;I=E2=80=99m still processing this miniature revelation,=
 though, so the logic behind this&nbsp;<i class=3D"">still</i>&nbsp;seems=
=E2=80=A6a <i class=3D"">bit</i>&nbsp;mind-bending to me, to be frank. &nbs=
p;</div><div><br class=3D""></div><blockquote type=3D"cite" class=3D"">=E2=
=8B=AE</blockquote><blockquote type=3D"cite" class=3D""><div class=3D""><di=
v dir=3D"ltr" style=3D"font-family: Helvetica; font-size: 14px; font-style:=
 normal; font-variant-caps: normal; font-weight: normal; letter-spacing: no=
rmal; orphans: auto; text-align: start; text-indent: 0px; text-transform: n=
one; white-space: normal; widows: auto; word-spacing: 0px; -webkit-text-str=
oke-width: 0px;" class=3D""><div class=3D"gmail_extra"><div class=3D"gmail_=
quote"><div class=3D"">&nbsp;</div><blockquote class=3D"gmail_quote" style=
=3D"margin: 0px 0px 0px 0.8ex; border-left-width: 1px; border-left-style: s=
olid; border-left-color: rgb(204, 204, 204); padding-left: 1ex;"><div style=
=3D"word-wrap: break-word;" class=3D""><div class=3D"">&nbsp;Also, your use=
 of =E2=80=98in some cases=E2=80=99 should be followed by a comma, though I=
 acknowledge that two comma-suffixed&nbsp;<a href=3D"https://en.wikipedia.o=
rg/wiki/Dependent_clause" target=3D"_blank" class=3D"">dependent</a>&nbsp;<=
a href=3D"https://en.wikipedia.org/wiki/Relative_clause" target=3D"_blank" =
class=3D"">relat<wbr class=3D"">ive clauses</a>&nbsp;(at least, I<span clas=
s=3D"Apple-converted-space">&nbsp;</span><i class=3D"">think</i>&nbsp;that=
=E2=80=99s what they=E2=80=99re called; you can correct me if my grammar=E2=
=80=99s off) coming one after another at the beginning of a sentence can re=
ad somewhat awkwardly.&nbsp; A reasonable way around that stylistic issue w=
ould be to keep =E2=80=99Technically, =E2=80=A6=E2=80=99 at the beginning o=
f the sentence, but move =E2=80=98in some cases=E2=80=99 later on within it=
=E2=80=89=E2=80=94=E2=80=89specifically, between =E2=80=98can=E2=80=99 and =
=E2=80=98be=E2=80=99 such that the resulting sentence fragment would, prope=
rly using commas as delimiters, read as, =E2=80=9C=E2=80=A6, std::move can,=
 in some cases, be used=E2=80=A6.=E2=80=9D &nbsp;(If the thought of splitti=
ng infinitives brings you distaste, I can explain myself: &nbsp;it turns ou=
t that the validity of the rule against doing so is actually&nbsp;<a href=
=3D"https://en.wikipedia.org/wiki/West_Germanic_languages" target=3D"_blank=
" class=3D"">a matter of dispute</a>.) &nbsp;</div></div></blockquote><div =
class=3D""><br class=3D""></div><div class=3D"">How about this instead?</di=
v><div class=3D""><div style=3D"margin: 0px; font-size: 11px; line-height: =
normal; font-family: Helvetica;" class=3D""><span style=3D"-webkit-font-ker=
ning: none;" class=3D"">Technically, std::move can, in some cases, be used =
with reverse iterators to implement a shift of elements forward, but not in=
 all cases. It is also less efficient; see<span class=3D"Apple-converted-sp=
ace">&nbsp;</span><a href=3D"https://groups.google.com/a/isocpp.org/d/msg/s=
td-proposals/I76om68B3t0/25bGu7O6AwAJ" class=3D""><span style=3D"-webkit-fo=
nt-kerning: none;" class=3D"">https://groups.google.com/a/isocpp.org/d/msg/=
std-proposals/I76om68B3t0/25bGu7O6AwAJ</span></a><span class=3D"Apple-conve=
rted-space">&nbsp;</span>and<span class=3D"Apple-converted-space">&nbsp;</s=
pan><a href=3D"https://groups.google.com/a/isocpp.org/d/msg/std-proposals/I=
76om68B3t0/SPTeZdofAQAJ" class=3D""><span style=3D"-webkit-font-kerning: no=
ne;" class=3D"">https://groups.google.com/a/isocpp.org/d/msg/std-proposals/=
I76om68B3t0/SPTeZdofAQAJ</span></a>.</span></div></div><div class=3D"">&nbs=
p;</div></div></div></div></div></blockquote><div><blockquote type=3D"cite"=
 class=3D"">=E2=8B=AE</blockquote></div><div><br class=3D""></div><div>&nbs=
p; &nbsp; &nbsp;=E2=80=98In some cases=E2=80=99 usually implies =E2=80=98bu=
t not in all cases,=E2=80=99 but, yeah, that reads well enough to me. &nbsp=
;</div><div><br class=3D""></div><div><blockquote type=3D"cite" class=3D"">=
=E2=8B=AE</blockquote></div><blockquote type=3D"cite" class=3D""><br class=
=3D""></blockquote><blockquote type=3D"cite" class=3D""><div class=3D""><di=
v dir=3D"ltr" style=3D"font-family: Helvetica; font-size: 14px; font-style:=
 normal; font-variant-caps: normal; font-weight: normal; letter-spacing: no=
rmal; orphans: auto; text-align: start; text-indent: 0px; text-transform: n=
one; white-space: normal; widows: auto; word-spacing: 0px; -webkit-text-str=
oke-width: 0px;" class=3D""><div class=3D"gmail_extra"><div class=3D"gmail_=
quote"><blockquote class=3D"gmail_quote" style=3D"margin: 0px 0px 0px 0.8ex=
; border-left-width: 1px; border-left-style: solid; border-left-color: rgb(=
204, 204, 204); padding-left: 1ex;"><div style=3D"word-wrap: break-word;" c=
lass=3D""><div class=3D"">&nbsp; &nbsp; &nbsp;Second, you might wish to ree=
valuate your use of fonts: &nbsp;some function names referenced within part=
icular sentences are not in code font when they should be. &nbsp;</div></di=
v></blockquote><div class=3D""><br class=3D""></div><div class=3D"">Done.</=
div></div></div></div></div></blockquote><div><blockquote type=3D"cite" cla=
ss=3D""><br class=3D""></blockquote><blockquote type=3D"cite" class=3D"">=
=E2=8B=AE</blockquote><br class=3D""></div><div>&nbsp; &nbsp; &nbsp;Again, =
glad to be of service. &nbsp;</div><div><br class=3D""></div><blockquote ty=
pe=3D"cite" class=3D"">=E2=8B=AE</blockquote><blockquote type=3D"cite" clas=
s=3D""><div class=3D""><div dir=3D"ltr" style=3D"font-family: Helvetica; fo=
nt-size: 14px; font-style: normal; font-variant-caps: normal; font-weight: =
normal; letter-spacing: normal; orphans: auto; text-align: start; text-inde=
nt: 0px; text-transform: none; white-space: normal; widows: auto; word-spac=
ing: 0px; -webkit-text-stroke-width: 0px;" class=3D""><div class=3D"gmail_e=
xtra"><div class=3D"gmail_quote"><div class=3D"">&nbsp;</div><blockquote cl=
ass=3D"gmail_quote" style=3D"margin: 0px 0px 0px 0.8ex; border-left-width: =
1px; border-left-style: solid; border-left-color: rgb(204, 204, 204); paddi=
ng-left: 1ex;"><div style=3D"word-wrap: break-word;" class=3D""><div class=
=3D"">Other than these concerns and those parts of your proposal which you =
have yet to fill in, the document hosting it looks good so far. &nbsp;</div=
><div class=3D""><br class=3D""></div><div class=3D""><div style=3D"letter-=
spacing: normal; text-align: start; text-indent: 0px; text-transform: none;=
 white-space: normal; word-spacing: 0px; word-wrap: break-word;" class=3D""=
><div style=3D"letter-spacing: normal; text-align: start; text-indent: 0px;=
 text-transform: none; white-space: normal; word-spacing: 0px; word-wrap: b=
reak-word;" class=3D""><div style=3D"letter-spacing: normal; text-align: st=
art; text-indent: 0px; text-transform: none; white-space: normal; word-spac=
ing: 0px; word-wrap: break-word;" class=3D""><div class=3D"">Regards,&nbsp;=
</div><div class=3D"">&nbsp; &nbsp; &nbsp;Bryce Glover</div><div class=3D""=
>&nbsp; &nbsp; &nbsp;<a href=3D"mailto:RandomDSdevel@gmail.com" target=3D"_=
blank" class=3D"">RandomDSdevel@gmail.com</a></div></div></div></div></div>=
</div></blockquote><div class=3D""><br class=3D""></div><div class=3D"">Tha=
nks!</div><div class=3D"">Dan&nbsp;</div><blockquote class=3D"gmail_quote" =
style=3D"margin: 0px 0px 0px 0.8ex; border-left-width: 1px; border-left-sty=
le: solid; border-left-color: rgb(204, 204, 204); padding-left: 1ex;"><span=
 class=3D"gmail-"><div class=3D""><br class=3D"webkit-block-placeholder"></=
div>--<span class=3D"Apple-converted-space">&nbsp;</span><br class=3D"">You=
 received this message because you are subscribed to a topic in the Google =
Groups "ISO C++ Standard - Future Proposals" group.<br class=3D"">To unsubs=
cribe from this topic, visit<span class=3D"Apple-converted-space">&nbsp;</s=
pan><a href=3D"https://groups.google.com/a/isocpp.org/d/topic/std-proposals=
/I76om68B3t0/unsubscribe" target=3D"_blank" class=3D"">https://groups.googl=
e.com/a/<wbr class=3D"">isocpp.org/d/topic/std-<wbr class=3D"">proposals/I7=
6om68B3t0/<wbr class=3D"">unsubscribe</a>.<br class=3D"">To unsubscribe fro=
m this group and all its topics, send an email to<span class=3D"Apple-conve=
rted-space">&nbsp;</span><a href=3D"mailto:std-proposals+unsubscribe@isocpp=
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=3D""></div><div>&nbsp; &nbsp; &nbsp;Again, you=E2=80=99re very welcome. &n=
bsp;</div><div><br class=3D""></div><div class=3D"">
<div style=3D"color: rgb(0, 0, 0); letter-spacing: normal; orphans: auto; t=
ext-align: start; text-indent: 0px; text-transform: none; white-space: norm=
al; widows: auto; word-spacing: 0px; -webkit-text-stroke-width: 0px; word-w=
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space;" class=3D""><div style=3D"color: rgb(0, 0, 0); letter-spacing: norma=
l; orphans: auto; text-align: start; text-indent: 0px; text-transform: none=
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break: after-white-space;" class=3D""><div style=3D"color: rgb(0, 0, 0); le=
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-webkit-text-stroke-width: 0px; word-wrap: break-word; -webkit-nbsp-mode: s=
pace; -webkit-line-break: after-white-space;" class=3D""><div class=3D"">Re=
gards,&nbsp;</div><div class=3D"">&nbsp; &nbsp; &nbsp;Bryce Glover</div><di=
v class=3D"">&nbsp; &nbsp; &nbsp;<a href=3D"mailto:RandomDSdevel@gmail.com"=
 class=3D"">RandomDSdevel@gmail.com</a></div></div></div></div>
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Hi,

Attached an updated proposal draft.

Would appreciate any comments, as well as opinions on any of the listed
open issues.

Thanks!
Dan

On Saturday, July 29, 2017 at 8:19:01 PM UTC+3, Dan Raviv wrote:
>
> Hi,
>
> Attached a proposal draft with reasoning and sample implementation (but
> still no complete design and standard wording).
> Would appreciate any feedback!
>
> Thanks,
> Dan
>
> On Wednesday, July 12, 2017 at 12:53:19 PM UTC+3, d...@soundradix.com
> wrote:
>>
>> Hi,
>>
>> Would anyone be interested in adding std::shift to <algorithm>?
>>
>> It would be similar to both:
>> - std::rotate, but without moving the head elements back to the tail.
>> This would allow a more efficient implementation and clearer semantics in
>> case rotation is not needed as well as correctness in case rotation is
>> undesired.
>> - <algorithm>'s std::move/std::move_backward (depending on the shift
>> direction).
>>
>> std::shift should probably accommodate both left and right shifts by one
>> of:
>> - giving it either begin() and end(), or rbegin() and rend(), similar to
>> how std::rotate works for both left and right rotations. The advantage is
>> compactness of the implementation.
>> - allowing the shift count parameter to be either positive or negative.
>> The advantage is compactness, though it might not be clear which direction
>> is which - to be consistent with rotate, positive integers should shift to
>> the left.
>> - having std::shift_right and std::shift_left functions. The advantage is
>> clarity when calling the methods, although the same argument could be made
>> for having separate std::rotate_left and std::rotate_right instead of
>> std::rotate, which we don't have.
>>
>> Here's a sample implementation of a shift to the right direction:
>>
>> template<class BidirIt>
>> void shift_right(BidirIt first, BidirIt last, unsigned int n = 1)
>> {
>>     std::move_backward(first, last - n, last);
>> }
>>
>> This demonstrates that while std::shift is implementable with
>> std::move/std::move_backward,
>> 1) It isn't immediately clear from the code (at least to my eyes) that
>> this is a shift right, unless you are intimately familiar with
>> std::move_backward.
>> 2) Different calls, either to std::move or to std::move_backward, are
>> required, depending on the shift direction.
>>
>> So, implementing std::shift would allow writing more readable code.
>>
>> Thanks,
>> Dan
>>
>

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<div dir=3D"ltr">Hi,<div><br></div><div>Attached an updated proposal draft.=
</div><div><br></div><div>Would appreciate any comments, as well as opinion=
s on any of the listed open issues.</div><div><br></div><div>Thanks!</div><=
div>Dan</div><div><br>On Saturday, July 29, 2017 at 8:19:01 PM UTC+3, Dan R=
aviv wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;margin-left=
: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"ltr">Hi=
,<div><br></div><div>Attached a proposal draft with reasoning and sample im=
plementation (but still no complete design and standard wording).<div>Would=
 appreciate any feedback!</div><div><br></div><div>Thanks,</div><div>Dan<br=
><br>On Wednesday, July 12, 2017 at 12:53:19 PM UTC+3, <a>d...@soundradix.c=
om</a> wrote:<blockquote class=3D"gmail_quote" style=3D"margin:0;margin-lef=
t:0.8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">Hi,<d=
iv><br></div><div>Would anyone be interested in adding std::shift to &lt;al=
gorithm&gt;?=C2=A0</div><div><br></div><div>It would be similar to both:</d=
iv><div>- std::rotate, but without moving the head elements back to the tai=
l. This would allow a more efficient implementation and clearer semantics i=
n case rotation is not needed as well as correctness in case rotation is un=
desired.</div><div>- &lt;algorithm&gt;&#39;s std::move/std::move_backward (=
depending on the shift direction).</div><div><br></div><div>std::shift shou=
ld probably accommodate both left and right shifts by one of:</div><div>- g=
iving it either begin() and end(), or rbegin() and rend(), similar to how s=
td::rotate works for both left and right rotations. The advantage is compac=
tness of the implementation.</div><div>- allowing the shift count parameter=
 to be either positive or negative. The advantage is compactness, though it=
 might not be clear which direction is which - to be consistent with rotate=
, positive integers should shift to the left.<br></div><div><div>- having s=
td::shift_right and std::shift_left functions. The advantage is clarity whe=
n calling the methods, although the same argument could be made for having =
separate std::rotate_left and std::rotate_right instead of std::rotate, whi=
ch we don&#39;t have.</div></div><div><br></div><div>Here&#39;s a sample im=
plementation of a shift to the right direction:</div><br><div style=3D"back=
ground-color:rgb(250,250,250);border:1px solid rgb(187,187,187);word-wrap:b=
reak-word"><code><div><span style=3D"color:#008">template</span><span style=
=3D"color:#660">&lt;</span><span style=3D"color:#008">class</span><span sty=
le=3D"color:#000"> </span><span style=3D"color:#606">BidirIt</span><span st=
yle=3D"color:#660">&gt;</span><span style=3D"color:#000"> <br></span><span =
style=3D"color:#008">void</span><span style=3D"color:#000"> shift_right</sp=
an><span style=3D"color:#660">(</span><span style=3D"color:#606">BidirIt</s=
pan><span style=3D"color:#000"> first</span><span style=3D"color:#660">,</s=
pan><span style=3D"color:#000"> </span><span style=3D"color:#606">BidirIt</=
span><span style=3D"color:#000"> </span><span style=3D"color:#008">last</sp=
an><span style=3D"color:#660">,</span><span style=3D"color:#000"> </span><s=
pan style=3D"color:#008">unsigned</span><span style=3D"color:#000"> </span>=
<span style=3D"color:#008">int</span><span style=3D"color:#000"> n </span><=
span style=3D"color:#660">=3D</span><span style=3D"color:#000"> </span><spa=
n style=3D"color:#066">1</span><span style=3D"color:#660">)</span><span sty=
le=3D"color:#000"> <br></span><span style=3D"color:#660">{</span><span styl=
e=3D"color:#000"> <br>=C2=A0 =C2=A0 std</span><span style=3D"color:#660">::=
</span><span style=3D"color:#000">move_backward</span><span style=3D"color:=
#660">(</span><span style=3D"color:#000">first</span><span style=3D"color:#=
660">,</span><span style=3D"color:#000"> </span><span style=3D"color:#008">=
last</span><span style=3D"color:#000"> </span><span style=3D"color:#660">-<=
/span><span style=3D"color:#000"> n</span><span style=3D"color:#660">,</spa=
n><span style=3D"color:#000"> </span><span style=3D"color:#008">last</span>=
<span style=3D"color:#660">);</span><span style=3D"color:#000"> <br></span>=
<span style=3D"color:#660">}</span><span style=3D"color:#000"><br></span></=
div></code></div><div><br></div><div>This demonstrates that while std::shif=
t is implementable with std::move/std::move_backward,</div><div>1) It isn&#=
39;t immediately clear from the code (at least to my eyes) that this is a s=
hift right, unless you are intimately familiar with std::move_backward.</di=
v><div>2) Different calls, either to std::move or to std::move_backward, ar=
e required, depending on the shift direction.</div><div><br></div><div>So, =
implementing std::shift would allow writing more readable code.</div><div><=
br></div><div>Thanks,</div><div>Dan</div></div></blockquote></div></div></d=
iv></blockquote></div></div>

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.

> On Aug 18, 2017, at 6:24 PM, Dan Raviv <dan.raviv@gmail.com> wrote:
>
> <shift proposal.pdf>


- p. 1:  s/A main use case/An important use case/

- p. 1: "can be found _here_":  somewhere (bib?) the link should be written out in full

- speaking of a bib, I recommend one that includes a reference or two to the time series technique mentioned

- everwhere:  pages should be numbered, and (except p. 1) should have a header or trailer giving the paper number and title

- III title:  s/Expected Objections/Possible Objections/  or just retitle to FAQ

- V.1 strike "only" from "only bidirectional iterators" -- otherwise you seem to exclude random-access iter's; the next sentence has a similar issue

- ... and I suggest that next sentence ("This is similar....) be parenthesized -- it's not your main point here

- V.2  s/Following/Per/

- V.2 1st sentence seems unclear:  perhaps "is required to support fwd iter's"?

- V.3 s/an optional filler/overloads with a optional filler/

- Thank you for the ack.

Best,

-- WEB

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On Friday, August 18, 2017 at 4:24:07 PM UTC-7, Dan Raviv wrote:
>
> Hi,
>
> Attached an updated proposal draft.
>
> Would appreciate any comments, as well as opinions on any of the listed
> open issues.
>
> Thanks!
> Dan
>
>
I am not fond of the optional<value type> filler argument. I suspect that
the vast majority of use cases will NOT fill the emptied elements, and this
formulation - at least in non-optimizing compiles - is likely to generate
unused code for the fill operation. I'd prefer to see separate overloads
with an additional const T& argument whose value would be used to fill the
emptied elements, although realistically it's simple enough for users to
perform the fill themselves that I don't think the facility provides enough
value to standardize.

In V.1 you state that "Shifting [forward ranges] right is possible, but
inefficient, requiring either O(N) space or O(N^2) time." The fact that
std::rotate can efficiently rotate forward ranges suggests that they can be
efficiently shifted as well. I've implemented shift_right for forward
ranges in https://github.com/danra/shift_proposal/pull/1 - it has linear
complexity and requires constant additional space.

I don't buy the arguments that shift counts less than zero or greater than
the length of the sequence should have undefined behavior. Given that the
implementation must check the shift count to avoid UB for the shift-by-zero
case, I don't believe that guarding against negative shift counts incurs
any additional overhead. I think a similar argument applies for shift
counts greater than the length of the range vs. shift count exactly equal
to the length of the range. We certainly want shift by N to be valid, and
allowing shift by greater than N has negligible additional cost.

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Content-Type: text/html; charset="UTF-8"
Content-Transfer-Encoding: quoted-printable

<div dir=3D"ltr">On Friday, August 18, 2017 at 4:24:07 PM UTC-7, Dan Raviv =
wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;margin-left: 0.8=
ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"ltr">Hi,<div=
><br></div><div>Attached an updated proposal draft.</div><div><br></div><di=
v>Would appreciate any comments, as well as opinions on any of the listed o=
pen issues.</div><div><br></div><div>Thanks!</div><div>Dan</div><div><br></=
div></div></blockquote><div><br></div><div>I am not fond of the optional&lt=
;value type&gt; filler argument. I suspect that the vast majority of use ca=
ses will NOT fill the emptied elements, and this formulation - at least in =
non-optimizing compiles - is likely to generate unused code for the fill op=
eration. I&#39;d prefer to see separate overloads with an additional const =
T&amp; argument whose value would be used to fill the emptied elements, alt=
hough realistically it&#39;s simple enough for users to perform the fill th=
emselves that I don&#39;t think the facility provides enough value to stand=
ardize.</div><div><br></div><div>In V.1 you state that &quot;Shifting [forw=
ard ranges] right is possible, but inefficient, requiring either O(N) space=
 or O(N^2) time.&quot; The fact that std::rotate can efficiently rotate for=
ward ranges suggests that they can be efficiently shifted as well. I&#39;ve=
 implemented shift_right for forward ranges in=C2=A0https://github.com/danr=
a/shift_proposal/pull/1 - it has linear complexity and requires constant ad=
ditional space.</div><div>=C2=A0</div><div>I don&#39;t buy the arguments th=
at shift counts less than zero or greater than the length of the sequence s=
hould have undefined behavior. Given that the implementation must check the=
 shift count to avoid UB for the shift-by-zero case, I don&#39;t believe th=
at guarding against negative shift counts incurs any additional overhead. I=
 think a similar argument applies for shift counts greater than the length =
of the range vs. shift count exactly equal to the length of the range. We c=
ertainly want shift by N to be valid, and allowing shift by greater than N =
has negligible additional cost.</div><div><br></div></div>

<p></p>

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--Apple-Mail=_A8AFB77F-4CAB-4EDC-9262-B9044A5A184E
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> On Aug 20, 2017, at 6:18 PM, std-proposals@isocpp.org wrote:
>=20
> On Saturday, 19 August 2017 14:48:26 PDT Bryce Glover wrote:
> > Whoops, forgot to change the subject after copying the part I quoted fr=
om
> > the digest=E2=80=A6:
> =20
> That is not enough. You have to copy the message's Message-Id to your ema=
il's=20
> In-Reply-To header.

     Darn it, I always forget about that!  And I think you=E2=80=99ve menti=
oned this before, too=E2=80=A6; like I think I=E2=80=99ve at least implied =
before, I don=E2=80=99t know how to set that header field from within Apple=
 Mail (or even if you can, for that matter!)   But enough of this off-topic=
 rambling=E2=80=A6

Slightly abashed,=20
     Bryce Glover
     RandomDSdevel@gmail.com

--=20
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..

--Apple-Mail=_A8AFB77F-4CAB-4EDC-9262-B9044A5A184E
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<html><head><meta http-equiv=3D"Content-Type" content=3D"text/html charset=
=3Dutf-8"></head><body style=3D"word-wrap: break-word; -webkit-nbsp-mode: s=
pace; -webkit-line-break: after-white-space;" class=3D""><div><blockquote t=
ype=3D"cite" class=3D""><div class=3D"">On Aug 20, 2017, at 6:18 PM, <a hre=
f=3D"mailto:std-proposals@isocpp.org" class=3D"">std-proposals@isocpp.org</=
a> wrote:</div><br class=3D"Apple-interchange-newline"><div class=3D""><spa=
n style=3D"color: rgb(46, 46, 46); font-family: arial; font-size: inherit; =
font-style: normal; font-variant-caps: normal; font-weight: normal; letter-=
spacing: normal; orphans: auto; text-align: start; text-indent: 0px; text-t=
ransform: none; white-space: normal; widows: auto; word-spacing: 0px; -webk=
it-text-stroke-width: 0px; background-color: rgb(255, 255, 255); float: non=
e; display: inline !important;" class=3D"">On Saturday, 19 August 2017 14:4=
8:26 PDT Bryce Glover wrote:</span><br style=3D"color: rgb(46, 46, 46); fon=
t-family: arial; font-style: normal; font-variant-caps: normal; font-weight=
: normal; letter-spacing: normal; orphans: auto; text-align: start; text-in=
dent: 0px; text-transform: none; white-space: normal; widows: auto; word-sp=
acing: 0px; -webkit-text-stroke-width: 0px; background-color: rgb(255, 255,=
 255);" class=3D""><span style=3D"color: rgb(46, 46, 46); font-family: aria=
l; font-size: inherit; font-style: normal; font-variant-caps: normal; font-=
weight: normal; letter-spacing: normal; orphans: auto; text-align: start; t=
ext-indent: 0px; text-transform: none; white-space: normal; widows: auto; w=
ord-spacing: 0px; -webkit-text-stroke-width: 0px; background-color: rgb(255=
, 255, 255); float: none; display: inline !important;" class=3D"">&gt; Whoo=
ps, forgot to change the subject after copying the part I quoted from</span=
><br style=3D"color: rgb(46, 46, 46); font-family: arial; font-style: norma=
l; font-variant-caps: normal; font-weight: normal; letter-spacing: normal; =
orphans: auto; text-align: start; text-indent: 0px; text-transform: none; w=
hite-space: normal; widows: auto; word-spacing: 0px; -webkit-text-stroke-wi=
dth: 0px; background-color: rgb(255, 255, 255);" class=3D""><span style=3D"=
color: rgb(46, 46, 46); font-family: arial; font-size: inherit; font-style:=
 normal; font-variant-caps: normal; font-weight: normal; letter-spacing: no=
rmal; orphans: auto; text-align: start; text-indent: 0px; text-transform: n=
one; white-space: normal; widows: auto; word-spacing: 0px; -webkit-text-str=
oke-width: 0px; background-color: rgb(255, 255, 255); float: none; display:=
 inline !important;" class=3D"">&gt; the digest=E2=80=A6:</span><br style=
=3D"color: rgb(46, 46, 46); font-family: arial; font-style: normal; font-va=
riant-caps: normal; font-weight: normal; letter-spacing: normal; orphans: a=
uto; text-align: start; text-indent: 0px; text-transform: none; white-space=
: normal; widows: auto; word-spacing: 0px; -webkit-text-stroke-width: 0px; =
background-color: rgb(255, 255, 255);" class=3D""><span style=3D"color: rgb=
(46, 46, 46); font-family: arial; font-size: inherit; font-style: normal; f=
ont-variant-caps: normal; font-weight: normal; letter-spacing: normal; orph=
ans: auto; text-align: start; text-indent: 0px; text-transform: none; white=
-space: normal; widows: auto; word-spacing: 0px; -webkit-text-stroke-width:=
 0px; background-color: rgb(255, 255, 255); float: none; display: inline !i=
mportant;" class=3D"">&nbsp;</span><br style=3D"color: rgb(46, 46, 46); fon=
t-family: arial; font-style: normal; font-variant-caps: normal; font-weight=
: normal; letter-spacing: normal; orphans: auto; text-align: start; text-in=
dent: 0px; text-transform: none; white-space: normal; widows: auto; word-sp=
acing: 0px; -webkit-text-stroke-width: 0px; background-color: rgb(255, 255,=
 255);" class=3D""><span style=3D"color: rgb(46, 46, 46); font-family: aria=
l; font-size: inherit; font-style: normal; font-variant-caps: normal; font-=
weight: normal; letter-spacing: normal; orphans: auto; text-align: start; t=
ext-indent: 0px; text-transform: none; white-space: normal; widows: auto; w=
ord-spacing: 0px; -webkit-text-stroke-width: 0px; background-color: rgb(255=
, 255, 255); float: none; display: inline !important;" class=3D"">That is n=
ot enough. You have to copy the message's Message-Id to your email's<span c=
lass=3D"Apple-converted-space">&nbsp;</span></span><br style=3D"color: rgb(=
46, 46, 46); font-family: arial; font-style: normal; font-variant-caps: nor=
mal; font-weight: normal; letter-spacing: normal; orphans: auto; text-align=
: start; text-indent: 0px; text-transform: none; white-space: normal; widow=
s: auto; word-spacing: 0px; -webkit-text-stroke-width: 0px; background-colo=
r: rgb(255, 255, 255);" class=3D""><span style=3D"color: rgb(46, 46, 46); f=
ont-family: arial; font-size: inherit; font-style: normal; font-variant-cap=
s: normal; font-weight: normal; letter-spacing: normal; orphans: auto; text=
-align: start; text-indent: 0px; text-transform: none; white-space: normal;=
 widows: auto; word-spacing: 0px; -webkit-text-stroke-width: 0px; backgroun=
d-color: rgb(255, 255, 255); float: none; display: inline !important;" clas=
s=3D"">In-Reply-To header.</span></div></blockquote></div><br class=3D""><d=
iv class=3D"">&nbsp; &nbsp; &nbsp;Darn it, I <i class=3D"">always</i> forge=
t about that! &nbsp;And I think you=E2=80=99ve mentioned this before, too=
=E2=80=A6; like I think I=E2=80=99ve at least <i class=3D"">implied</i>&nbs=
p;before, I don=E2=80=99t know how to set that header field from within App=
le Mail (or even if you <i class=3D"">can</i>, for <i class=3D"">that</i>&n=
bsp;matter!) &nbsp;&nbsp;But enough of this off-topic rambling=E2=80=A6</di=
v><br class=3D""><div class=3D"">
<div style=3D"color: rgb(0, 0, 0); letter-spacing: normal; orphans: auto; t=
ext-align: start; text-indent: 0px; text-transform: none; white-space: norm=
al; widows: auto; word-spacing: 0px; -webkit-text-stroke-width: 0px; word-w=
rap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-=
space;" class=3D""><div style=3D"color: rgb(0, 0, 0); letter-spacing: norma=
l; orphans: auto; text-align: start; text-indent: 0px; text-transform: none=
; white-space: normal; widows: auto; word-spacing: 0px; -webkit-text-stroke=
-width: 0px; word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-=
break: after-white-space;" class=3D""><div style=3D"color: rgb(0, 0, 0); le=
tter-spacing: normal; orphans: auto; text-align: start; text-indent: 0px; t=
ext-transform: none; white-space: normal; widows: auto; word-spacing: 0px; =
-webkit-text-stroke-width: 0px; word-wrap: break-word; -webkit-nbsp-mode: s=
pace; -webkit-line-break: after-white-space;" class=3D""><div class=3D"">Sl=
ightly abashed,&nbsp;</div><div class=3D"">&nbsp; &nbsp; &nbsp;Bryce Glover=
</div><div class=3D"">&nbsp; &nbsp; &nbsp;<a href=3D"mailto:RandomDSdevel@g=
mail.com" class=3D"">RandomDSdevel@gmail.com</a></div></div></div></div>
</div>
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Hi!

Attached an updated proposal draft, now with shift_right for forward,
non-bidirectional iterators, courtesy of Casey Carter! You can check out
the implementation at https://github.com/danra/shift_proposal .

Also removed the filler functionality, following feedback which has proven
it to be redundant.

Would appreciate any further comments, as well as opinions on the listed
open issues.

Thanks,
Dan



On Saturday, August 19, 2017 at 2:24:07 AM UTC+3, Dan Raviv wrote:
>
> Hi,
>
> Attached an updated proposal draft.
>
> Would appreciate any comments, as well as opinions on any of the listed
> open issues.
>
> Thanks!
> Dan
>
> On Saturday, July 29, 2017 at 8:19:01 PM UTC+3, Dan Raviv wrote:
>>
>> Hi,
>>
>> Attached a proposal draft with reasoning and sample implementation (but
>> still no complete design and standard wording).
>> Would appreciate any feedback!
>>
>> Thanks,
>> Dan
>>
>> On Wednesday, July 12, 2017 at 12:53:19 PM UTC+3, d...@soundradix.com
>> wrote:
>>>
>>> Hi,
>>>
>>> Would anyone be interested in adding std::shift to <algorithm>?
>>>
>>> It would be similar to both:
>>> - std::rotate, but without moving the head elements back to the tail.
>>> This would allow a more efficient implementation and clearer semantics in
>>> case rotation is not needed as well as correctness in case rotation is
>>> undesired.
>>> - <algorithm>'s std::move/std::move_backward (depending on the shift
>>> direction).
>>>
>>> std::shift should probably accommodate both left and right shifts by one
>>> of:
>>> - giving it either begin() and end(), or rbegin() and rend(), similar to
>>> how std::rotate works for both left and right rotations. The advantage is
>>> compactness of the implementation.
>>> - allowing the shift count parameter to be either positive or negative.
>>> The advantage is compactness, though it might not be clear which direction
>>> is which - to be consistent with rotate, positive integers should shift to
>>> the left.
>>> - having std::shift_right and std::shift_left functions. The advantage
>>> is clarity when calling the methods, although the same argument could be
>>> made for having separate std::rotate_left and std::rotate_right instead of
>>> std::rotate, which we don't have.
>>>
>>> Here's a sample implementation of a shift to the right direction:
>>>
>>> template<class BidirIt>
>>> void shift_right(BidirIt first, BidirIt last, unsigned int n = 1)
>>> {
>>>     std::move_backward(first, last - n, last);
>>> }
>>>
>>> This demonstrates that while std::shift is implementable with
>>> std::move/std::move_backward,
>>> 1) It isn't immediately clear from the code (at least to my eyes) that
>>> this is a shift right, unless you are intimately familiar with
>>> std::move_backward.
>>> 2) Different calls, either to std::move or to std::move_backward, are
>>> required, depending on the shift direction.
>>>
>>> So, implementing std::shift would allow writing more readable code.
>>>
>>> Thanks,
>>> Dan
>>>
>>

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<div dir=3D"ltr">Hi!<div><br></div><div>Attached an updated proposal draft,=
 now with shift_right for forward, non-bidirectional iterators, courtesy of=
 Casey Carter! You can check out the implementation at=C2=A0https://github.=
com/danra/shift_proposal .</div><div><br></div><div>Also removed the filler=
 functionality, following feedback which has proven it to be redundant.</di=
v><div><br></div><div>Would appreciate any further comments, as well as opi=
nions on the listed open issues.</div><div><br></div><div>Thanks,</div><div=
>Dan</div><div><br></div><div><br><br>On Saturday, August 19, 2017 at 2:24:=
07 AM UTC+3, Dan Raviv wrote:<blockquote class=3D"gmail_quote" style=3D"mar=
gin: 0;margin-left: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><=
div dir=3D"ltr">Hi,<div><br></div><div>Attached an updated proposal draft.<=
/div><div><br></div><div>Would appreciate any comments, as well as opinions=
 on any of the listed open issues.</div><div><br></div><div>Thanks!</div><d=
iv>Dan</div><div><br>On Saturday, July 29, 2017 at 8:19:01 PM UTC+3, Dan Ra=
viv wrote:<blockquote class=3D"gmail_quote" style=3D"margin:0;margin-left:0=
..8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">Hi,<div>=
<br></div><div>Attached a proposal draft with reasoning and sample implemen=
tation (but still no complete design and standard wording).<div>Would appre=
ciate any feedback!</div><div><br></div><div>Thanks,</div><div>Dan<br><br>O=
n Wednesday, July 12, 2017 at 12:53:19 PM UTC+3, <a>d...@soundradix.com</a>=
 wrote:<blockquote class=3D"gmail_quote" style=3D"margin:0;margin-left:0.8e=
x;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"ltr">Hi,<div><br=
></div><div>Would anyone be interested in adding std::shift to &lt;algorith=
m&gt;?=C2=A0</div><div><br></div><div>It would be similar to both:</div><di=
v>- std::rotate, but without moving the head elements back to the tail. Thi=
s would allow a more efficient implementation and clearer semantics in case=
 rotation is not needed as well as correctness in case rotation is undesire=
d.</div><div>- &lt;algorithm&gt;&#39;s std::move/std::move_backward (depend=
ing on the shift direction).</div><div><br></div><div>std::shift should pro=
bably accommodate both left and right shifts by one of:</div><div>- giving =
it either begin() and end(), or rbegin() and rend(), similar to how std::ro=
tate works for both left and right rotations. The advantage is compactness =
of the implementation.</div><div>- allowing the shift count parameter to be=
 either positive or negative. The advantage is compactness, though it might=
 not be clear which direction is which - to be consistent with rotate, posi=
tive integers should shift to the left.<br></div><div><div>- having std::sh=
ift_right and std::shift_left functions. The advantage is clarity when call=
ing the methods, although the same argument could be made for having separa=
te std::rotate_left and std::rotate_right instead of std::rotate, which we =
don&#39;t have.</div></div><div><br></div><div>Here&#39;s a sample implemen=
tation of a shift to the right direction:</div><br><div style=3D"background=
-color:rgb(250,250,250);border:1px solid rgb(187,187,187);word-wrap:break-w=
ord"><code><div><span style=3D"color:#008">template</span><span style=3D"co=
lor:#660">&lt;</span><span style=3D"color:#008">class</span><span style=3D"=
color:#000"> </span><span style=3D"color:#606">BidirIt</span><span style=3D=
"color:#660">&gt;</span><span style=3D"color:#000"> <br></span><span style=
=3D"color:#008">void</span><span style=3D"color:#000"> shift_right</span><s=
pan style=3D"color:#660">(</span><span style=3D"color:#606">BidirIt</span><=
span style=3D"color:#000"> first</span><span style=3D"color:#660">,</span><=
span style=3D"color:#000"> </span><span style=3D"color:#606">BidirIt</span>=
<span style=3D"color:#000"> </span><span style=3D"color:#008">last</span><s=
pan style=3D"color:#660">,</span><span style=3D"color:#000"> </span><span s=
tyle=3D"color:#008">unsigned</span><span style=3D"color:#000"> </span><span=
 style=3D"color:#008">int</span><span style=3D"color:#000"> n </span><span =
style=3D"color:#660">=3D</span><span style=3D"color:#000"> </span><span sty=
le=3D"color:#066">1</span><span style=3D"color:#660">)</span><span style=3D=
"color:#000"> <br></span><span style=3D"color:#660">{</span><span style=3D"=
color:#000"> <br>=C2=A0 =C2=A0 std</span><span style=3D"color:#660">::</spa=
n><span style=3D"color:#000">move_backward</span><span style=3D"color:#660"=
>(</span><span style=3D"color:#000">first</span><span style=3D"color:#660">=
,</span><span style=3D"color:#000"> </span><span style=3D"color:#008">last<=
/span><span style=3D"color:#000"> </span><span style=3D"color:#660">-</span=
><span style=3D"color:#000"> n</span><span style=3D"color:#660">,</span><sp=
an style=3D"color:#000"> </span><span style=3D"color:#008">last</span><span=
 style=3D"color:#660">);</span><span style=3D"color:#000"> <br></span><span=
 style=3D"color:#660">}</span><span style=3D"color:#000"><br></span></div><=
/code></div><div><br></div><div>This demonstrates that while std::shift is =
implementable with std::move/std::move_backward,</div><div>1) It isn&#39;t =
immediately clear from the code (at least to my eyes) that this is a shift =
right, unless you are intimately familiar with std::move_backward.</div><di=
v>2) Different calls, either to std::move or to std::move_backward, are req=
uired, depending on the shift direction.</div><div><br></div><div>So, imple=
menting std::shift would allow writing more readable code.</div><div><br></=
div><div>Thanks,</div><div>Dan</div></div></blockquote></div></div></div></=
blockquote></div></div></blockquote></div></div>

<p></p>

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Hi,

Attached updated proposal draft.

- Added proposed standard wording.
- Decided to allow shift by zero despite a possible minimal performance
penalty.
- Improved formatting and content nits.

Would appreciate any comments as well as possible naming alternatives (see
Open Issues section in the proposal).

Thanks,
Dan

On Friday, August 25, 2017 at 1:00:28 AM UTC+3, Dan Raviv wrote:
>
> Hi!
>
> Attached an updated proposal draft, now with shift_right for forward,
> non-bidirectional iterators, courtesy of Casey Carter! You can check out
> the implementation at https://github.com/danra/shift_proposal .
>
> Also removed the filler functionality, following feedback which has proven
> it to be redundant.
>
> Would appreciate any further comments, as well as opinions on the listed
> open issues.
>
> Thanks,
> Dan
>
>
>
> On Saturday, August 19, 2017 at 2:24:07 AM UTC+3, Dan Raviv wrote:
>>
>> Hi,
>>
>> Attached an updated proposal draft.
>>
>> Would appreciate any comments, as well as opinions on any of the listed
>> open issues.
>>
>> Thanks!
>> Dan
>>
>> On Saturday, July 29, 2017 at 8:19:01 PM UTC+3, Dan Raviv wrote:
>>>
>>> Hi,
>>>
>>> Attached a proposal draft with reasoning and sample implementation (but
>>> still no complete design and standard wording).
>>> Would appreciate any feedback!
>>>
>>> Thanks,
>>> Dan
>>>
>>> On Wednesday, July 12, 2017 at 12:53:19 PM UTC+3, d...@soundradix.com
>>> wrote:
>>>>
>>>> Hi,
>>>>
>>>> Would anyone be interested in adding std::shift to <algorithm>?
>>>>
>>>> It would be similar to both:
>>>> - std::rotate, but without moving the head elements back to the tail.
>>>> This would allow a more efficient implementation and clearer semantics in
>>>> case rotation is not needed as well as correctness in case rotation is
>>>> undesired.
>>>> - <algorithm>'s std::move/std::move_backward (depending on the shift
>>>> direction).
>>>>
>>>> std::shift should probably accommodate both left and right shifts by
>>>> one of:
>>>> - giving it either begin() and end(), or rbegin() and rend(), similar
>>>> to how std::rotate works for both left and right rotations. The advantage
>>>> is compactness of the implementation.
>>>> - allowing the shift count parameter to be either positive or negative.
>>>> The advantage is compactness, though it might not be clear which direction
>>>> is which - to be consistent with rotate, positive integers should shift to
>>>> the left.
>>>> - having std::shift_right and std::shift_left functions. The advantage
>>>> is clarity when calling the methods, although the same argument could be
>>>> made for having separate std::rotate_left and std::rotate_right instead of
>>>> std::rotate, which we don't have.
>>>>
>>>> Here's a sample implementation of a shift to the right direction:
>>>>
>>>> template<class BidirIt>
>>>> void shift_right(BidirIt first, BidirIt last, unsigned int n = 1)
>>>> {
>>>>     std::move_backward(first, last - n, last);
>>>> }
>>>>
>>>> This demonstrates that while std::shift is implementable with
>>>> std::move/std::move_backward,
>>>> 1) It isn't immediately clear from the code (at least to my eyes) that
>>>> this is a shift right, unless you are intimately familiar with
>>>> std::move_backward.
>>>> 2) Different calls, either to std::move or to std::move_backward, are
>>>> required, depending on the shift direction.
>>>>
>>>> So, implementing std::shift would allow writing more readable code.
>>>>
>>>> Thanks,
>>>> Dan
>>>>
>>>

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<div dir=3D"ltr">Hi,<div><br></div><div>Attached updated proposal draft.</d=
iv><div><br></div><div>- Added proposed standard wording.</div><div>- Decid=
ed to allow shift by zero despite a possible minimal performance penalty.</=
div><div>- Improved formatting and content nits.</div><div><br></div><div>W=
ould appreciate any comments as well as possible naming alternatives (see O=
pen Issues section in the proposal).</div><div><br></div><div>Thanks,</div>=
<div>Dan</div><div><br>On Friday, August 25, 2017 at 1:00:28 AM UTC+3, Dan =
Raviv wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0;margin-lef=
t: 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;"><div dir=3D"ltr">H=
i!<div><br></div><div>Attached an updated proposal draft, now with shift_ri=
ght for forward, non-bidirectional iterators, courtesy of Casey Carter! You=
 can check out the implementation at=C2=A0<a href=3D"https://github.com/dan=
ra/shift_proposal" target=3D"_blank" rel=3D"nofollow" onmousedown=3D"this.h=
ref=3D&#39;https://www.google.com/url?q\x3dhttps%3A%2F%2Fgithub.com%2Fdanra=
%2Fshift_proposal\x26sa\x3dD\x26sntz\x3d1\x26usg\x3dAFQjCNHiQn6IrMCHhvjPvIg=
88uN8njRO6g&#39;;return true;" onclick=3D"this.href=3D&#39;https://www.goog=
le.com/url?q\x3dhttps%3A%2F%2Fgithub.com%2Fdanra%2Fshift_proposal\x26sa\x3d=
D\x26sntz\x3d1\x26usg\x3dAFQjCNHiQn6IrMCHhvjPvIg88uN8njRO6g&#39;;return tru=
e;">https://github.com/danra/<wbr>shift_proposal</a> .</div><div><br></div>=
<div>Also removed the filler functionality, following feedback which has pr=
oven it to be redundant.</div><div><br></div><div>Would appreciate any furt=
her comments, as well as opinions on the listed open issues.</div><div><br>=
</div><div>Thanks,</div><div>Dan</div><div><br></div><div><br><br>On Saturd=
ay, August 19, 2017 at 2:24:07 AM UTC+3, Dan Raviv wrote:<blockquote class=
=3D"gmail_quote" style=3D"margin:0;margin-left:0.8ex;border-left:1px #ccc s=
olid;padding-left:1ex"><div dir=3D"ltr">Hi,<div><br></div><div>Attached an =
updated proposal draft.</div><div><br></div><div>Would appreciate any comme=
nts, as well as opinions on any of the listed open issues.</div><div><br></=
div><div>Thanks!</div><div>Dan</div><div><br>On Saturday, July 29, 2017 at =
8:19:01 PM UTC+3, Dan Raviv wrote:<blockquote class=3D"gmail_quote" style=
=3D"margin:0;margin-left:0.8ex;border-left:1px #ccc solid;padding-left:1ex"=
><div dir=3D"ltr">Hi,<div><br></div><div>Attached a proposal draft with rea=
soning and sample implementation (but still no complete design and standard=
 wording).<div>Would appreciate any feedback!</div><div><br></div><div>Than=
ks,</div><div>Dan<br><br>On Wednesday, July 12, 2017 at 12:53:19 PM UTC+3, =
<a>d...@soundradix.com</a> wrote:<blockquote class=3D"gmail_quote" style=3D=
"margin:0;margin-left:0.8ex;border-left:1px #ccc solid;padding-left:1ex"><d=
iv dir=3D"ltr">Hi,<div><br></div><div>Would anyone be interested in adding =
std::shift to &lt;algorithm&gt;?=C2=A0</div><div><br></div><div>It would be=
 similar to both:</div><div>- std::rotate, but without moving the head elem=
ents back to the tail. This would allow a more efficient implementation and=
 clearer semantics in case rotation is not needed as well as correctness in=
 case rotation is undesired.</div><div>- &lt;algorithm&gt;&#39;s std::move/=
std::move_backward (depending on the shift direction).</div><div><br></div>=
<div>std::shift should probably accommodate both left and right shifts by o=
ne of:</div><div>- giving it either begin() and end(), or rbegin() and rend=
(), similar to how std::rotate works for both left and right rotations. The=
 advantage is compactness of the implementation.</div><div>- allowing the s=
hift count parameter to be either positive or negative. The advantage is co=
mpactness, though it might not be clear which direction is which - to be co=
nsistent with rotate, positive integers should shift to the left.<br></div>=
<div><div>- having std::shift_right and std::shift_left functions. The adva=
ntage is clarity when calling the methods, although the same argument could=
 be made for having separate std::rotate_left and std::rotate_right instead=
 of std::rotate, which we don&#39;t have.</div></div><div><br></div><div>He=
re&#39;s a sample implementation of a shift to the right direction:</div><b=
r><div style=3D"background-color:rgb(250,250,250);border:1px solid rgb(187,=
187,187);word-wrap:break-word"><code><div><span style=3D"color:#008">templa=
te</span><span style=3D"color:#660">&lt;</span><span style=3D"color:#008">c=
lass</span><span style=3D"color:#000"> </span><span style=3D"color:#606">Bi=
dirIt</span><span style=3D"color:#660">&gt;</span><span style=3D"color:#000=
"> <br></span><span style=3D"color:#008">void</span><span style=3D"color:#0=
00"> shift_right</span><span style=3D"color:#660">(</span><span style=3D"co=
lor:#606">BidirIt</span><span style=3D"color:#000"> first</span><span style=
=3D"color:#660">,</span><span style=3D"color:#000"> </span><span style=3D"c=
olor:#606">BidirIt</span><span style=3D"color:#000"> </span><span style=3D"=
color:#008">last</span><span style=3D"color:#660">,</span><span style=3D"co=
lor:#000"> </span><span style=3D"color:#008">unsigned</span><span style=3D"=
color:#000"> </span><span style=3D"color:#008">int</span><span style=3D"col=
or:#000"> n </span><span style=3D"color:#660">=3D</span><span style=3D"colo=
r:#000"> </span><span style=3D"color:#066">1</span><span style=3D"color:#66=
0">)</span><span style=3D"color:#000"> <br></span><span style=3D"color:#660=
">{</span><span style=3D"color:#000"> <br>=C2=A0 =C2=A0 std</span><span sty=
le=3D"color:#660">::</span><span style=3D"color:#000">move_backward</span><=
span style=3D"color:#660">(</span><span style=3D"color:#000">first</span><s=
pan style=3D"color:#660">,</span><span style=3D"color:#000"> </span><span s=
tyle=3D"color:#008">last</span><span style=3D"color:#000"> </span><span sty=
le=3D"color:#660">-</span><span style=3D"color:#000"> n</span><span style=
=3D"color:#660">,</span><span style=3D"color:#000"> </span><span style=3D"c=
olor:#008">last</span><span style=3D"color:#660">);</span><span style=3D"co=
lor:#000"> <br></span><span style=3D"color:#660">}</span><span style=3D"col=
or:#000"><br></span></div></code></div><div><br></div><div>This demonstrate=
s that while std::shift is implementable with std::move/std::move_backward,=
</div><div>1) It isn&#39;t immediately clear from the code (at least to my =
eyes) that this is a shift right, unless you are intimately familiar with s=
td::move_backward.</div><div>2) Different calls, either to std::move or to =
std::move_backward, are required, depending on the shift direction.</div><d=
iv><br></div><div>So, implementing std::shift would allow writing more read=
able code.</div><div><br></div><div>Thanks,</div><div>Dan</div></div></bloc=
kquote></div></div></div></blockquote></div></div></blockquote></div></div>=
</blockquote></div></div>

<p></p>

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------=_Part_3510_1645026934.1506800313345--

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------=_Part_3509_1344779633.1506800313344--

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On 30 September 2017 at 22:38, Dan Raviv <dan.raviv@gmail.com> wrote:
> Hi,
>
> Attached updated proposal draft.
>
> - Added proposed standard wording.
> - Decided to allow shift by zero despite a possible minimal performance
> penalty.
> - Improved formatting and content nits.
>
> Would appreciate any comments as well as possible naming alternatives (see
> Open Issues section in the proposal).


Looks ready for LEWG consumption, based on my reading of it.

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