Topic: Return this or *this in overridden method in child class?
Author: Vu Pham <phvu225@gmail.com>
Date: Fri, 30 Nov 2018 13:38:07 +0000
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While thinking about my (ahem) streaming proposal
<https://groups.google.com/a/isocpp.org/forum/?utm_medium=email&utm_source=footer#!msg/std-proposals/w0j1pF8gQPQ/YzHdodLoBwAJ>,
I think I found a missing feature in C++. Since this group is highly
populated with people speaking C++ fluently, I will ask this here instead.
Assume I have the following classes:
class A {
public:
A& f1(float& x) {
x++;
return *this;
}
};
class B: public A {
public:
B& f2(float& x) {
x--;
return *this;
}
};
int main()
{
float x(100.0f);
B b;
*static_cast<B>(b.f1(x)).f2(x);* // this doesn't compile
return 0;
}
The idea is I want B::f1() to return an instance of B (it should, given the
implementation of f1), but since the return type of f1() is A&, apparently
there is no way to make it work the way I want. Here are a few alternatives
I tried:
- Make f1() returns A*, then cast the returned pointer. This doesn't look
really nice.
- Change the return type of f1() to something like decltype(*this) or auto,
none of this seems to work.
This issue may get worse if A and B are templated, or in a more complicated
scenario where A::f1() returns a child class C of A, while B is a child of
A but not C, and I want to override B::f1() to return D, which is a child
class of B.
Since C++ allows multiple inheritence, and in the same light with the
*concept* idea that are coming up in new C++, should we coin a new
annotation to indicate that a function returns an instance of *this* class?
The actual returned type will change depending on the actual type of the
class that mix those functions in.
What do you think?
Vu
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<div dir=3D"ltr"><div dir=3D"ltr"><div>While thinking about my (ahem) <a hr=
ef=3D"https://groups.google.com/a/isocpp.org/forum/?utm_medium=3Demail&=
utm_source=3Dfooter#!msg/std-proposals/w0j1pF8gQPQ/YzHdodLoBwAJ">streaming =
proposal</a>, I think I found a missing feature in C++. Since this group is=
highly populated with people speaking C++ fluently, I will ask this here i=
nstead.</div><div><br></div><div>Assume I have the following classes:</div>=
<div><br></div><div><span style=3D"font-family:monospace,monospace">class A=
{<br>public:<br>=C2=A0=C2=A0=C2=A0 A& f1(float& x) {<br>=C2=A0=C2=
=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 x++;<br>=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=
=A0=C2=A0 return *this;<br>=C2=A0=C2=A0=C2=A0 }<br>};<br><br>class B: publi=
c A {<br>public:<br>=C2=A0=C2=A0=C2=A0 B& f2(float& x) {<br>=C2=A0=
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 x--;<br>=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=
=C2=A0=C2=A0 return *this;<br>=C2=A0=C2=A0=C2=A0 }<br>};<br><br>int main()<=
br>{<br>=C2=A0=C2=A0=C2=A0 float x(100.0f);<br>=C2=A0=C2=A0=C2=A0 B b;<br>=
=C2=A0=C2=A0=C2=A0 <b>static_cast<B>(b.f1(x)).f2(x);</b>=C2=A0=C2=A0 =
// this doesn't compile<br>=C2=A0=C2=A0=C2=A0 return 0;<br>}</span><br>=
</div><div><br></div><div>The idea is I want B::f1() to return an instance =
of B (it should, given the implementation of f1), but since the return type=
of f1() is A&, apparently there is no way to make it work the way I wa=
nt. Here are a few alternatives I tried:</div><div><br></div><div>- Make f1=
() returns A*, then cast the returned pointer. This doesn't look really=
nice.</div><div>- Change the return type of f1() to something like decltyp=
e(*this) or auto, none of this seems to work.</div><div><br></div><div>This=
issue may get worse if A and B are templated, or in a more complicated sce=
nario where A::f1() returns a child class C of A, while B is a child of A b=
ut not C, and I want to override B::f1() to return D, which is a child clas=
s of B.</div><div><br></div><div>Since C++ allows multiple inheritence, and=
in the same light with the <i>concept</i> idea that are coming up in new C=
++, should we coin a new annotation to indicate that a function returns an =
instance of <i>this</i> class? The actual returned type will change dependi=
ng on the actual type of the class that mix those functions in.</div><div><=
br></div><div>What do you think?</div><div>Vu<br></div></div></div>
<p></p>
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